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If you dribble a basketball with a frequency of \(1.77 \mathrm{Hz},\) how long does it take for you to complete 12 dribbles?

Short Answer

Expert verified
It takes approximately 6.78 seconds to complete 12 dribbles.

Step by step solution

01

Understand the Problem

The problem asks how long it takes to complete 12 dribbles if each dribble occurs with a frequency of 1.77 Hz. Frequency in this context means the number of dribbles per second.
02

Define Frequency

Frequency (f) is defined as the number of cycles (or dribbles) per unit of time. It is given as 1.77 Hz, which means 1.77 dribbles per second.
03

Calculate Time for One Dribble

Since frequency is the reciprocal of the period (time for one cycle), we find the time for one dribble by taking the reciprocal of the frequency: \[ T = \frac{1}{f} = \frac{1}{1.77} \text{ seconds} \]
04

Compute the Total Time for 12 Dribbles

Multiply the time for one dribble by the total number of dribbles to find the total time:\[ \text{Total Time} = 12 \times T = 12 \times \frac{1}{1.77} \text{ seconds} \]
05

Final Calculation

Calculate the exact value: \[ \text{Total Time} = 12 \times \frac{1}{1.77} \approx 6.78 \text{ seconds} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Period of a Cycle
When talking about cycles, such as dribbling a basketball, the "period" is the time it takes to complete one full cycle. In simpler terms, it's how long one dribble takes from start to finish. This concept is important in understanding how often something happens over a period.

To find the period, you need to know the frequency, which is how many cycles occur in one second. The key here is that the period and frequency are inversely related. A higher frequency means a shorter period, and vice versa.

When we say frequency is 1.77 Hz, it means 1.77 dribbles occur each second. Therefore, the period of one dribble is the inverse of the frequency. By using the formula:
  • Period (\[T\]) = \(\[\frac{1}{\text{frequency}}\] \)
You can calculate how many seconds one dribble takes, giving you a clear picture of the timing for each cycle.
Reciprocal Relationship
Understanding the reciprocal relationship between period and frequency is crucial when dealing with cycles. When two quantities are reciprocals, multiplying them gives you 1. In our context, the period (\(T\)) and the frequency (\(f\)) have this kind of inverse connection.

Here's how it works:
  • If the frequency of dribbling is 1.77 Hz, it means 1.77 dribbles happen every second.
  • To find the period—how much time one dribble takes—you take the reciprocal of the frequency.
  • This is calculated as \(T = \frac{1}{f}\).
This simple mathematical operation helps you transition from knowing how often events happen (frequency) to understanding the exact timing of a single event (period). So, whenever you are given the frequency, you can easily find the period by using this reciprocal relationship.
Time Calculation for Cycles
Once you understand the period of an individual cycle, you can calculate the total time for multiple cycles. This is especially useful in scenarios like determining how long a series of basketball dribbles will take.

To compute this, simply multiply the period of one cycle by the total number of cycles you wish to complete.
  • First, calculate the period using the reciprocal of frequency: \(T = \frac{1}{f}\).
  • Then, determine the total time by multiplying \(T\) by the number of cycles. In our example, it becomes: \( \text{Total Time} = \text{Number of Cycles} \times T \).
This step-by-step process allows anyone to determine how long a series of repeated actions will take, making it easier to manage time effectively in various repetitive tasks, whether in sports, engineering, or daily activities.

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Most popular questions from this chapter

IP A 9.50-g bullet, moving horizontally with an initial speed "b. embeds itself in a 1.45 -kg pendulum bob that is initially at rest. The length of the pendulum is \(L=0.745 \mathrm{m}\). After the collision, the pendulum swings to one side and comes to rest when it has gained a vertical height of \(12.4 \mathrm{cm} .\) (a) Is the kinetic energy of the bullet-bob system immediately after the collision greater than, less than, or the same as the kinetic energy of the system just before the collision? Explain. (b) Find the initial speed of the bullet. (c) How long does it take for the bullet-bob system to come to rest for the first time?

IP Consider a meterstick that oscillates back and forth about a pivot point at one of its ends, (a) Is the period of a simple pendulum of length \(L=1.00 \mathrm{m}\) greater than, less than, or the same as the period of the meterstick? Explain. (b) Find the length \(L\) of a simple pendulum that has a period equal to the period of the meterstick.

A 0.45-kg crow lands on a slender branch and bobs up and down with a period of 1.5 s. An eagle flies up to the same branch, scaring the crow away, and lands. The eagle now bobs up and down with a period of 4.8 s. Treating the branch as an ideal spring, find (a) the effective force constant of the branch and (b) the mass of the eagle.

A vibrating structural beam in a spacecraft can cause problems if the frequency of vibration is fairly high. Even if the amplitude of vibration is only a fraction of a millimeter, the acceleration of the beam can be several times greater than the acceleration due to gravity. As an example, find the maximum acceleration of a beam that vibrates with an amplitude of \(0.25 \mathrm{mm}\) at the rate of 110 vibrations per second. Give your answer as a multiple of \(g\).

A pendulum of length \(L\) has a period \(T\). How long must the pendulum be if its period is to be \(2 T ?\)

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