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A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is \(4.1 \mathrm{kg} \cdot \mathrm{m}^{2} .\) A second student tosses a \(1.5-\mathrm{kg}\) mass with a speed of \(2.7 \mathrm{m} / \mathrm{s}\) to the student on the stool, who catches it at a distance of \(0.40 \mathrm{m}\) from the axis of rotation. What is the resulting angular speed of the student and the stool?

Short Answer

Expert verified
The resulting angular speed is \(0.395 \text{ rad/s}\).

Step by step solution

01

Identify Initial Conditions

The initial angular momentum of the system is zero since the student and stool are at rest, and the moment of inertia is given as \(I = 4.1 \text{ kg} \cdot \text{m}^2\). The mass of the object thrown is \(m = 1.5 \text{ kg}\) and its speed is \(v = 2.7 \text{ m/s}\).
02

Calculate Linear Momentum of the Mass

The linear momentum \(p\) of the tossed mass is found using \( p = m \cdot v \). This gives \( p = 1.5 \text{ kg} \times 2.7 \text{ m/s} = 4.05 \text{ kg} \cdot \text{m/s} \).
03

Convert Linear Momentum to Angular Momentum

The angular momentum \(L\) of the mass with respect to the axis of rotation is given by \( L = r \cdot p \), where \(r = 0.40 \text{ m}\) is the distance from the axis. Thus, \( L = 0.40 \text{ m} \times 4.05 \text{ kg} \cdot \text{m/s} = 1.62 \text{ kg} \cdot \text{m}^2/s \).
04

Apply Conservation of Angular Momentum

Since the system has no external torques, angular momentum is conserved. Initially, the system has zero angular momentum, and this must equal the final angular momentum of the combined system, which is \(I' \cdot \omega\). Therefore, set \( I' \cdot \omega = L \), where \(I' = 4.1 \text{ kg} \cdot \text{m}^2 \) is the moment of inertia of the student-stool system.
05

Solve for Angular Speed

Rearrange the equation \( I' \cdot \omega = L \) to find \( \omega = \frac{L}{I'} \). Substituting the known values, \( \omega = \frac{1.62 \text{ kg} \cdot \text{m}^2/s}{4.1 \text{ kg} \cdot \text{m}^2} = 0.395 \text{ rad/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
In rotational motion, moment of inertia plays a similar role to mass in linear motion. It is a measure of an object's resistance to changes in its rotation. The larger the moment of inertia, the harder it is to change the rotational speed of the object. In our exercise, the moment of inertia of the student-stool system is given as \(4.1 \text{ kg} \cdot \text{m}^2\). This tells us that this system has a certain amount of rotational inertia, making it resistant to changes in its angular velocity.
The moment of inertia depends on how the mass of the object is distributed relative to the axis of rotation. A greater distance from the axis means a higher moment of inertia for the same amount of mass.
This concept is crucial in understanding rotational dynamics, as it influences how systems respond to forces and torques.
Conservation of Angular Momentum
The principle of conservation of angular momentum states that if no external torque acts on a system, the angular momentum remains constant. In simpler terms, the total angular momentum before an event must equal the total angular momentum after the event.
In our exercise, initially, the student-stool system has zero angular momentum because it is at rest. Once the mass is introduced into the system, there is a transfer of momentum, yet the total must still equal zero, since no external forces are acting. The angular momentum from catching the mass is what propels the system into motion, but the overall angular momentum does not change.
  • This principle helps explain how objects behave when spinning and why they continue spinning unless an external force stops them.
  • It also shows the intrinsic link between linear and angular properties.
Linear Momentum to Angular Momentum Conversion
Converting linear momentum to angular momentum is essential in understanding rotational dynamics. Linear momentum \(p\) is calculated as the product of mass \(m\) and velocity \(v\), \( p = m \cdot v \). This represents the momentum an object possesses due to its motion in a straight line.
For an object moving in such a straight line but impacting a rotating system, like in our exercise, its linear momentum contributes to angular momentum \(L\) when it acts at some distance \(r\) from the axis of rotation. The conversion is described by the formula \( L = r \cdot p \), where \(r\) is the perpendicular distance to the rotation axis. This shows that momentum not only depends on the linear properties but also on how far off-axis the motion is occurring, thus affecting rotational outcomes.
Understanding this conversion is crucial in predicting how the interaction of linear-moving elements with rotational systems leads to changes in angular velocity and system dynamics.
  • This conversion is key in understanding actions like catching a ball on a rotating stool, as it changes the system's motion based on the input linear momentum.
  • It highlights the relationship between translational and rotational motion, one of the foundations of physics.

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Most popular questions from this chapter

Suppose partial melting of the polar ice caps increases the moment of inertia of the Earth from \(0.331 M_{\mathrm{E}} R_{\mathrm{E}}{ }^{2}\) to \(0.332 M_{\mathrm{E}} R_{\mathrm{E}}^{2}\) (a) Would the length of a day (the time required for the Earth to complete one revolution about its axis) increase or decrease? Explain. (b) Calculate the change in the length of a day. Give your answer in seconds.

A student on a piano stool rotates freely with an angular speed of 2.95 rev /s. The student holds a 1.25 -kg mass in each outstretched arm, 0.759 \(\mathrm{m}\) from the axis of rotation. The combined moment of inertia of the student and the stool, ignoring the two masses, is \(5.43 \mathrm{kg} \cdot \mathrm{m}^{2}\), a value that remains constant. (a) As the student pulls his arms inward, his angular speed increases to 3.54 rev \(/ \mathrm{s} .\) How far are the masses from the axis of rotation at this time, considering the masses to be points? (b) Calculate the initial and final kinetic energies of the system.

Two gerbils run in place with a linear speed of \(0.55 \mathrm{m} / \mathrm{s}\) on an exercise wheel that is shaped like a hoop. Find the angular momentum of the system if each gerbil has a mass of \(0.22 \mathrm{kg}\) and the exercise wheel has a radius of \(9.5 \mathrm{cm}\) and a mass of \(5.0 \mathrm{g}\).

A wheel on a game show is given an initial angular speed of \(1.22 \mathrm{rad} / \mathrm{s}\). It comes to rest after rotating through 0.75 of a turn. (a) Find the average torque exerted on the wheel given that it is a disk of radius \(0.71 \mathrm{m}\) and \(\mathrm{mass} 6.4 \mathrm{kg}\). (b) If the mass of the wheel is doubled and its radius is halved, will the angle through which it rotates before coming to rest increase, decrease, or stay the same? Explain. (Assume that the average torque exerted on the wheel is unchanged.)

A torque of \(0.97 \mathrm{N} \cdot \mathrm{m}\) is applied to a bicycle wheel of radius \(35 \mathrm{cm}\) and mass \(0.75 \mathrm{kg}\). Treating the wheel as a hoop, find its angular acceleration.

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