91Ó°ÊÓ

Weight is the force acting on an object due to gravity, and it's calculated as the mass of the object multiplied by the acceleration due to gravity (g = \(9.8 m/s^2\)). So, let's find the weight of the baby and adult. Weight of the baby = mass of baby × g Weight of the baby = 10 kg × 9.8 \(m/s^2\) = 98 N Weight of the adult = mass of adult × g Weight of the adult = 60 kg × 9.8 \(m/s^2\) = 588 N

The contact area for a single leg of both the stool and the chair will be the area of a circle with the diameter given in the problem. Let's first find the radius from the given diameter and then calculate the area for each. Radius of stool leg = diameter of stool leg / 2 Radius of stool leg = 1.0 cm = 0.01 m Radius of chair leg = diameter of chair leg / 2 Radius of chair leg = 3.0 cm = 0.03 m Now, we can calculate the area of a single stool and chair leg. Area of a single stool leg = \(\pi * (radius\ of\ stool\ leg)^2\) Area of a single stool leg = \(\pi * (0.01 m)^2\) = \(3.14 * 10^{-4} m^2\) Area of a single chair leg = \(\pi * (radius\ of\ chair\ leg)^2\) Area of a single chair leg = \(\pi * (0.03 m)^2\) = \(2.826 * 10^{-3} m^2\) Now, let's multiply these areas by the number of legs for each. Total contact area for stool = 3 * Area of a single stool leg Total contact area for stool = 3 * (\(3.14 * 10^{-4} m^2\)) = \(9.42 * 10^{-4} m^2\) Total contact area for chair = 4 * Area of a single chair leg Total contact area for chair = 4 * (\(2.826 * 10^{-3} m^2\)) = \(1.1304 * 10^{-2} m^2\)

Now we have all the information necessary to calculate the pressure exerted by both the baby and the adult. Pressure exerted by the baby = Weight of the baby / Total contact area for stool Pressure exerted by the baby = 98 N / (\(9.42 * 10^{-4} m^2\)) = \(104044.59 N/m^2\) Pressure exerted by the adult = Weight of the adult / Total contact area for chair Pressure exerted by the adult = 588 N / (\(1.1304 * 10^{-2} m^2\)) = \(52000 N/m^2\)

Comparing the pressures calculated in Step 3, we find that: Pressure exerted by the baby > Pressure exerted by the adult \(104044.59 N/m^2\) > \(52000 N/m^2\) The baby exerts more pressure on the floor than the adult, and the difference in pressure is: Difference in pressure = Pressure exerted by the baby - Pressure exerted by the adult Difference in pressure = \(104044.59 N/m^2 - 52000 N/m^2 = 52044.59 N/m^2\) So, the baby applies greater pressure to the floor by \(52044.59 N/m^2\).