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A 46.4 -N force is applied to the outer edge of a door of width $1.26 \mathrm{m}$ in such a way that it acts (a) perpendicular to the door, (b) at an angle of \(43.0^{\circ}\) with respect to the door surface, (c) so that the line of action of the force passes through the axis of the door hinges. Find the torque for these three cases.

Short Answer

Expert verified
Question: Calculate the torque for each of the three cases when a force of 46.4 N is applied on a door with a width of 1.26 m. Answer: 1. The torque when the force is perpendicular to the door is 58.464 Nm. 2. The torque when the force is at a 43° angle with respect to the door surface is 46.90 Nm. 3. The torque when the force passes through the axis of the door hinges is 0 Nm.

Step by step solution

01

Case (a): Perpendicular to the door

For this case, the force is acting perpendicular to the door. Therefore, the angle between the door surface and the force (θ) is 90º. Force, F = 46.4 N Distance (from hinge to outer edge), d = 1.26 m Angle, θ = 90° Now, let's calculate the torque using the formula: Torque = F × d × sinθ Torque = 46.4 × 1.26 × sin(90°) Torque = 58.464 Nm
02

Case (b): Force at a 43° angle with respect to the door surface

In this case, the force is acting at a 43° angle with respect to the door surface. Therefore, the angle between the door surface and the force (θ) is 43º. Force, F = 46.4 N Distance (from hinge to outer edge), d = 1.26 m Angle, θ = 43° Now, let's calculate the torque using the formula: Torque = F × d × sinθ Torque = 46.4 × 1.26 × sin(43°) Torque ≈ 46.90 Nm
03

Case (c): Force passes through the axis of the door hinges

When the line of action of the force passes through the axis of rotation of the hinges, the angle between the force and the line joining the point at which force acts and the rotation axis (hinge) is 0º. Force, F = 46.4 N Distance (from hinge to outer edge), d = 1.26 m Angle, θ = 0° Now, let's calculate the torque using the formula: Torque = F × d × sinθ Torque = 46.4 × 1.26 × sin(0°) Torque = 0 Nm In this case, the torque is 0 Nm because the force is passing through the axis of rotation, causing no rotation of the door. To summarize: 1. The torque when the force is perpendicular to the door is 58.464 Nm. 2. The torque when the force is at a 43° angle with respect to the door surface is 46.90 Nm. 3. The torque when the force passes through the axis of the door hinges is 0 Nm.

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