/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 The bungee jumper of Example 6.4... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The bungee jumper of Example 6.4 made a jump into the Gorge du Verdon in southern France from a platform \(182 \mathrm{m}\) above the bottom of the gorge. The jumper weighed \(780 \mathrm{N}\) and came within \(68 \mathrm{m}\) of the bottom of the gorge. The cord's unstretched length is \(30.0 \mathrm{m}\) (a) Assuming that the bungee cord follows Hooke's law when it stretches, find its spring constant. [Hint: The cord does not begin to stretch until the jumper has fallen \(30.0 \mathrm{m} .]\) (b) At what speed is the jumper falling when he reaches a height of \(92 \mathrm{m}\) above the bottom of the gorge?

Short Answer

Expert verified
Answer: The speed of the bungee jumper when he is 92 meters above the bottom of the gorge is approximately 26.62 m/s.

Step by step solution

01

Analyze the problem

First, we'll find the spring constant by analyzing the potential and elastic energies involved. After that, we'll use the conservation of energy principle to find the jumper's velocity at a specific height.
02

Find the maximum stretch of the cord

The cord's unstretched length is 30 m. The bungee jumper comes within 68 m of the bottom of the gorge. The total length of the bungee cord when stretched will be the initial height minus the distance he comes within the bottom: Maximum stretch = (182 - 68) - 30 = 84 m
03

Apply Hooke's Law

Hooke's Law for an elastic cord states that the force acting on the object is proportional to the displacement or stretch (x). F = kx, where k is the spring constant. During the maximum stretch, the only forces acting on the jumper are his weight and the elastic force, which are equal and opposite: Weight of the jumper = 780 N Elastic force = k * (84 m - 30 m) 780 N = k * 54 m
04

Calculate spring constant k

Now, we'll calculate the spring constant: k = 780 N / 54 m k ≈ 14.44 N/m The spring constant of the bungee cord is approximately 14.44 N/m.
05

Calculate jumper's height from the bottom of the gorge

Now, we'll find the height in terms of the cord's length when the jumper is 92 m above the bottom of the gorge: Height from the bottom = 182 m - 92 m = 90 m
06

Use conservation of energy

We will use the conservation of energy principle. Mechanical energy is conserved since only conservative forces (gravitational force and elastic force) are acting on the jumper: Initial potential energy = Final potential energy + Final elastic potential energy + Final kinetic energy mgh_initial = mgh_final + 0.5 * k * x^2 + 0.5 * m * v^2 where m is the mass of the jumper, g is the acceleration due to gravity (9.8 m/s^2), h_initial and h_final are the initial and final heights, and v is the velocity we want to find.
07

Calculate the jumper's mass

First, we need to find the mass of the jumper. Using the weight of the jumper (780 N), we can calculate the mass: m = weight / g m = 780 N / 9.8 m/s^2 m ≈ 79.59 kg
08

Apply the conservation of energy equation

Now, we'll plug the values into the conservation of energy equation: (79.59 kg)(9.8 m/s^2)(182 m) = (79.59 kg)(9.8 m/s^2)(92 m) + 0.5 * (14.44 N/m) * (90 m - 30 m)^2 + 0.5 * (79.59 kg) * v^2 After simplification, we get: 0.5 * (79.59 kg) * v^2 ≈ 28191 J
09

Calculate the jumper's velocity

Finally, we'll solve for the velocity of the jumper: v^2 = (28191 J) / (0.5 * 79.59 kg) v ≈ sqrt(708.52) v ≈ 26.62 m/s The jumper is falling at a speed of approximately 26.62 m/s when he reaches a height of 92 m above the bottom of the gorge.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Rachel is on the roof of a building, \(h\) meters above ground. She throws a heavy ball into the air with a speed \(v,\) at an angle \(\theta\) with respect to the horizontal. Ignore air resistance. (a) Find the speed of the ball when it hits the ground in terms of \(h, v, \theta,\) and \(g .\) (b) For what value(s) of \(\theta\) is the speed of the ball greatest when it hits the ground?
Two springs with spring constants \(k_{1}\) and \(k_{2}\) are connected in series. (a) What is the effective spring constant of the combination? (b) If a hanging object attached to the combination is displaced by \(4.0 \mathrm{cm}\) from the relaxed position, what is the potential energy stored in the spring for \(k_{1}=5.0 \mathrm{N} / \mathrm{cm}\) and $k_{2}=3.0 \mathrm{N} / \mathrm{cm} ?$ [See Problem \(83(\mathrm{a}) .]\)
A wind turbine converts some of the kinetic energy of the wind into electric energy. Suppose that the blades of a small wind turbine have length $L=4.0 \mathrm{m}$ (a) When a \(10 \mathrm{m} / \mathrm{s}(22 \mathrm{mi} / \mathrm{h})\) wind blows head-on, what volume of air (in \(\mathrm{m}^{3}\) ) passes through the circular area swept out by the blades in \(1.0 \mathrm{s} ?\) (b) What is the mass of this much air? Each cubic meter of air has a mass of 1.2 \(\mathrm{kg}\). (c) What is the translational kinetic energy of this mass of air? (d) If the turbine can convert \(40 \%\) of this kinetic energy into electric energy, what is its electric power output? (e) What happens to the power output if the wind speed decreases to \(\frac{1}{2}\) of its initial value? What can you conclude about electric power production by wind turbines?
Two springs with spring constants \(k_{1}\) and \(k_{2}\) are connected in parallel. (a) What is the effective spring constant of the combination? (b) If a hanging object attached to the combination is displaced by \(2.0 \mathrm{cm}\) from the relaxed position, what is the potential energy stored in the spring for \(k_{1}=5.0 \mathrm{N} / \mathrm{cm}\) and $k_{2}=3.0 \mathrm{N} / \mathrm{cm} ?$ [See Problem \(83(\mathrm{b}) .]\)
(a) If the length of the Achilles tendon increases \(0.50 \mathrm{cm}\) when the force exerted on it by the muscle increases from \(3200 \mathrm{N}\) to $4800 \mathrm{N},$ what is the "spring constant" of the tendon? (b) How much work is done by the muscle in stretching the tendon \(0.50 \mathrm{cm}\) as the force increases from \(3200 \mathrm{N}\) to \(4800 \mathrm{N} ?\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.