/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 During normal operation, a com... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

During normal operation, a computer's hard disk spins at 7200 rpm. If it takes the hard disk 4.0 s to reach this angular velocity starting from rest, what is the average angular acceleration of the hard disk in $\mathrm{rad} / \mathrm{s}^{2} ?$

Short Answer

Expert verified
Answer: The average angular acceleration of the hard disk is 75.4 rad/s².

Step by step solution

01

Convert angular velocity to radians per second

To convert the angular velocity from rpm (revolutions per minute) to radians per second, we can use the following conversion factors: 1 revolution = 2Ï€ radians, and 1 minute = 60 seconds So, angular velocity in radians per second is: $$ \omega = 7200 \frac{\text{rev}}{\text{min}} \times \frac{2\pi \text{ radians}}{1 \text{rev}} \times \frac{1 \text{min}}{60 \text{s}} $$
02

Calculate the average angular acceleration

Now that we have the angular velocity in radians per second, we can use the formula for average angular acceleration: $$ \text{average angular acceleration} = \frac{\text{final angular velocity} - \text{initial angular velocity}}{\text{time}} $$ Since the hard disk starts from rest, its initial angular velocity is 0. Thus, the formula becomes: $$ \text{average angular acceleration} = \frac{\omega}{t} $$ Plug in the values and calculate the average angular acceleration: $$ \text{average angular acceleration} = \frac{7200 \times \frac{2\pi}{60}}{4.0} $$ Now, simplify and find the average angular acceleration: $$ \text{average angular acceleration} = \frac{7200 \times \frac{2\pi}{60}}{4.0} = 75.4 \mathrm{rad} / \mathrm{s}^{2} $$ So, the average angular acceleration of the hard disk is 75.4 \(\mathrm{rad} / \mathrm{s}^{2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the professional videotape recording system known as quadriplex, four tape heads are mounted on the circumference of a drum of radius \(2.5 \mathrm{cm}\) that spins at \(1500 \mathrm{rad} / \mathrm{s} .\) (a) At what speed are the tape heads moving? (b) Why are moving tape heads used instead of stationary ones, as in audiotape recorders? [Hint: How fast would the tape have to move if the heads were stationary?]
A car drives around a curve with radius \(410 \mathrm{m}\) at a speed of $32 \mathrm{m} / \mathrm{s} .$ The road is not banked. The mass of the car is \(1400 \mathrm{kg} .\) (a) What is the frictional force on the car? (b) Does the frictional force necessarily have magnitude $\mu_{\mathrm{s}} N ?$ Explain.

Massimo, a machinist, is cutting threads for a bolt on a lathe. He wants the bolt to have 18 threads per inch. If the cutting tool moves parallel to the axis of the would be bolt at a linear velocity of 0.080 in./s, what must the rotational speed of the lathe chuck be to ensure the correct thread density? [Hint: One thread is formed for each complete revolution of the chuck.]

A car drives around a curve with radius \(410 \mathrm{m}\) at a speed of $32 \mathrm{m} / \mathrm{s} .\( The road is banked at \)5.0^{\circ} .$ The mass of the car is \(1400 \mathrm{kg}\). (a) What is the frictional force on the car? (b) At what speed could you drive around this curve so that the force of friction is zero?
A carnival swing is fixed on the end of an 8.0 -m-long beam. If the swing and beam sweep through an angle of \(120^{\circ},\) what is the distance through which the riders move?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.