/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 A horse is trotting along pullin... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 64

A horse is trotting along pulling a sleigh through the snow. To move the sleigh, of mass \(m,\) straight ahead at a constant speed, the horse must pull with a force of magnitude \(T.\) (a) What is the net force acting on the sleigh? (b) What is the coefficient of kinetic friction between the sleigh and the snow?

Short Answer

Expert verified
The net force acting on the sleigh is 0. (b) Calculate the coefficient of kinetic friction between the sleigh and the snow. 渭_k = T / (m * g)

Step by step solution

01

(a) Net force calculation

To find the net force acting on the sleigh, we need to consider the forces acting on it. There are two forces acting on the sleigh: tension (T) exerted by the horse and friction (f) between the sleigh and the snow. Since the sleigh is moving at a constant speed, the net force acting on the sleigh must be zero. Therefore, the tension force is equal and opposite to the friction force. Mathematically: Net force = T - f = 0 Hence, T = f The net force acting on the sleigh is 0.
02

(b) Coefficient of kinetic friction calculation

To find the coefficient of kinetic friction (渭_k), we need to use the friction formula: f = 渭_k * N where f is the friction force, N is the normal force acting on the sleigh (which is equal to its weight), and 渭_k is the coefficient of kinetic friction. Since the sleigh is moving horizontally, its normal force (N) will be equal to its gravitational force, which is given by: N = m * g where m is the mass of the sleigh and g is the gravitational acceleration (approximately 9.81 m/s^2) Since we derived earlier that the tension force equals the friction force (T = f), we can substitute f by T: T = 渭_k * m * g Now, to find the coefficient of kinetic friction (渭_k), we need to rearrange the equation: 渭_k = T / (m * g) By plugging the given values of tension force (T) and mass (m) into the equation, we can calculate the coefficient of kinetic friction (渭_k).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A block of mass \(m_{1}=3.0 \mathrm{kg}\) rests on a frictionless horizontal surface. A second block of mass \(m_{2}=2.0 \mathrm{kg}\) hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block. The blocks are released from rest. (a) Find the acceleration of the two blocks after they are released. (b) What is the velocity of the first block 1.2 s after the release of the blocks, assuming the first block does not run out of room on the table and the second block does not land on the floor? (c) How far has block 1 moved during the 1.2 -s interval? (d) What is the displacement of the blocks from their initial positions 0.40 s after they are released?
A man lifts a 2.0 -kg stone vertically with his hand at a constant upward velocity of \(1.5 \mathrm{m} / \mathrm{s} .\) What is the magnitude of the total force of the man's hand on the stone?
Find the altitudes above the Earth's surface where Earth's gravitational field strength would be (a) two thirds and (b) one third of its value at the surface. [Hint: First find the radius for each situation; then recall that the altitude is the distance from the surface to a point above the surface. Use proportional reasoning.]
The mass of the Moon is 0.0123 times that of the Earth. A spaceship is traveling along a line connecting the centers of the Earth and the Moon. At what distance from the Earth does the spaceship find the gravitational pull of the Earth equal in magnitude to that of the Moon? Express your answer as a percentage of the distance between the centers of the two bodies.
A helicopter of mass \(M\) is lowering a truck of mass \(m\) onto the deck of a ship. (a) At first, the helicopter and the truck move downward together (the length of the cable doesn't change). If their downward speed is decreasing at a rate of \(0.10 g,\) what is the tension in the cable? (b) As the truck gets close to the deck, the helicopter stops moving downward. While it hovers, it lets out the cable so that the truck is still moving downward. If the truck's downward speed is decreasing at a rate of \(0.10 g,\) while the helicopter is at rest, what is the tension in the cable?
See all solutions

Recommended explanations on Physics Textbooks

Electricity and Magnetism

Read Explanation

Quantum Physics

Read Explanation

Rotational Dynamics

Read Explanation

Mechanics and Materials

Read Explanation

Engineering Physics

Read Explanation

Energy Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.