91Ó°ÊÓ

As the skydiver is falling at a constant speed, the net force acting on him must be equal to zero. We can use this fact to determine the force of air resistance acting on the skydiver. The skydiver's weight is balanced by the sum of the upward parachute force and the air resistance force. So, let's write the equation of motion: $$ \text{Weight} - \text{Parachute Force} - \text{Air Resistance Force} = 0 $$ Now, plug in the given values and solve for the air resistance force: $$ 650 \,\text{N} - 620 \,\text{N} - F_{\text{air}} = 0 \\ F_{\text{air}} = 650 \,\text{N} - 620 \,\text{N} \\ F_{\text{air}} = 30 \,\text{N} $$ The force of air resistance acting on the skydiver is \(30 \,\text{N}\).

There are three forces acting on the skydiver: 1. Weight (\(650 \,\text{N}\)) acting downward, this force is due to the Earth's gravity and its interaction partner is the Earth. 2. Parachute force (\(620 \,\text{N}\)) acting upward, this force is due to the tension in the parachute apparatus, and its interaction partner is the parachute. 3. Air resistance force (\(30 \,\text{N}\)) acting upward, this force is due to the interaction between the skydiver and the air molecules, and its interaction partner is the air.

There are two main forces acting on the parachute: 1. Parachute force (\(620 \,\text{N}\)) acting downward, this force is due to the tension in the parachute apparatus, and its interaction partner is the skydiver. 2. Combined air resistance force acting upward, this force is due to the interaction between the parachute, skydiver, and the air molecules, and its interaction partner is the air. Since the skydiver is falling at a constant speed, this combined force should balance the parachute force, i.e., \(620 \,\text{N}\). Keep in mind that the question only asked about the air resistance force on the skydiver, not the parachute, which is why we didn't calculate the air resistance force for the parachute separately.