/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Two cars are driving toward each... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two cars are driving toward each other on a straight, flat Kansas road. The Jeep Wrangler is traveling at \(82 \mathrm{km} / \mathrm{h}\) north and the Ford Taurus is traveling at \(48 \mathrm{km} / \mathrm{h}\) south, both measured relative to the road. What is the velocity of the Jeep relative to an observer in the Ford?

Short Answer

Expert verified
Answer: The relative velocity of the Jeep Wrangler with respect to an observer in the Ford Taurus is 130 km/h in the north direction.

Step by step solution

01

Convert Velocities to the Same Units

Since the velocities are given in km/h, there is no need to change the units.
02

Determine Whether Velocities Are Positive or Negative

Since they are in opposite directions (north and south), we should assign positive and negative signs based on their directions. Let's consider the north direction as positive and the south direction as negative: Jeep Wrangler velocity: \(+82 \mathrm{km/h}\) Ford Taurus velocity: \(-48 \mathrm{km/h}\)
03

Calculate Relative Velocity

To find the velocity of the Jeep Wrangler relative to the Ford Taurus, subtract the velocity of the Ford Taurus from the velocity of the Jeep Wrangler: Relative velocity (Vr) = Velocity of Jeep Wrangler - Velocity of Ford Taurus Vr = \(+82 \mathrm{km/h} - (-48 \mathrm{km/h})\)
04

Simplify the Equation

Simplify by adding the two velocities: Vr = \(82 \mathrm{km/h} + 48 \mathrm{km/h}\)
05

Find the Relative Velocity

Add the velocities to find the relative velocity: Vr = \(130 \mathrm{km/h}\) (north direction, because the result is positive) Thus, the velocity of the Jeep Wrangler relative to an observer in the Ford Taurus is \(130 \mathrm{km/h}\) in the north direction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A gull is flying horizontally \(8.00 \mathrm{m}\) above the ground at $6.00 \mathrm{m} / \mathrm{s} .$ The bird is carrying a clam in its beak and plans to crack the clamshell by dropping it on some rocks below. Ignoring air resistance, (a) what is the horizontal distance to the rocks at the moment that the gull should let go of the clam? (b) With what speed relative to the rocks does the clam smash into the rocks? (c) With what speed relative to the gull does the clam smash into the rocks?
A car travels three quarters of the way around a circle of radius $20.0 \mathrm{m}\( in a time of \)3.0 \mathrm{s}$ at a constant speed. The initial velocity is west and the final velocity is south. (a) Find its average velocity for this trip. (b) What is the car's average acceleration during these 3.0 s? (c) Explain how a car moving at constant speed has a nonzero average acceleration.
A small plane is flying directly west with an airspeed of $30.0 \mathrm{m} / \mathrm{s} .\( The plane flies into a region where the wind is blowing at \)10.0 \mathrm{m} / \mathrm{s}\( at an angle of \)30^{\circ}$ to the south of west. (a) If the pilot does not change the heading of the plane, what will be the ground speed of the airplane? (b) What will be the new directional heading, relative to the ground, of the airplane? (tutorial: flight of crow)
The velocity vector of a sprinting cheetah has \(x\) - and \(y\) -components \(v_{x}=+16.4 \mathrm{m} / \mathrm{s}\) and $v_{y}=-26.3 \mathrm{m} / \mathrm{s}$ (a) What is the magnitude of the velocity vector? (b) What angle does the velocity vector make with the \(+x\) - and \(-y\) -axes?
The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was \(36.6 \mathrm{m}\) long and it had a muzzle speed of \(1.46 \mathrm{km} / \mathrm{s} .\) When the gun's angle of elevation was set to \(55^{\circ},\) what would be the range? For the purposes of solving this problem, neglect air resistance. (The actual range at this elevation was \(121 \mathrm{km} ;\) air resistance cannot be ignored for the high muzzle speed of the shells.)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.