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Chapter 29: Problem 6

How many neutrons are found in a \(^{35} \mathrm{Cl}\) nucleus?

Short Answer

Expert verified
Answer: There are 18 neutrons in a \(^{35} \mathrm{Cl}\) nucleus.

Step by step solution

01

Determine the atomic number of Chlorine

From the periodic table, we find that the atomic number of Chlorine (Cl) is 17. This means that there are 17 protons in its nucleus.
02

Find the mass number of the isotope

The notation \(^{35} \mathrm{Cl}\) has a mass number of 35, which is the total number of protons and neutrons combined in the nucleus.
03

Calculate the number of neutrons

To find the number of neutrons, subtract the atomic number (number of protons) from the mass number (number of protons and neutrons combined), i.e., Neutrons = Mass number - Atomic number = 35 - 17 = 18. So, there are 18 neutrons in a \(^{35} \mathrm{Cl}\) nucleus.

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Most popular questions from this chapter

Radium- 226 decays as ${ }_{88}^{226} \mathrm{Ra} \rightarrow{ }_{86}^{222} \mathrm{Rn}+{ }_{2}^{4} \mathrm{He} .\( If the \){ }_{88}^{226}$ Ra nucleus is at rest before the decay and the \({ }_{86}^{222} \mathrm{Rn}\) nucleus is in its ground state, estimate the kinetic energy of the \(\alpha\) particle. (Assume that the \({ }_{86}^{222} \mathrm{Rn}\) nucleus takes away an insignificant fraction of the kinetic energy.)
The half-life of I-131 is 8.0 days. A sample containing I- 131 has an activity of \(6.4 \times 10^{8}\) Bq. How many days later will the sample have an activity of \(2.5 \times 10^{6} \mathrm{Bq} ?\) (Wills tutorial: radioactive decay)
In naturally occurring potassium, \(0.0117 \%\) of the nuclei are radioactive \(^{40} \mathrm{K} .\) (a) What mass of \(^{40} \mathrm{K}\) is found in a broccoli stalk containing \(300 \mathrm{mg}\) of potassium? (b) What is the activity of this broccoli stalk due to \(^{40} \mathrm{K} ?\)
Approximately what is the total energy of the neutrino emitted when ${ }_{11}^{22} \mathrm{Na}$ decays by electron capture?
The radioactive decay of \(^{238} \mathrm{U}\) produces \(\alpha\) particles with a kinetic energy of \(4.17 \mathrm{MeV} .\) (a) At what speed do these \(\alpha\) particles move? (b) Put yourself in the place of Rutherford and Geiger. You know that \(\alpha\) particles are positively charged (from the way they are deflected in a magnetic field). You want to measure the speed of the \(\alpha\) particles using a velocity selector. If your magnet produces a magnetic field of \(0.30 \mathrm{T},\) what strength electric field would allow the \(\alpha\) particles to pass through undeflected? (c) Now that you know the speed of the \(\alpha\) particles, you measure the radius of their trajectory in the same magnetic field (without the electric field) to determine their charge-to-mass ratio. Using the charge and mass of the \(\alpha\) particle, what would the radius be in a \(0.30-\mathrm{T}\) field? (d) Why can you determine only the charge-to-mass ratio \((q / m)\) by this experiment, but not the individual values of \(q\) and \(m ?\)
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