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Chapter 28: Problem 65

What is the ground-state electron configuration of tellurium (Te, atomic number 52 )?

Short Answer

Expert verified
The ground-state electron configuration of tellurium (Te) is [TeX]1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^4[/TeX].

Step by step solution

01

Identify the position of tellurium in the periodic table

Tellurium is in Group 16 (also known as the chalcogens) and Period 5 of the periodic table. Remember that the atomic number (Z) of tellurium is 52, meaning that it has 52 electrons in its ground state.
02

Apply the Aufbau principle

According to the Aufbau principle, electrons fill atomic orbitals in the order of increasing energy. The order of filling is as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p. Fill the electrons following this order until all 52 electrons are placed.
03

Fill in the electron configuration

Using the order established in Step 2, start filling the orbitals: 1s^2: 2 electrons (2 remaining) 2s^2: 2 electrons (4 remaining) 2p^6: 6 electrons (10 remaining) 3s^2: 2 electrons (12 remaining) 3p^6: 6 electrons (18 remaining) 4s^2: 2 electrons (20 remaining) 3d^10: 10 electrons (30 remaining) 4p^6: 6 electrons (36 remaining) 5s^2: 2 electrons (38 remaining) 4d^10: 10 electrons (48 remaining) 5p^4: 4 electrons (52 total, no more remaining)
04

Write the ground-state electron configuration for tellurium

Combine the filled orbitals found in Step 3 to write the electron configuration: [TeX]1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^4[/TeX]. This electron configuration represents the ground state of tellurium (Te) with an atomic number of 52.

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Most popular questions from this chapter

A bullet leaves the barrel of a rifle with a speed of $300.0 \mathrm{m} / \mathrm{s} .\( The mass of the bullet is \)10.0 \mathrm{g} .$ (a) What is the de Broglie wavelength of the bullet? (b) Compare \(\lambda\) with the diameter of a proton (about \(1 \mathrm{fm}\) ). (c) Is it possible to observe wave properties of the bullet, such as diffraction? Explain.
The particle in a box model is often used to make rough estimates of energy level spacings. Suppose that you have a proton confined to a one-dimensional box of length equal to a nuclear diameter (about \(10^{-14} \mathrm{m}\) ). (a) What is the energy difference between the first excited state and the ground state of this proton in the box? (b) If this energy is emitted as a photon as the excited proton falls back to the ground state, what is the wavelength and frequency of the electromagnetic wave emitted? In what part of the spectrum does it lie? (c) Sketch the wave function \(\psi\) as a function of position for the proton in this box for the ground state and each of the first three excited states.
(a) What are the electron configurations of the ground states of lithium \((Z=3),\) sodium \((Z=11),\) and potassium \((Z=19) ?\) (b) Why are these elements placed in the same column of the periodic table?
A proton and a deuteron (which has the same charge as the proton but 2.0 times the mass) are incident on a barrier of thickness \(10.0 \mathrm{fm}\) and "height" \(10.0 \mathrm{MeV} .\) Each particle has a kinetic energy of $3.0 \mathrm{MeV} .$ (a) Which particle has the higher probability of tunneling through the barrier? (b) Find the ratio of the tunneling probabilities.
A hydrogen atom has a radius of about \(0.05 \mathrm{nm}\) (a) Estimate the uncertainty in any component of the momentum of an electron confined to a region of this size. (b) From your answer to (a), estimate the electron's kinetic energy. (c) Does the estimate have the correct order of magnitude? (The ground-state kinetic energy predicted by the Bohr model is \(13.6 \mathrm{eV} .\) )
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