91Ó°ÊÓ

First, it is important to convert the given energies from electron volts (eV) to joules (J) since we will be working with Planck's constant, which is in units of joule-seconds. To convert eV to J, we can use the conversion factor of 1 eV = 1.6*10^(-19) J. Work function, \(\phi = 4.5 \text{eV} = 4.5 * 1.6*10^(-19) \text{J}\) Incident photon energy, \(E_{photon} = 4.8 \text{eV} = 4.8 * 1.6*10^(-19) \text{J}\)

To find the threshold frequency, \(\nu_t\), we'll use the work function equation: \(\phi = h\nu_t\) We know that Planck's constant, \(h = 6.626*10^{-34} \text{J s}\). Now, isolating \(\nu_t\) to find its value: \(\nu_t = \frac{\phi}{h}\) Substitute the values of \(\phi\) and \(h\): \(\nu_t = \frac{4.5 * 1.6*10^{-19} \text{J}}{6.626*10^{-34} \text{J s}} = 1.08 * 10^{15} \text{Hz}\) The threshold frequency is approximately \(1.08 * 10^{15} \text{Hz}\).

To find the stopping potential, \(V_0\), we will use the following equation: \(eV_0 = E_{photon} - \phi\) We know the electron charge, \(e = 1.6*10^{-19} \text{C}\). Solve for \(V_0\): \(V_0 = \frac{E_{photon} - \phi}{e}\) Substitute the values of \(E_{photon}\), \(\phi\), and \(e\): \(V_0 = \frac{(4.8 - 4.5) * 1.6*10^{-19} \text{J}}{1.6*10^{-19} \text{C}} = 0.3 \text{V}\) The stopping potential is \(0.3 \text{V}\).

In classical physics, it was assumed that the energy of an incident electromagnetic wave (light) was proportional to its amplitude, not its frequency. Therefore, a continuous energy transfer was expected between the incident wave and the electrons, independent of the frequency of the light. This means that electrons should be emitted regardless of the frequency, as long as the intensity of light is high enough. However, the photoelectric effect and subsequent experiments demonstrated that there is a threshold frequency below which no photoelectrons are emitted, even with very high-intensity light. This implies that there is a quantized relationship between the energy of incident photons and their frequency, as described by Planck's theory of light quanta and Einstein's interpretation of the photoelectric effect. In conclusion, classical physics does not predict a threshold frequency because it assumes a continuous energy transfer dependent on the amplitude of the incident light, rather than the quantized relationship between energy and frequency observed in the photoelectric effect.