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Chapter 27: Problem 4

The photoelectric threshold frequency of silver is $1.04 \times 10^{15} \mathrm{Hz} .$ What is the minimum energy required to remove an electron from silver?

Short Answer

Expert verified
Answer: The minimum energy required to remove an electron from silver is \(6.89104 \times 10^{-19} \mathrm{J}\).

Step by step solution

01

Identify the given values and constants

We are given the threshold frequency of silver, \(\nu = 1.04 \times 10^{15} \mathrm{Hz}\). Planck's constant, \(h = 6.626 \times 10^{-34} \mathrm{Js}\)
02

Apply the photon energy formula

To find the minimum energy required to remove an electron from silver, we use the formula \(E = h \nu\).
03

Calculate the minimum energy

Now, substitute the given values of \(h\) and \(\nu\) into the formula: \(E = (6.626 \times 10^{-34} \mathrm{Js}) (1.04 \times 10^{15} \mathrm{Hz})\) \(E = 6.89104 \times 10^{-19} \mathrm{J}\)
04

Write the final answer

The minimum energy required to remove an electron from silver is \(6.89104 \times 10^{-19} \mathrm{J}\).

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Most popular questions from this chapter

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