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A spaceship is traveling away from Earth at \(0.87 c .\) The astronauts report home by radio every 12 h (by their own clocks). (a) At what interval are the reports sent to Earth, according to Earth clocks? (b) At what interval are the reports received by Earth observers, according to their own clocks?

Short Answer

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In order to answer this question, follow the step-by-step solution provided: Step 1: Calculate the time dilation factor, which is given by the formula \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\). In this case, \(v = 0.87c\). Step 2: Determine the time intervals according to Earth's clocks (t_Earth) using the equation: \(t_{Earth} = \gamma t_{astronaut}\), where \(t_{astronaut} = 12\) hours. Step 3: Calculate the observed frequency by Earth observers (f_Earth) using the Doppler effect formula for light: \(f_{Earth} = f_{astronaut}\frac{1}{1 + \frac{v}{c}}\). Step 4: Calculate the time intervals between received reports by Earth observers (t_received) by taking the inverse of the observed frequency: \(t_{received} = \frac{1}{f_{Earth}}\). The interval at which the reports are sent according to Earth clocks is \(t_{Earth}\), and the interval at which the reports are received by Earth observers is \(t_{received}\).

Step by step solution

01

Calculate time dilation factor

First, we need to find the time dilation factor, given by \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\), where \(v\) is the speed of the spaceship and \(c\) is the speed of light. In this case, \(v = 0.87c\). So, let's calculate the time dilation factor: $$\gamma = \frac{1}{\sqrt{1-\frac{(0.87c)^2}{c^2}}} $$
02

Determine time intervals according to Earth's clocks

Now that we have calculated the time dilation factor, we can find the time interval between the astronaut's reports according to Earth clocks (t_Earth) using the equation: \(t_{Earth} = \gamma t_{astronaut}\), where \(t_{astronaut}\) is the time interval according to the astronaut's clock. $$t_{Earth} = \gamma \cdot 12 \text{ hours}$$
03

Calculate frequency for Earth observers

Now that we have the time interval between reports according to Earth clocks, we can find the frequency observed by Earth observers (f_Earth) using the Doppler effect formula for light: $$f_{Earth} = f_{astronaut}\frac{1}{1 + \frac{v}{c}}$$ where \(f_{astronaut}\) is the frequency of the signals sent by the astronauts. We can find the frequency of the signals sent by the astronauts using their given time intervals: \(f_{astronaut} = \frac{1}{12 \text{ hours}}\). Substitute this into the Doppler effect formula: $$f_{Earth} = \frac{1}{12 \text{ hours}}\frac{1}{1 + \frac{0.87c}{c}}$$
04

Calculate time intervals between received reports

Now that we have the frequency observed by Earth observers, we can find the time intervals between the received reports (t_received) by taking the inverse of the observed frequency: \(t_{received} = \frac{1}{f_{Earth}}\). Calculate the time intervals between the received reports: $$t_{received} = \frac{1}{f_{Earth}}$$ Now, we can find both the interval at which the reports are sent according to Earth clocks and the interval at which they are received by Earth observers. (a) The interval at which the reports are sent according to Earth clocks is \(t_{Earth}\). (b) The interval at which the reports are received by Earth observers is \(t_{received}\).

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