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#tag_title#Step 2: Convert MeV to Joules#tag_content#Using the conversion factor 1 MeV = 1.60218 × 10^{-13} J, we can convert the momentum in MeV/c to momentum in Joules per speed of light (J/c). For example, if we have a momentum of 2 MeV/c, we can convert it to Joules as follows: (2 MeV/c) × (1.60218 × 10^{-13} J/MeV) = 3.20436 × 10^{-13} J/c #tag_title#Step 3: Convert energy to mass#tag_content#Now, we can use the mass-energy equivalence formula (E = mc^2) to convert the energy in Joules to mass in kilograms (kg). To do this, divide the energy by the speed of light squared (c²): mass = (3.20436 × 10^{-13} J) / (c^2) = 3.20436 × 10^{-13} J / (299,792,458 m/s)^2 mass ≈ 3.57310 × 10^{-30} kg #tag_title#Step 4: Multiply mass by speed of light#tag_content#Finally, we can multiply the mass in kilograms by the speed of light in m/s to find the momentum in SI units (kg·m/s): momentum = (3.57310 × 10^{-30} kg) × (299,792,458 m/s) ≈ 1.07 × 10^{-22} kg·m/s So, the momentum in SI units is approximately 1.07 × 10^{-22} kg·m/s. Question: Convert a momentum of 5 MeV/c to SI units (kg·m/s).