/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Telescopes (a) If you were s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Telescopes (a) If you were stranded on an island with only a pair of 3.5 -D reading glasses, could you make a telescope? If so, what would be the length of the telescope and what would be the best possible angular magnification? (b) Answer the same questions if you also had a pair of 1.3 -D reading glasses.

Short Answer

Expert verified
If not, what is the best possible angular magnification if we also have a pair of 1.3 -D reading glasses? Answer: No, it is not possible to create a telescope that provides any magnification using only a pair of 3.5 -D reading glasses. The best possible angular magnification when using both 3.5 -D and 1.3 -D reading glasses is approximately 2.69.

Step by step solution

01

Understand the formula for angular magnification

The angular magnification (M) of a telescope is given by the formula: M = (-f_obj) / (f_eye) where f_obj is the focal length of the objective lens and f_eye is the focal length of the eyepiece lens.
02

Analyze the constraints and calculate the required focal lengths

The power (P) of a lens is given by the formula: P = 1/f where f is the focal length of the lens. In the first part of the exercise, we are given a pair of 3.5 -D reading glasses. We can calculate the focal length (f_eye) using the formula: f_eye = 1/P = 1/(-3.5 D) = -1/3.5 m In the second part of the exercise, we also have a pair of 1.3 -D reading glasses. We can similarly calculate the focal length (f_obj) for these glasses: f_obj = 1/P = 1/(-1.3 D) = -1/1.3 m
03

Calculate the best possible angular magnification for each scenario

(a) If we only have a pair of 3.5 -D reading glasses, we can use these as both the eyepiece and the objective lens. Therefore, f_eye = f_obj and the angular magnification becomes: M = (-f_obj) / (f_eye) = (-(-1/3.5 m))/(1/3.5 m) = 1 This means that the best possible angular magnification with only 3.5 -D reading glasses is 1 (no magnification). Therefore, it is not possible to make a telescope that provides any magnification using only the 3.5 -D reading glasses. In this case, the length of the telescope would be approximately the distance between the lenses, which is given as the sum of their focal lengths: Length = f_obj + f_eye = (-1/3.5 m) + (-1/3.5 m) = -2/3.5 m ≈ -0.57 m (b) If we also have a pair of 1.3 -D reading glasses, we can use these as the objective lens while still using the 3.5 -D reading glasses as the eyepiece lens. In this case, the angular magnification becomes: M = (-f_obj) / (f_eye) = (-(-1/1.3 m))/(1/3.5 m) = 3.5/1.3 ≈ 2.69 This means that the best possible angular magnification with both 3.5 -D and 1.3 -D reading glasses is approximately 2.69. In this case, the length of the telescope would be approximately the distance between the lenses, which is given as the sum of their focal lengths: Length = f_obj + f_eye = (-1/1.3 m) + (-1/3.5 m) = (-1/1.3) + (-1/3.5) m ≈ -0.92 m

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A camera has a telephoto lens of 240 -mm focal length. The lens can be moved in and out a distance of \(16 \mathrm{mm}\) from the film plane by rotating the lens barrel. If the lens can focus objects at infinity, what is the closest object distance that can be focused?
An object is located \(16.0 \mathrm{cm}\) in front of a converging lens with focal length \(12.0 \mathrm{cm} .\) To the right of the converging lens, separated by a distance of \(20.0 \mathrm{cm},\) is a diverging lens of focal length \(-10.0 \mathrm{cm} .\) Find the location of the final image by ray tracing and verify using the lens equations.
Unless the problem states otherwise, assume that the distance from the comea- lens system to the retina is \(2.0 \mathrm{cm}\) and the normal near point is \(25 \mathrm{cm}.\) If the distance from the lens system (cornea + lens) to the retina is $2.00 \mathrm{cm},$ show that the focal length of the lens system must vary between \(1.85 \mathrm{cm}\) and \(2.00 \mathrm{cm}\) to see objects from $25.0 \mathrm{cm}$ to infinity.
Comprehensive Problems Good lenses used in cameras and other optical devices are actually compound lenses, made of five or more lenses put together to minimize distortions, including chromatic aberration. Suppose a converging lens with a focal length of \(4.00 \mathrm{cm}\) is placed right next to a diverging lens with focal length of \(-20.0 \mathrm{cm} .\) An object is placed \(2.50 \mathrm{m}\) to the left of this combination. (a) Where will the image be located? (b) Is the image real or virtual?

A refracting telescope is \(45.0 \mathrm{cm}\) long and the caption states that the telescope magnifies images by a factor of \(30.0 .\) Assuming these numbers are for viewing an object an infinite distance away with minimum eyestrain, what is the focal length of each of the two lenses?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.