91Ó°ÊÓ

The Impedance (Z) of the circuit can be found using the given amplitude of Voltage(V) and Current(I) using, \(Z =\frac{V}{I}\). So, plug in the given values to get the Impedance (Z) of the circuit. $$Z = \frac{10.0 V}{0.50 A} = 20.0 \,\Omega !$$

Next, we find the amplitude of the reactance (X). We are given the resistance (R) in the circuit and we have calculated impedance (Z), so we can use the following formula to find the reactance (X): $$X = \sqrt{Z^2 - R^2}$$ where X is the reactance, Z is impedance, and R is resistance. $$X = \sqrt{(20.0 \, \Omega)^2 - (15.0 \, \Omega)^2} = \sqrt{625} \, \Omega$$ $$X = 25.0 \, \Omega$$

Now that we have the impedance (Z) and resistance (R), we can calculate the power factor (PF) of the circuit using the following formula: $$PF = \frac{R}{Z}$$ $$PF = \frac{15.0 \, \Omega}{20.0 \, \Omega} = 0.75$$

Using the power factor, we can calculate the phase angle (θ) between the voltage and current using: $$\cos{\theta} = PF$$ $$\theta = \arccos{(PF)}$$ $$\theta = \arccos{(0.75)} = 41.4°$$

The circuit contains a resistor, inductor, and capacitor. In an inductor, the current lags the voltage, and in a capacitor, the current leads the voltage. Since we are not told the values of the inductor (L) and capacitor (C), we cannot determine the net effect in this case. However, if the net effect was reactive (inductive or capacitive), the magnitude of the phase angle would have been exactly 90°. But the phase angle is 41.4° which is not exactly 90°. So, there must be some complex combination of inductor and capacitor effects that lead to a net phase angle of 41.4°. Hence, we cannot determine whether the current leads or lags the source voltage without more information. In conclusion: a) The power factor for the circuit is 0.75, and the phase angle is 41.4°. b) We cannot determine whether the current leads or lags the source voltage without more information on the inductor and capacitor values.