/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A uniform magnetic field of magn... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A uniform magnetic field of magnitude 0.29 T makes an angle of \(13^{\circ}\) with the plane of a circular loop of wire. The loop has radius $1.85 \mathrm{cm} .$ What is the magnetic flux through the loop?

Short Answer

Expert verified
Question: Calculate the magnetic flux through a circular loop of wire with a radius of 1.85 cm, placed in a uniform magnetic field of 0.29 T. The angle between the magnetic field and the plane of the loop is 13°. Answer: The magnetic flux through the circular loop is approximately 0.000307 Tm².

Step by step solution

01

1. Calculate the area of the circular loop

The area A of the circular loop can be calculated using the formula A = πr². We are given the radius r = 0.0185 m, so: A = π(0.0185)² A ≈ 0.001076 m²
02

2. Convert the angle to radians

The angle θ is given in degrees, we need to convert it to radians first: θ = 13° × (π/180) θ ≈ 0.227 radians
03

3. Calculate the magnetic flux through the loop

Now we can calculate the magnetic flux Φ using the formula: Φ = B × A × cos(θ) Φ = (0.29 T) × (0.001076 m²) × cos(0.227 radians) Φ ≈ 0.000307 Tm² So, the magnetic flux through the circular loop is approximately 0.000307 Tm².

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The current in a \(0.080-\mathrm{H}\) solenoid increases from \(20.0 \mathrm{mA}\) to \(160.0 \mathrm{mA}\) in \(7.0 \mathrm{s} .\) Find the average emf in the solenoid during that time interval.
The outside of an ideal solenoid $\left(N_{1} \text { turns, length } L\right.\( radius \)r)\( is wound with a coil of wire with \)N_{2}$ turns. (a) What is the mutual inductance? (b) If the current in the solenoid is changing at a rate \(\Delta I_{1} / \Delta t,\) what is the magnitude of the induced emf in the coil?
A step-down transformer has 4000 turns on the primary and 200 turns on the secondary. If the primary voltage amplitude is \(2.2 \mathrm{kV},\) what is the secondary voltage amplitude?
The largest constant magnetic field achieved in the laboratory is about $40 \mathrm{T}$. (a) What is the magnetic energy density due to this field? (b) What magnitude electric field would have an equal energy density?
A flip coil is a device used to measure a magnetic field. A coil of radius $r, N\( turns, and electrical resistance \)R$ is initially perpendicular to a magnetic field of magnitude B. The coil is connected to a special kind of galvanometer that measures the total charge \(Q\) that flows through it. To measure the field, the flip coil is rapidly flipped upside down. (a) What is the change in magnetic flux through the coil in one flip? (b) If the time interval during which the coil is flipped is \(\Delta t,\) what is the average induced emf in the coil? (c) What is the average current that flows through the galvanometer? (d) What is the total charge \(Q\) in terms of \(r, N, R,\) and \(B ?\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.