/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A chipmunk, trying to cross a ro... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A chipmunk, trying to cross a road, first moves \(80 \mathrm{cm}\) to the right, then \(30 \mathrm{cm}\) to the left, then \(90 \mathrm{cm}\) to the right, and finally \(310 \mathrm{cm}\) to the left. (a) What is the chipmunk's total displacement? (b) If the elapsed time was \(18 \mathrm{s},\) what was the chipmunk's average speed? (c) What was its average velocity?

Short Answer

Expert verified
Answer: The chipmunk's total displacement is -1.70 m to the left, its average speed is 0.283 m/s, and its average velocity is -0.0944 m/s.

Step by step solution

01

Find the total distance traveled by the chipmunk

To find the total distance traveled by the chipmunk, we simply sum up all the distances it moved in each direction because distance is always positive. Total distance = 80 cm + 30 cm + 90 cm + 310 cm = 510 cm
02

Find the total displacement of the chipmunk

Displacement is a vector quantity. To find the total displacement, we can consider the rightward movement as positive and the leftward movement as negative, so we subtract the leftward movements from the rightward movements. Total displacement = (80 cm + 90 cm) - (30 cm + 310 cm) = 170 cm - 340 cm = -170 cm The displacement is negative, meaning the chipmunk is 170 cm to the left of its starting point.
03

Calculate the average speed of the chipmunk

To find the average speed, we can use the formula: Average speed = Total distance / Total time As given, the elapsed time is 18 seconds. Converting the total distance to meters, we get: 510 cm = 5.1 m So, the average speed is: Average speed = 5.10 m / 18 s = 0.283 m/s
04

Calculate the average velocity of the chipmunk

To find the average velocity, we can use the formula: Average velocity = Total displacement / Total time Converting the total displacement to meters, we get: -170 cm = -1.70 m So, the average velocity is: Average velocity = -1.70 m / 18 s = -0.0944 m/s
05

Final answers

(a) The chipmunk's total displacement is -170 cm or -1.70 m to the left. (b) The chipmunk's average speed is 0.283 m/s. (c) The chipmunk's average velocity is -0.0944 m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of \(1.7 \mathrm{m} / \mathrm{s}^{2}\) how long does it take for the antelope to reach a speed of \(22 \mathrm{m} / \mathrm{s} ?\)
A train, traveling at a constant speed of \(22 \mathrm{m} / \mathrm{s}\), comes to an incline with a constant slope. While going up the incline, the train slows down with a constant acceleration of magnitude $1.4 \mathrm{m} / \mathrm{s}^{2} .\( (a) Draw a graph of \)v_{x}\( versus \)t\( where the \)x$ -axis points up the incline. (b) What is the speed of the train after $8.0 \mathrm{s}$ on the incline? (c) How far has the train traveled up the incline after \(8.0 \mathrm{s} ?\) (d) Draw a motion diagram, showing the trains position at 2.0 -s intervals.
Find the point of no return for an airport runway of \(1.50 \mathrm{mi}\) in length if a jet plane can accelerate at \(10.0 \mathrm{ft} / \mathrm{s}^{2}\) and decelerate at \(7.00 \mathrm{ft} / \mathrm{s}^{2} .\) The point of no return occurs when the pilot can no longer abort the takeoff without running out of runway. What length of time is available from the start of the motion in which to decide on a course of action?
An airplane lands and starts down the runway with a southwest velocity of $55 \mathrm{m} / \mathrm{s}$. What constant acceleration allows it to come to a stop in \(1.0 \mathrm{km} ?\)
In the problems, please assume the free-fall acceleration $g=9.80 \mathrm{m} / \mathrm{s}^{2}$ unless a more precise value is given in the problem statement. Ignore air resistance. To pass a physical fitness test, Marcella must run \(1000 \mathrm{m}\) at an average speed of \(4.00 \mathrm{m} / \mathrm{s} .\) She runs the first $500 \mathrm{m}\( at an average of \)4.20 \mathrm{m} / \mathrm{s} .$ (a) How much time does she have to run the last \(500 \mathrm{m} ?\) (b) What should be her average speed over the last \(500 \mathrm{m}\) in order to finish with an overall average speed of \(4.00 \mathrm{m} / \mathrm{s} ?\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.