/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 A galvanometer has a coil resist... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 18: Problem 76

A galvanometer has a coil resistance of \(50.0 \Omega\). It is to be made into an ammeter with a full-scale deflection equal to \(10.0 \mathrm{A} .\) If the galvanometer deflects full scale for a current of \(0.250 \mathrm{mA},\) what size shunt resistor should be used?

Short Answer

Expert verified
Answer: The value of the shunt resistor needed is approximately 0.00125 惟.

Step by step solution

01

Find the total current through the parallel combination

Since the desired full-scale deflection for the ammeter is 10.0 A, and the galvanometer can deflect full scale with a current of 0.250 mA, the total current passing through the parallel combination of the galvanometer and the shunt resistor must be 10.0 A.
02

Calculate the voltage across the galvanometer

We'll first calculate the voltage across the galvanometer when it's at its full-scale deflection. To do this, we can use Ohm's Law, which states that \(V = IR\). We're given the coil resistance of the galvanometer \(R_g = 50.0\,\Omega\) and the full-scale current \(I_g = 0.250\,\mathrm{mA} = 0.00025\,\mathrm{A}\). So: \(V_g = I_g \cdot R_g = 0.00025\,\mathrm{A} \cdot 50.0\,\Omega = 0.0125\,\mathrm{V}\)
03

Calculate the current through the shunt resistor

Now that we have the voltage across the galvanometer, we can determine the current passing through the shunt resistor. Since the galvanometer and the shunt resistor are connected in parallel, the voltage across both is equal. Thus, we can find the current through the shunt resistor \(I_s\) using the total current \(I_t = 10.0\,\mathrm{A}\) and the current through the galvanometer \(I_g\): \(I_s = I_t - I_g = 10.0\,\mathrm{A} - 0.00025\,\mathrm{A} = 9.99975\,\mathrm{A}\)
04

Calculate the shunt resistor value

Finally, we can calculate the value of the shunt resistor \(R_s\). Since the voltage across the shunt resistor is the same as the voltage across the galvanometer, we can use Ohm's Law again: \(R_s = \dfrac{V_g}{I_s} = \dfrac{0.0125\,\mathrm{V}}{9.99975\,\mathrm{A}} = 0.0012500625\,\Omega\) The shunt resistor value should be approximately \(0.00125\,\Omega\) to convert the galvanometer into an ammeter with a full-scale deflection of 10.0 A.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 1.5 -horsepower motor operates on \(120 \mathrm{V}\). Ignoring \(l^{2} R\) losses, how much current does it draw?
A galvanometer is to be turned into a voltmeter that deflects full scale for a potential difference of \(100.0 \mathrm{V}\) What size resistor should be placed in series with the galvanometer if it has an internal resistance of $75 \Omega\( and deflects full scale for a current of \)2.0 \mathrm{mA} ?$
In an ion accelerator, \(3.0 \times 10^{13}\) helium-4 nuclei (charge \(+2 e\) ) per second strike a target. What is the beam current?
A defibrillator passes a brief burst of current through the heart to restore normal beating. In one such defibrillator, a 50.0 - \(\mu \mathrm{F}\) capacitor is charged to \(6.0 \mathrm{kV}\). Paddles are used to make an electric connection to the patient's chest. A pulse of current lasting 1.0 ms partially discharges the capacitor through the patient. The electrical resistance of the patient (from paddle to paddle) is \(240 \Omega\) (a) What is the initial energy stored in the capacitor? (b) What is the initial current through the patient? (c) How much energy is dissipated in the patient during the 1.0 ms? (d) If it takes 2.0 s to recharge the capacitor, compare the average power supplied by the power source with the average power delivered to the patient. (e) Referring to your answer to part (d), explain one reason a capacitor is used in a defibrillator.
Two copper wires, one double the diameter of the other, have the same current flowing through them. If the thinner wire has a drift speed \(v_{1},\) and the thicker wire has a drift speed \(v_{2},\) how do the drift speeds of the charge carriers compare?
See all solutions

Recommended explanations on Physics Textbooks

Space Physics

Read Explanation

Dynamics

Read Explanation

Electricity

Read Explanation

Translational Dynamics

Read Explanation

Particle Model of Matter

Read Explanation

Torque and Rotational Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.