/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A potential difference is applie... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 18: Problem 6

A potential difference is applied between the electrodes in a gas discharge tube. In 1.0 s, \(3.8 \times 10^{16}\) electrons and \(1.2 \times 10^{16}\) singly charged positive ions move in opposite directions through a surface perpendicular to the length of the tube. What is the current in the tube?

Short Answer

Expert verified
Question: Find the current in the gas discharge tube given that 3.8 x 10^16 electrons and 1.2 x 10^16 singly charged positive ions move through the tube in 1.0 s. Answer: To find the current, calculate the net charge by subtracting the charge due to positive ions from the charge due to electrons, and then divide the net charge by the time interval. The current in the gas discharge tube is given by: \(I = \frac{(3.8 \times 10^{16} \times 1.6 \times 10^{-19}) - (1.2 \times 10^{16} \times 1.6 \times 10^{-19})}{1.0}\) A.

Step by step solution

01

Calculate the charge due to electrons and positive ions.

To calculate the charge due to the given number of electrons and positive ions, we need to multiply their respective numbers by the elementary charge. The elementary charge (e) is \(1.6 \times 10^{-19}\) C. Charge due to electrons = Number of electrons 脳 Elementary charge \(Q_{e} = 3.8 \times 10^{16} \times 1.6 \times 10^{-19}\) C Charge due to positive ions = Number of positive ions 脳 Elementary charge \(Q_{p} = 1.2 \times 10^{16} \times 1.6 \times 10^{-19}\) C
02

Calculate the net charge.

Since the electrons and positive ions move in opposite directions, we need to find the net charge that passes through the surface. To do this, subtract the charge due to the positive ions from the charge due to the electrons. Net charge = Charge due to electrons - Charge due to positive ions \(Q_{net} = Q_{e} - Q_{p}\)
03

Calculate the current.

The current (I) can be found by dividing the net charge by the time interval. The time interval (螖t) is given as 1.0 s. Current = Net charge / Time interval \(I = \frac{Q_{net}}{\Delta t}\) Now, plug in the values and compute the current: \(I = \frac{(3.8 \times 10^{16} \times 1.6 \times 10^{-19}) - (1.2 \times 10^{16} \times 1.6 \times 10^{-19})}{1.0}\) A Upon calculating the above expression, you will find the current in the gas discharge tube.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A silver wire of diameter 1.0 mm carries a current of \(150 \mathrm{mA} .\) The density of conduction electrons in silver is $5.8 \times 10^{28} \mathrm{m}^{-3} .$ How long (on average) does it take for a conduction electron to move \(1.0 \mathrm{cm}\) along the wire?
What is the energy stored in a small battery if it can move \(675 \mathrm{C}\) through a potential difference of \(1.20 \mathrm{V} ?\)
A source of emf \(\&\) has internal resistance \(r\), (a) What is the terminal voltage when the source supplies a current \(I ?\) (b) The net power supplied is the terminal voltage times the current. Starting with \(P=I \Delta V,\) derive Eq. \((18-22)\) for the net power supplied by the source. Interpret each of the two terms. (c) Suppose that a battery of emf 8 and internal resistance \(r\) is being recharged: another emf sends a current \(I\) through the battery in the reverse direction (from positive terminal to negative). At what rate is electric energy converted to chemical energy in the recharging battery? (d) What is the power supplied by the recharging circuit to the battery?
In the physics laboratory, Oscar measured the resistance between his hands to be \(2.0 \mathrm{k} \Omega .\) Being curious by nature, he then took hold of two conducting wires that were connected to the terminals of an emf with a terminal voltage of \(100.0 \mathrm{V} .\) (a) What current passes through Oscar? (b) If one of the conducting wires is grounded and the other has an alternate path to ground through a \(15-\Omega\) resistor (so that Oscar and the resistor are in parallel), how much current would pass through Oscar if the maximum current that can be drawn from the emf is \(1.00 \mathrm{A} ?\)
A gold wire and an aluminum wire have the same dimensions and carry the same current. The electron density (in electrons/cm \(^{3}\) ) in aluminum is three times larger than the density in gold. How do the drift speeds of the electrons in the two wires, \(v_{\mathrm{Au}}\) and \(v_{\mathrm{Al}},\) compare?
See all solutions

Recommended explanations on Physics Textbooks

Scientific Method Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Mechanics and Materials

Read Explanation

Radiation

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Linear Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.