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Chapter 16: Problem 30

An electron traveling horizontally from west to east enters a region where a uniform electric field is directed upward. What is the direction of the electric force exerted on the electron once it has entered the field?

Short Answer

Expert verified
Answer: The electric force exerted on the electron is in the southeast direction (downward and eastward).

Step by step solution

01

Analyze the electric field and electron charge

The electric field is directed upward. Since the electron has a negative charge, the electric force acting on it will be in the opposite direction of the electric field. Therefore, the electric force on the electron will be directed downward.
02

Combine directions of electron movement and electric force

The electron is moving horizontally from west to east, and the direction of the electric force is downward. Combining these two directions, the overall direction of the electric force exerted on the electron will be southeast (downward and eastward).
03

Conclusion

The electric force exerted on the electron, once it has entered the field, is in the southeast direction (downward and eastward). This is due to the combination of the electron's horizontal movement from west to east and the downward direction of the electric force, which is opposite to the upward-directed electric field.

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Most popular questions from this chapter

A metallic sphere has a charge of \(+4.0 \mathrm{nC} .\) A negatively charged rod has a charge of \(-6.0 \mathrm{nC} .\) When the rod touches the sphere, $8.2 \times 10^{9}$ electrons are transferred. What are the charges of the sphere and the rod now?
In a uniform electric field of magnitude \(E\), the field lines cross through a rectangle of area \(A\) at an angle of \(60.0^{\circ}\) with respect to the plane of the rectangle. What is the flux through the rectangle?
In lab tests it was found that rats can detect electric fields of about $5.0 \mathrm{kN} / \mathrm{C}\( or more. If a point charge of \)1.0 \mu \mathrm{C}$ is sitting in a maze, how close must the rat come to the charge in order to detect it?
(a) What would the net charges on the Sun and Earth have to be if the electric force instead of the gravitational force were responsible for keeping Earth in its orbit? There are many possible answers, so restrict yourself to the case where the magnitude of the charges is proportional to the masses. (b) If the magnitude of the charges of the proton and electron were not exactly equal, astronomical bodies would have net charges that are approximately proportional to their masses. Could this possibly be an explanation for the Earth's orbit?
Two metal spheres separated by a distance much greater than either sphere's radius have equal mass \(m\) and equal electric charge \(q .\) What is the ratio of charge to mass \(q / m\) in C/kg if the electrical and gravitational forces balance?
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