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Chapter 16: Problem 30

An electron traveling horizontally from west to east enters a region where a uniform electric field is directed upward. What is the direction of the electric force exerted on the electron once it has entered the field?

Short Answer

Expert verified
Answer: The electric force exerted on the electron is in the southeast direction (downward and eastward).

Step by step solution

01

Analyze the electric field and electron charge

The electric field is directed upward. Since the electron has a negative charge, the electric force acting on it will be in the opposite direction of the electric field. Therefore, the electric force on the electron will be directed downward.
02

Combine directions of electron movement and electric force

The electron is moving horizontally from west to east, and the direction of the electric force is downward. Combining these two directions, the overall direction of the electric force exerted on the electron will be southeast (downward and eastward).
03

Conclusion

The electric force exerted on the electron, once it has entered the field, is in the southeast direction (downward and eastward). This is due to the combination of the electron's horizontal movement from west to east and the downward direction of the electric force, which is opposite to the upward-directed electric field.

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Most popular questions from this chapter

(a) Find the electric flux through each side of a cube of edge length \(a\) in a uniform electric field of magnitude \(E\) The field direction is perpendicular to two of the faces. (b) What is the total flux through the cube?
Two tiny objects with equal charges of \(7.00 \mu \mathrm{C}\) are placed at the two lower corners of a square with sides of \(0.300 \mathrm{m},\) as shown. Find the electric field at point \(B\) midway between the upper left and right corners.
In a cathode ray tube, electrons initially at rest are accelerated by a uniform electric field of magnitude $4.0 \times 10^{5} \mathrm{N} / \mathrm{C}\( during the first \)5.0 \mathrm{cm}$ of the tube's length; then they move at essentially constant velocity another \(45 \mathrm{cm}\) before hitting the screen. (a) Find the speed of the electrons when they hit the screen. (b) How long does it take them to travel the length of the tube?
In a uniform electric field of magnitude \(E\), the field lines cross through a rectangle of area \(A\) at an angle of \(60.0^{\circ}\) with respect to the plane of the rectangle. What is the flux through the rectangle?
(a) Use Gauss's law to prove that the electric field outside any spherically symmetric charge distribution is the same as if all of the charge were concentrated into a point charge. (b) Now use Gauss's law to prove that the electric field inside a spherically symmetric charge distribution is zero if none of the charge is at a distance from the center less than that of the point where we determine the field.
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