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Chapter 16: Problem 1

Find the total positive charge of all the protons in \(1.0 \mathrm{mol}\) of water.

Short Answer

Expert verified
Answer: The total positive charge of all the protons in 1.0 mol of water is approximately \(1.93\times10^{6}\) coulombs.

Step by step solution

01

Determine the number of protons in one water molecule

A water molecule has the chemical formula H鈧侽, which means it consists of two hydrogen atoms and one oxygen atom. Since each hydrogen atom contains 1 proton, there are 2 protons in a single water molecule.
02

Determine the number of molecules in 1.0 mol of water

One mole of any substance contains Avogadro's number (approximately \(6.022\times10^{23}\)) of particles (atoms, molecules, ions, etc.). Therefore, there are about \(6.022\times10^{23}\) water molecules in 1.0 mol of water.
03

Find the total number of protons in 1.0 mol of water

To determine the total number of protons in 1.0 mol of water, we need to multiply the number of protons in a single water molecule by the number of water molecules in 1.0 mol of water: Total protons \(= 2\) protons/water molecule \(\times 6.022\times10^{23}\) water molecules/mol \(= 1.2044\times10^{24}\) protons
04

Find the total positive charge of all the protons

The elementary charge of a single proton is approximately \(1.602\times10^{-19}\) coulombs. Therefore, to find the total positive charge of all the protons, we multiply the total number of protons by the elementary charge of a proton: Total positive charge \(= 1.2044\times10^{24}\) protons \(\times 1.602\times10^{-19}\) coulombs/proton \(\approx 1.93\times10^{6}\) coulombs So, the total positive charge of all the protons in 1.0 mol of water is about \(1.93\times10^{6}\) coulombs.

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Most popular questions from this chapter

Two point charges are located on the \(x\) -axis: a charge of \(+6.0 \mathrm{nC}\) at \(x=0\) and an unknown charge \(q\) at \(x=\) \(0.50 \mathrm{m} .\) No other charges are nearby. If the electric field is zero at the point $x=1.0 \mathrm{m},\( what is \)q ?$
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A metallic sphere has a charge of \(+4.0 \mathrm{nC} .\) A negatively charged rod has a charge of \(-6.0 \mathrm{nC} .\) When the rod touches the sphere, $8.2 \times 10^{9}$ electrons are transferred. What are the charges of the sphere and the rod now?
Three equal charges are placed on three corners of a square. If the force that \(Q_{\mathrm{a}}\) exerts on \(Q_{\mathrm{b}}\) has magnitude \(F_{\mathrm{ba}}\) and the force that \(Q_{\mathrm{a}}\) exerts on \(Q_{\mathrm{c}}\) has magnitude \(F_{\mathrm{ca}},\) what is the ratio of \(F_{\mathrm{ca}}\) to $F_{\mathrm{ba}} ?$
Three point charges are placed on the \(x\) -axis. A charge of $3.00 \mu \mathrm{C}\( is at the origin. A charge of \)-5.00 \mu \mathrm{C}\( is at \)20.0 \mathrm{cm},\( and a charge of \)8.00 \mu \mathrm{C}\( is at \)35.0 \mathrm{cm} .$ What is the force on the charge at the origin?
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