/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 A model steam engine of \(1.00-\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A model steam engine of \(1.00-\mathrm{kg}\) mass pulls eight cars of \(1.00-\mathrm{kg}\) mass each. The cars start at rest and reach a velocity of \(3.00 \mathrm{m} / \mathrm{s}\) in a time of \(3.00 \mathrm{s}\) while moving a distance of \(4.50 \mathrm{m} .\) During that time, the engine takes in $135 \mathrm{J}$ of heat. What is the change in the internal energy of the engine?

Short Answer

Expert verified
Answer: The change in internal energy of the engine is 99 J.

Step by step solution

01

Calculate the net force acting on the cars from the given information

First, let's find the net force acting on the cars. We know their initial velocity (u), final velocity (v), time taken (t), and mass (m), so we can use the equation of motion v = u + at to find the acceleration (a). Then we can use Newton's second law (F = ma) to find the force. v = 3.00 m/s u = 0 m/s t = 3.00 s Rearrange the equation of motion to solve for acceleration: a = (v - u) / t Plug the values into the equation: a = (3.00 - 0) / 3.00 a = 1.00 m/s² Now, find the net force on the cars using F = ma: F = (1.00 kg per car × 8 cars) × 1.00 m/s² F = 8.00 kg × 1.00 m/s² F = 8.00 N
02

Calculate the work done by the steam engine on the cars

Now that we have the net force acting on the cars, let's find the work done by the steam engine. We know the distance traveled by the cars (d) and the net force (F), so we can use the formula for work: W = F × d. Plug the values into the equation: W = 8.00 N × 4.50 m W = 36.00 J
03

Apply the First Law of Thermodynamics to find the change in internal energy

Now that we have the work done by the system (W) and the heat absorbed (Q), we can use the First Law of Thermodynamics to find the change in internal energy (ΔU). ΔU = Q - W Plug the values into the equation: ΔU = 135 J - 36.00 J ΔU = 99 J The change in the internal energy of the engine is 99 J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An ideal gas is in contact with a heat reservoir so that it remains at a constant temperature of \(300.0 \mathrm{K}\). The gas is compressed from a volume of \(24.0 \mathrm{L}\) to a volume of 14.0 L. During the process, the mechanical device pushing the piston to compress the gas is found to expend \(5.00 \mathrm{kJ}\) of energy. How much heat flows between the heat reservoir and the gas and in what direction does the heat flow occur?
The efficiency of an engine is \(0.21 .\) For every \(1.00 \mathrm{kJ}\) of heat absorbed by the engine, how much (a) net work is done by it and (b) heat is released by it?
A balloon contains \(200.0 \mathrm{L}\) of nitrogen gas at $20.0^{\circ} \mathrm{C}$ and at atmospheric pressure. How much energy must be added to raise the temperature of the nitrogen to \(40.0^{\circ} \mathrm{C}\) while allowing the balloon to expand at atmospheric pressure?
An air conditioner whose coefficient of performance is 2.00 removes $1.73 \times 10^{8} \mathrm{J}$ of heat from a room per day. How much does it cost to run the air conditioning unit per day if electricity costs \(\$ 0.10\) per kilowatt-hour? (Note that 1 kilowatt-hour \(=3.6 \times 10^{6} \mathrm{J} .\) )
On a cold day, Ming rubs her hands together to warm them up. She presses her hands together with a force of \(5.0 \mathrm{N} .\) Each time she rubs them back and forth they move a distance of \(16 \mathrm{cm}\) with a coefficient of kinetic friction of \(0.45 .\) Assuming no heat flow to the surroundings, after she has rubbed her hands back and forth eight times, by how much has the internal energy of her hands increased?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.