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Chapter 13: Problem 35

The principal component of natural gas is methane \(\left(\mathrm{CH}_{4}\right) .\) How many moles of \(\mathrm{CH}_{4}\) are present in \(144.36 \mathrm{g}\) of methane?

Short Answer

Expert verified
Answer: Approximately 8.99 moles of methane (CH4) are present in 144.36 g of methane.

Step by step solution

01

Determine the molar mass of methane (CH4)

Find the molar mass of methane by adding the molar masses of each element in the molecule. The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Since there is 1 carbon atom and 4 hydrogen atoms in methane, the molar mass of methane (CH4) is: Molar mass of CH4 = (1 x 12.01) + (4 x 1.01) = 12.01 + 4.04 = 16.05 g/mol.
02

Calculate the number of moles of methane

Now that we have the molar mass of methane, we can calculate the number of moles present in 144.36 g of methane using the formula: Number of moles = mass of the substance (g) / molar mass of the substance (g/mol) Number of moles of CH4 = (144.36 g) / (16.05 g/mol) = 8.99 moles So, there are approximately 8.99 moles of methane (CH4) in 144.36 g of methane.

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Most popular questions from this chapter

An iron cannonball of radius \(0.08 \mathrm{m}\) has a cavity of radius $0.05 \mathrm{m}$ that is to be filled with gunpowder. If the measurements were made at a temperature of \(22^{\circ} \mathrm{C}\) how much extra volume of gunpowder, if any, will be required to fill 500 cannonballs when the temperature is \(30^{\circ} \mathrm{C} ?\)

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Verify that the SI units of \(P V\) (pressure times volume) are joules.
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