/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A small bird's wings can undergo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A small bird's wings can undergo a maximum displacement amplitude of $5.0 \mathrm{cm}$ (distance from the tip of the wing to the horizontal). If the maximum acceleration of the wings is \(12 \mathrm{m} / \mathrm{s}^{2},\) and we assume the wings are undergoing simple harmonic motion when beating. what is the oscillation frequency of the wing tips?

Short Answer

Expert verified
Answer: The oscillation frequency of the wing tips is approximately 2.46 Hz.

Step by step solution

01

Convert the displacement amplitude to meters

The given displacement amplitude is in centimeters, so we need to convert it to meters: \(A = 5.0 \, \mathrm{cm} \times \dfrac{1 \, \mathrm{m}}{100 \, \mathrm{cm}} = 0.05 \, \mathrm{m}\)
02

Set up the formula for maximum acceleration

The formula for maximum acceleration in simple harmonic motion is: \(a = Aω^2\) We know the maximum acceleration \(a = 12 \, \mathrm{m/s^2}\) and the amplitude \(A = 0.05 \, \mathrm{m}\). Now we can plug in the values to solve for ω.
03

Solve for the angular frequency ω

Plugging the values into the equation, we get: \(12 \, \mathrm{m/s^2} = 0.05 \, \mathrm{m} \times ω^2\) Now, to find ω, we can rearrange the equation and solve for ω: \(ω^2 = \dfrac{12 \, \mathrm{m/s^2}}{0.05 \, \mathrm{m}}\) \(ω^2 = 240 \, \mathrm{s^{-2}}\) \(ω = \sqrt{240 \, \mathrm{s^{-2}}} = 15.49 \, \mathrm{rad/s}\)
04

Find the oscillation frequency using the formula \(f = \dfrac{ω}{2\pi}\)

Now, we can find the oscillation frequency using the formula: \(f = \dfrac{ω}{2\pi} = \dfrac{15.49 \, \mathrm{rad/s}}{2\pi} \approx 2.46 \, \mathrm{Hz}\) The oscillation frequency of the wing tips is approximately 2.46 Hz.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An ideal spring has a spring constant \(k=25 \mathrm{N} / \mathrm{m}\). The spring is suspended vertically. A 1.0 -kg body is attached to the unstretched spring and released. It then performs oscillations. (a) What is the magnitude of the acceleration of the body when the extension of the spring is a maximum? (b) What is the maximum extension of the spring?
A small rowboat has a mass of \(47 \mathrm{kg} .\) When a \(92-\mathrm{kg}\) person gets into the boat, the boat floats \(8.0 \mathrm{cm}\) lower in the water. If the boat is then pushed slightly deeper in the water, it will bob up and down with simple harmonic motion (neglecting any friction). What will be the period of oscillation for the boat as it bobs around its equilibrium position?
Two steel plates are fastened together using four bolts. The bolts each have a shear modulus of \(8.0 \times 10^{10} \mathrm{Pa}\) and a shear strength of $6.0 \times 10^{8} \mathrm{Pa} .\( The radius of each bolt is \)1.0 \mathrm{cm} .$ Normally, the bolts clamp the two plates together and the frictional forces between the plates keep them from sliding. If the bolts are loose, then the frictional forces are small and the bolts themselves would be subject to a large shear stress. What is the maximum shearing force \(F\) on the plates that the four bolts can withstand? (IMAGE NOT COPY)
A horizontal spring with spring constant of \(9.82 \mathrm{N} / \mathrm{m}\) is attached to a block with a mass of \(1.24 \mathrm{kg}\) that sits on a frictionless surface. When the block is 0.345 m from its equilibrium position, it has a speed of \(0.543 \mathrm{m} / \mathrm{s}\) (a) What is the maximum displacement of the block from the equilibrium position? (b) What is the maximum speed of the block? (c) When the block is \(0.200 \mathrm{m}\) from the equilibrium position, what is its speed?
Equipment to be used in airplanes or spacecraft is often subjected to a shake test to be sure it can withstand the vibrations that may be encountered during flight. A radio receiver of mass \(5.24 \mathrm{kg}\) is set on a platform that vibrates in SHM at \(120 \mathrm{Hz}\) and with a maximum acceleration of $98 \mathrm{m} / \mathrm{s}^{2}(=10 \mathrm{g}) .$ Find the radio's (a) maximum displacement, (b) maximum speed, and (c) the maximum net force exerted on it.
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.