/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Some bacteria are propelled by b... [FREE SOLUTION] | 91Ó°ÊÓ

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Some bacteria are propelled by biological motors that spin hairlike flagella. A typical bacterial motor turning at a constant angular velocity has a radius of \(1.5 \times 10^{-8} \mathrm{m},\) and a tangential speed at the rim of \(2.3 \times 10^{-5} \mathrm{m} / \mathrm{s} .\) (a) What is the angular speed (the magnitude of the angular velocity) of this bacterial motor? (b) How long does it take the motor to make one revolution?

Short Answer

Expert verified
(a) Angular speed is \(1.533 \times 10^3\, \text{rad/s}\). (b) Time for one revolution is approximately \(4.1 \times 10^{-3}\, \text{s}\).

Step by step solution

01

Understanding Angular Speed Formula

Angular speed \( \omega \) can be calculated using the formula \( \omega = \frac{v}{r} \), where \( v \) is the tangential speed and \( r \) is the radius. In this problem, \( v = 2.3 \times 10^{-5} \, \text{m/s} \) and \( r = 1.5 \times 10^{-8} \, \text{m} \).
02

Calculation of Angular Speed

Substitute the given values into the angular speed formula: \( \omega = \frac{2.3 \times 10^{-5}}{1.5 \times 10^{-8}} \). Simplifying this gives \( \omega = 1.533 \times 10^{3} \, \text{rad/s} \).
03

Understanding Time for One Revolution

To find the time \( T \) for one revolution, use the relationship \( T = \frac{2\pi}{\omega} \), where \( \omega \) is the angular speed in rad/s.
04

Calculation of Time for One Revolution

Substitute the angular speed into the formula: \( T = \frac{2\pi}{1.533 \times 10^{3}} \). This simplifies to \( T \approx 4.1 \times 10^{-3} \, \text{s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangential Speed
In physics, tangential speed refers to the speed of an object moving along a circular path. It is the linear speed of any point situated on the radius of a rotating object. Tangential speed is directly proportional to both the radius of rotation and the angular velocity of the rotating object. Simply put, if an object is spinning faster or if it is located farther from the center of rotation, its tangential speed increases.

Tangential speed is given by the formula:
  • \( v = r imes \omega \)
where \( v \) is the tangential speed, \( r \) is the radius, and \( \omega \) is the angular speed of the rotating object.
For example, in our bacterial motor exercise, if the bacterium has a radius of \( 1.5 \times 10^{-8} \) meters and a tangential speed of \( 2.3 \times 10^{-5} \) meters per second, the angular speed can be calculated by rearranging the formula to solve for \( \omega \). This shows how tangential speed and angular speed are interconnected in rotational dynamics.
Bacterial Motor
A bacterial motor is a biological machine that allows bacteria to move. These motors are remarkable, akin to tiny outboard engines, that rotate the bacterium's flagella to propel it. Bacterial motors operate at incredible speeds even though they are microscopic. These motors function through a mechanism of rotating the flagellum, a whip-like structure, to produce movement forward.

This biological marvel is powered by a molecular mechanism involving ions. Specifically, bacterial motors use a flow of protons or sometimes sodium ions to create a voltage difference, harnessing this energy to rotate the motor and propelling the bacterium. The rotational speeds can be very high, with some bacteria reaching hundreds of revolutions per second, which is pivotal for their survival as it enables them to navigate their environment effectively.
Angular Speed Formula
The angular speed formula is fundamental in describing how fast an object rotates. Angular speed, denoted as \( \omega \), tells us how quickly the rotation happens and is measured in radians per second. This is distinct from tangential speed which deals with the linear movement along the circular path.

The formula to find angular speed is:
  • \( \omega = \frac{v}{r} \)
where \( \omega \) is the angular speed, \( v \) is the tangential speed, and \( r \) is the radius of the circle. This formula stemmed from linking linear and angular speed, showing that the bigger the circle or the faster the tangential speed, the greater the angular speed.
In our example of the bacterial motor, we used this formula to find that the angular speed is approximately \( 1.533 \times 10^{3} \) radians per second. This illustrates how using simple formulas can provide a deeper understanding of motion in rotational systems.
Revolutions
Revolutions are a measure of how many complete turns an object makes. In rotational motion, knowing the number of revolutions per unit time can tell us about its speed and distance traveled along a circular path.

One complete revolution means the object has returned to its starting position after completing a full circle. A common way to measure revolutions is by determining the time taken for one full revolution, known as the period \( T \). The formula to calculate the period from angular speed is:
  • \( T = \frac{2\pi}{\omega} \)
Here, \( T \) is the time for one revolution and \( \omega \) is the angular speed. It’s important because it gives insights into how long something takes to fully rotate.
The bacterial motor example shows how we find \( T \) by using \( \omega = 1.533 \times 10^{3} \), resulting in a time of approximately \( 4.1 \times 10^{-3} \) seconds per revolution. This means in just a fraction of a second, the motor completes an entire spin, showcasing the efficiency of natural motors.

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Most popular questions from this chapter

Our sun rotates in a circular orbit about the center of the Milky Way galaxy. The radius of the orbit is \(2.2 \times 10^{20} \mathrm{m},\) and the angular speed of the sun is \(1.1 \times 10^{-15} \mathrm{rad} / \mathrm{s} .\) How long (in years) does it take for the sun to make one revolution around the center?

A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experiences a constant angular acceleration of \(0.140 \mathrm{rad} / \mathrm{s}^{2} .\) After making 2870 revolutions, its angular speed is \(137 \mathrm{rad} / \mathrm{s}\). (a) What is the initial angular velocity of the turbine? (b) How much time elapses while the turbine is speeding up?

A floor polisher has a rotating disk that has a 15 -cm radius. The disk rotates at a constant angular velocity of 1.4 rev/s and is covered with a soft material that does the polishing. An operator holds the polisher in one place for \(45 \mathrm{s},\) in order to buff an especially scuffed area of the floor. How far (in meters) does a spot on the outer edge of the disk move during this time?

A thin rod (length \(=1.50 \mathrm{m}\) ) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge. The mass of the rod may be ignored, compared to the mass of an object fixed to the top of the rod. The rod, starting from rest, tips over and rotates downward. (a) What is the angular speed of the rod just before it strikes the floor? (Hint: Consider using the principle of conservation of mechanical energy.\()\) (b) What is the magnitude of the angular acceleration of the rod just before it strikes the floor?

A dragster starts from rest and accelerates down a track. Each tire has a radius of \(0.320 \mathrm{m}\) and rolls without slipping. At a distance of \(384 \mathrm{m},\) the angular speed of the wheels is 288 rad/s. Determine (a) the linear speed of the dragster and (b) the magnitude of the angular acceleration of its wheels.

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