/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 A golf ball bounces down a fligh... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A golf ball bounces down a flight of steel stairs, striking several steps on the way down, but never hitting the edge of a step. The ball starts at the top step with a vertical velocity component of zero. If all the collisions with the stairs are elastic, and if the vertical height of the staircase is \(3.00 \mathrm{m},\) determine the bounce height when the ball reaches the bottom of the stairs. Neglect air resistance.

Short Answer

Expert verified
The bounce height at the bottom is 3.00 meters.

Step by step solution

01

Understand the Problem

We have a golf ball bouncing elastically down a flight of stairs with an initial vertical velocity of zero and a total vertical height of 3.00 meters. The goal is to find the height of a bounce when the ball reaches the bottom of the stairs.
02

Determine Initial Potential Energy

The initial potential energy of the ball is due to its height at the top of the stairs. This is given by \( PE_{initial} = mgh \), where \( m \) is the mass of the golf ball, \( g = 9.81 \, \text{m/s}^2 \) is gravity, and \( h = 3.00 \, \text{m} \).
03

Consider Energy Conservation in Elastic Collisions

Since the collisions are elastic, the mechanical energy (sum of potential and kinetic energy) of the ball is conserved at every impact. Therefore, when it reaches the bottom, the potential energy at the top will be converted completely into kinetic energy.
04

Calculate Initial Kinetic Energy at the Bottom

Using energy conservation, \( PE_{initial} = KE_{bottom} \), which implies \( mgh = \frac{1}{2} mv^2 \).Cancelling \( m \) from each side and solving for \( v \), we have\( v = \sqrt{2gh} \).
05

Calculate the Bounce Height

Since the ball bounces elastically, it will rise to the same height from kinetic energy conversion; thus,\( h_{bounce} = \frac{v^2}{2g} = h \).This implies the bounce height at the bottom is the same as the original height, 3.00 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is the stored energy of an object due to its position or height. In the context of our problem, the golf ball starts at the top of the stairs with a certain amount of potential energy. This energy is determined by the formula \( PE = mgh \), where:
  • \( m \) is the mass of the golf ball,
  • \( g \) is the acceleration due to gravity, typically \( 9.81 \, \text{m/s}^2 \),
  • \( h \) is the height above the ground, which is \( 3 \, \text{meters} \) in this case.
At the top of the stairs, the ball has maximum potential energy because it is elevated. As it begins to bounce down the steps, this potential energy will be converted into other forms of energy.
Kinetic Energy
Kinetic energy is the energy of motion. When the golf ball starts descending the stairs, its potential energy at the top converts into kinetic energy. The formula for kinetic energy is \( KE = \frac{1}{2} mv^2 \), where:
  • \( m \) is the mass of the ball,
  • \( v \) is the velocity of the ball.
As the ball falls, it speeds up, increasing its kinetic energy due to gravity. At the bottom of the stairs, all the initial potential energy has been transformed into kinetic energy. This means the ball is moving at its fastest, having no potential energy left as it reaches ground level. The conversion process is efficient because the collisions along the stairs are elastic, meaning no energy is lost to other forms like heat or sound. Thus, right before reaching the bottom, the ball moves with a velocity calculated from \( v = \sqrt{2gh} \).
Energy Conservation
Energy conservation is a key principle, especially in elastic collisions. It states that the total energy in a closed system remains constant over time. In our golf ball problem, the potential and kinetic energies are interchangeable forms of mechanical energy.
Since the collisions with the stairs are elastic, the energy isn't lost to external factors. Instead, it just changes form from potential to kinetic and possibly back, depending on the bounce.
  • At the top of the stairs: Maximum potential energy, zero kinetic energy.
  • At the bottom of the stairs: Zero potential energy, maximum kinetic energy.
  • Upon bouncing up: Kinetic energy converts back into potential energy.
This conservation law ensures that the ball can bounce back to its original height after reaching the bottom of the stairs. The kinetic energy at the bottom allows the ball to reach its initial potential energy level as it ascends, resulting in a bounce height of \( 3.00 \, \text{m} \). This is because the total mechanical energy remains unchanged throughout the motion, aligning perfectly with the conservation law.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Batman (mass \(=91 \mathrm{kg}\) ) jumps straight down from a bridge into a boat (mass \(=510 \mathrm{kg}\) ) in which a criminal is fleeing. The velocity of the boat is initially \(+11 \mathrm{m} / \mathrm{s} .\) What is the velocity of the boat after Batman lands in it?

A model rocket is constructed with a motor that can provide a total impulse of \(29.0 \mathrm{N} \cdot\) s. The mass of the rocket is \(0.175 \mathrm{kg} .\) What is the speed that this rocket achieves when launched from rest? Neglect the effects of gravity and air resistance.

A \(46-\mathrm{kg}\) skater is standing still in front of a wall. By pushing against the wall she propels herself backward with a velocity of \(-1.2 \mathrm{m} / \mathrm{s}\). Her hands are in contact with the wall for 0.80 s. Ignore friction and wind resistance. Find the magnitude and direction of the average force she exerts on the wall (which has the same magnitude as, but opposite direction to, the force that the wall applies to her).

The drawing shows a human figure in a sitting position. For purposes of this problem, there are three parts to the figure, and the center of mass of each one is shown in the drawing. These parts are: (1) the torso, neck, and head (total mass \(=41 \mathrm{kg}\) ) with a center of mass located on the \(y\) axis at a point \(0.39 \mathrm{m}\) above the origin, (2) the upper legs \((\mathrm{mass}=17 \mathrm{kg})\) with a center of mass located on the \(x\) axis at a point \(0.17 \mathrm{m}\) to the right of the origin, and (3) the lower legs and feet (total mass \(=9.9 \mathrm{kg}\) ) with a center of mass located \(0.43 \mathrm{m}\) to the right of and \(0.26 \mathrm{m}\) below the origin. Find the \(x\) and \(y\) coordinates of the center of mass of the human figure. Note that the

In a performance test, each of two cars takes \(9.0 \mathrm{s}\) to accelerate from rest to \(27 \mathrm{m} / \mathrm{s}\). Car A has a mass of \(1400 \mathrm{kg},\) and car \(\mathrm{B}\) has a mass of \(1900 \mathrm{kg} .\) Find the net average force that acts on each car during the test.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.