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A husband and wife take turns pulling their child in a wagon along a horizontal sidewalk. Each exerts a constant force and pulls the wagon through the same displacement. They do the same amount of work, but the husband's pulling force is directed \(58^{\circ}\) above the horizontal, and the wife's pulling force is directed \(38^{\circ}\) above the horizontal. The husband pulls with a force whose magnitude is \(67 \mathrm{N}\). What is the magnitude of the pulling force exerted by his wife?

Short Answer

Expert verified
The wife's force is approximately 45.10 N.

Step by step solution

01

Understand Work Done Formula

The work done by a force is given by the formula \( W = F \cdot d \cdot \cos(\theta) \), where \( F \) is the force applied, \( d \) is the displacement, and \( \theta \) is the angle the force makes with the direction of displacement. In this problem, both the husband and wife do the same amount of work on the wagon.
02

Set Up Equation for Husband

For the husband, the work done \( W_h \) is given by \( W_h = 67 \cdot d \cdot \cos(58^\circ) \). Here, \( 67 \mathrm{N} \) is the husband's pulling force, and \( 58^\circ \) is the angle of the force above the horizontal.
03

Set Up Equation for Wife

For the wife, the work done \( W_w \) is given by \( W_w = F_w \cdot d \cdot \cos(38^\circ) \). Here, \( F_w \) is the wife's pulling force, and \( 38^\circ \) is the angle of the force above the horizontal.
04

Equate Work Done by Husband and Wife

Since they do the same amount of work, \( W_h = W_w \). Therefore, \( 67 \cdot d \cdot \cos(58^\circ) = F_w \cdot d \cdot \cos(38^\circ) \). The displacement \( d \) cancels out from both sides of the equation.
05

Solve for Wife's Force

From the equation \( 67 \cdot \cos(58^\circ) = F_w \cdot \cos(38^\circ) \), solve for \( F_w \):\[ F_w = \frac{67 \cdot \cos(58^\circ)}{\cos(38^\circ)} \]Calculating the values, we have:\[ F_w \approx \frac{67 \times 0.5299}{0.7880} \approx 45.10 \mathrm{N} \]
06

Conclude with the Wife's Force Magnitude

After calculations, we find that the magnitude of the wife's pulling force is approximately \( 45.10 \mathrm{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Work Done Formula
When calculating the work done by a force, it's crucial to understand the fundamental relationship between force, displacement, and the angle of application. The formula for work done is represented by:
  • \( W = F \cdot d \cdot \cos(\theta) \).
Here, \( W \) stands for the work done, \( F \) is the magnitude of the force, \( d \) is the displacement in the direction of the force, and \( \theta \) is the angle between the force and the displacement.
In practical terms, work involves transferring energy from one object to another. The work done by the force is effective only in the component of the force that acts in the same line as the displacement. This means, irrespective of how strong the force is, if it's perpendicular to the direction of motion (90 degrees), no work is done.
Understanding this formula is key to analyzing scenarios like in the exercise, where both husband and wife exert forces at different angles yet accomplish the same amount of work.
Effects and Types of Forces
In the context of physics, a force is any external influence that changes the motion of an object. Forces can be complex, often defined by both magnitude and direction, and can be divided into several categories:
  • Contact Forces: Forces that occur when two objects are physically touching each other, like friction, tension, or applied force from pulling a wagon.
  • Non-contact Forces: These occur even when objects are not in contact, like gravity or electromagnetic forces.
The force applied by both husband and wife is a contact force as they pull on a wagon handle. The angle at which these forces are applied impacts their effectiveness in terms of work done on the wagon. The differences in the angles create variations in how much of their force contributes to moving the wagon forward.
Understanding forces and their types helps in predicting how objects behave and what kind of motion or work outcomes we can expect depending on their interaction with other forces.
Influence of the Angle of Force
The angle at which a force is applied plays a major role in determining how effective that force is in doing work. This is why the angle of force is crucial in calculations involving work done.
  • When force is applied parallel to the direction of the displacement (angle \( \theta = 0^\circ \)), \( \cos(\theta) = 1 \), meaning the entire force contributes to moving the object.
  • As the angle increases, the cosine value decreases, reducing the component of force that actually contributes to the work done.
  • At \( 90^\circ \), \( \cos(\theta) = 0 \), meaning no work is done since the force is perpendicular to the displacement.
In our exercise, both individuals pull the wagon at different angles above the horizontal. This affects how much of their total force pulls the wagon.
The husband, pulling at \( 58^\circ \), and the wife, at \( 38^\circ \), implies that the wife’s force has a larger component moving the wagon directly forward due to her smaller angle. However, despite the angle differences, calculations and physics principles help us deduce that they both do the same work.

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Most popular questions from this chapter

At a carnival, you can try to ring a bell by striking a target with a \(9.00-\mathrm{kg}\) hammer. In response, a \(0.400-\mathrm{kg}\) metal piece is sent upward toward the bell, which is \(5.00 \mathrm{m}\) above. Suppose that \(25.0 \%\) of the hammer's kinetic energy is used to do the work of sending the metal piece upward. How fast must the hammer be moving when it strikes the target so that the bell just barely rings?

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