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? 67.0-kg person jumps from rest off a 3.00-m-high tower straight down into the water. Neglect air resistance. She comes to rest \(1.10 \mathrm{m}\) under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Short Answer

Expert verified
The average force exerted by the water is approximately 1792.6 N.

Step by step solution

01

Calculate Potential Energy at the Top

When the person is at the top of the tower, they have gravitational potential energy. Use the formula \( PE = mgh \), where \( m = 67.0 \text{ kg} \), \( g = 9.81 \text{ m/s}^2 \), and \( h = 3.00 \text{ m} \). Thus, the potential energy at the top is: \( PE = 67.0 \times 9.81 \times 3.00 \approx 1971.9 \text{ J} \).
02

Calculate Work Done by Water

After jumping, the diver eventually comes to rest beneath the water surface. The work done on the diver by the water is equal to the change in mechanical energy, which is \( 0 - 1971.9 \text{ J} = -1971.9 \text{ J} \) because all the initial potential energy is used to oppose the diver's motion.
03

Determine Displacement in the Water

The person comes to rest \( 1.10 \text{ m} \) below the water surface. Therefore, the displacement \( s \) while in water is \( 1.10 \text{ m} \).
04

Calculate Average Force Exerted by the Water

Use the work-energy principle where the work done by the force is equal to the force times displacement, \( W = F \cdot s \). Rearranging this equation gives \( F = \frac{W}{s} \). We have \( W = -1971.9 \text{ J} \) and \( s = 1.10 \text{ m} \), so \( F = \frac{-1971.9}{1.10} \approx -1792.6 \text{ N} \). Since force magnitude is positive, the average force is \( 1792.6 \text{ N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is the stored energy an object has due to its position. In this context, when the 67.0-kg diver is standing atop a 3.00-meter-high tower, the object (the diver) holds gravitational potential energy. This energy depends on three factors:
\[ \text{Potential Energy} (PE) = mgh \]
where:
  • \( m \) = mass in kilograms (67.0 kg)
  • \( g \) = acceleration due to gravity (9.81 m/s²)
  • \( h \) = height in meters (3.00 m)
The diver’s potential energy at the top of the tower is calculated by multiplying these values together, resulting in approximately 1971.9 Joules. This energy is what makes it possible for the diver to do work as they fall.
Understanding potential energy helps us see how energy is converted as the diver moves from a high point to rest in the water.
Work-Energy Principle
The work-energy principle is a critical concept in physics, explaining how work done on an object affects its energy state. Initially, the diver has gravitational potential energy at the top of the tower, which is transformed into kinetic energy as the diver falls. Once they hit the water, forces come into play to change this kinetic energy into work.
This principle states the total work done on an object is equal to its change in kinetic energy:
\[ W = \Delta KE \]
In this problem, the total mechanical energy is conserved until nonconservative forces like water resistance act. Thus, the work done by the water is equal to the change in mechanical energy from the top of the tower to rest underwater, approximately \(-1971.9 \text{ J}\) due to the negative sign indicating loss of energy.Understanding this principle is vital, as it gives insight into how forces and energy convert in practical scenarios, like the diver being slowed down by water.
Nonconservative Forces
Nonconservative forces are forces where the work done depends on the path taken. They do not have potential energies associated with them and often cause mechanical energy to dissipate, usually as thermal energy. Examples include friction and air resistance.
In the exercise, the water exerts a nonconservative force on the diver. As the dive enters into the water causing the person to decelerate over a distance of 1.10 meters, the kinetic energy is effectively dissipated.
Using the work-energy principle, we can calculate the average force exerted by the water as needed to halt the diver. Given that the work done \( W \) was \(-1971.9 \text{ J}\), and the displacement \( s \) in the water was 1.10 meters:
\[ F = \frac{W}{s} = \frac{-1971.9}{1.10} \approx -1792.6 \text{ N} \]
To find the magnitude, we take the absolute value, leading to the average force the water exerts on the diver being 1792.6 N. This illustrates how nonconservative forces can significantly influence motion by converting mechanical energy into other energy forms.

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Most popular questions from this chapter

A golf club strikes a 0.045-kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball's motion, has a magnitude of \(6800 \mathrm{N},\) and is in contact with the ball for a distance of \(0.010 \mathrm{m}\). With what speed does the ball leave the club?

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