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The brakes of a truck cause it to slow down by applying a retarding force of \(3.0 \times 10^{3} \mathrm{N}\) to the truck over a distance of \(850 \mathrm{m} .\) What is the work done by this force on the truck? Is the work positive or negative? Why?

Short Answer

Expert verified
The work done is \(-2.55 \times 10^{6} \text{ J}\). It is negative because the force opposes the truck's motion.

Step by step solution

01

Identify known values

Start by identifying the values given in the problem. We have a retarding force of \( F = 3.0 \times 10^{3} \, \text{N} \) and a distance \( d = 850 \, \text{m} \). These are the key values we need to use in the work formula.
02

Recall the formula for work

The work done by a force is given by the formula \( W = F \times d \times \cos(\theta) \), where \( \theta \) is the angle between the force and the direction of motion. In this case, the force is directly opposite to the direction of motion, making \( \theta = 180^\circ \).
03

Calculate cosine of the angle

Since the angle \( \theta \) is \( 180^\circ \), the cosine of \( 180^\circ \) is \( -1 \). This indicates that the force applied is in the opposite direction to the motion.
04

Substitute values into the work formula

Insert the known values into the work formula: \( W = 3.0 \times 10^{3} \, \text{N} \times 850 \, \text{m} \times (-1) \). Calculate the work: \( W = -2.55 \times 10^{6} \, \text{J} \).
05

Interpret the result

The negative sign in the result indicates that the work done by the force on the truck is negative. This tells us that the force is acting in the opposite direction to the truck’s motion, thus decreasing its kinetic energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Retarding Force
The retarding force is a type of force that acts opposite to the direction of an object's motion. It reduces the speed of the object, essentially slowing it down. In our exercise, the brakes of the truck apply this retarding force to stop the truck from moving faster. The key idea here is that a retarding force always does work on an object, but not in the way that other forces might. Instead of increasing energy, it takes energy away from the object's motion.
Retarding forces are commonly seen in everyday situations:
  • Brakes on cars and bicycles, which slow them down or bring them to a complete stop.
  • Frictional forces that oppose natural motion, like a sliding block on a rough surface.
Understanding retarding force is crucial in applications where control over speed is necessary. It is vital in ensuring safety by decreasing kinetic energy, such as stopping a vehicle within a safe distance.
Distance
Distance in physics refers to the measure of how much ground an object has covered during its motion. It's a scalar quantity, meaning it only has magnitude and not direction. In the original exercise, the distance is specified as 850 meters, which is the path over which the retarding force is applied. Knowing the distance is essential for calculating work done, since the formula for work is dependent on how far the object travels under the influence of a force.
When calculating work done by a force:
  • Distance is directly proportional to work. As distance increases, the work done also increases if the force remains constant.
  • If no distance is covered, no work is done.
Understanding the concept of distance helps in analyzing the effectiveness of a force applied to move or stop an object over a certain path.
Angle of Force
When evaluating work, the angle of force, symbolized as \( \theta \), represents the angle between the direction of the force applied and the direction of the object’s motion. It's crucial because it determines how much of the force actually contributes to the work performed in the direction of motion. In the exercise, the angle is \( 180^\circ \), indicating the force is directly opposite to the motion.
This opposition is significant:
  • When \( \theta = 0^\circ \), the force is in the direction of motion, resulting in maximum positive work.
  • When \( \theta = 90^\circ \), no work is done because the force is perpendicular to the motion.
  • When \( \theta = 180^\circ \), like in our exercise, the work done is negative. This is because the force decreases the object's kinetic energy, slowing it down.
Understanding how the angle of force influences work allows students to grasp why certain forces result in positive or negative work depending on their alignment with the motion.

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Most popular questions from this chapter

A small lead ball, attached to a 0.75-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is \(1.5 \mathrm{m}\) above the ground. The ball travels straight upward. In the absence of air resistance, to what maximum height above the ground does the ball rise?

Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. What average power must the winch supply in order to accelerate a 184 -kg ultralight glider from rest to \(26.0 \mathrm{m} / \mathrm{s}\) over a horizontal distance of \(48.0 \mathrm{m} ?\) Assume that friction and air resistance are negligible, and that the tension in the winch cable is constant.

A Sledding Contest. You are in a sledding contest where you start at a height of \(40.0 \mathrm{m}\) above the bottom of a valley and slide down a hill that makes an angle of \(25.0^{\circ}\) with respect to the horizontal. When you reach the valley, you immediately climb a second hill that makes an angle of \(15.0^{\circ}\) with respect to the horizontal. The winner of the contest will be the contestant who travels the greatest distance up the second hill. You must now choose between using your flat-bottomed plastic sled, or your "Blade Runner," which glides on two steel rails. The hill you will ride down is covered with loose snow. However, the hill you will climb on the other side is a popular sledding hill, and is packed hard and is slick. The two sleds perform very differently on the two surfaces, the plastic one performing better on loose snow, and the Blade Runner doing better on hard-packed snow or ice. The performances of each sled can be quantified in terms of their respective coefficients of kinetic friction on the two surfaces. For the plastic sled: \(\mu=0.17\) on loose snow, and \(\mu=0.15\) on packed snow or ice. For the Blade Runner, \(\mu=0.19\) on loose snow, and \(\mu=0.07\) on packed snow or ice. Assuming the two hills are shaped like inclined planes, and neglecting air resistance, (a) how far does each sled make it up the second hill before stopping? (b) Assuming the total mass of the sled plus rider is \(55.0 \mathrm{kg}\) in both cases, how much work is done by nonconservative forces (over the total trip) in each case?

The cheetah is one of the fastest-accelerating animals, because it can go from rest to \(27 \mathrm{m} / \mathrm{s}\) (about \(60 \mathrm{mi} / \mathrm{h}\) ) in \(4.0 \mathrm{s}\). If its mass is \(110 \mathrm{kg}\), determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in (a) watts and (b) horsepower.

A 63-kg skier coasts up a snow-covered hill that makes an angle of \(25^{\circ}\) with the horizontal. The initial speed of the skier is \(6.6 \mathrm{m} / \mathrm{s}\). After coasting \(1.9 \mathrm{m}\) up the slope, the skier has a speed of \(4.4 \mathrm{m} / \mathrm{s}\). (a) Find the work done by the kinetic frictional force that acts on the skis. (b) What is the magnitude of the kinetic frictional force?

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