/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Go A water-skier is being pulled... [FREE SOLUTION] | 91Ó°ÊÓ

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Go A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 70.3 -kg water- skier has an initial speed of \(6.10 \mathrm{m} / \mathrm{s}\). Later, the speed increases to \(11.3 \mathrm{m} / \mathrm{s} .\) Determine the work done by the net external force acting on the skier.

Short Answer

Expert verified
The work done is 3183.8 J.

Step by step solution

01

Understand the Problem

We need to find the work done on the skier given her change in speed. To do this, we use the concept of kinetic energy and the work-energy principle.
02

Apply the Work-Energy Principle

The work-energy principle states that the work done by the net external force on an object is equal to the change in kinetic energy of the object. Mathematically, this can be written as:\[ W = \Delta KE = KE_f - KE_i \]where \( KE_i \) is the initial kinetic energy and \( KE_f \) is the final kinetic energy.
03

Calculate Initial Kinetic Energy

The initial kinetic energy \( KE_i \) can be calculated using the formula:\[ KE_i = \frac{1}{2} m v_i^2 \]Substitute \( m = 70.3 \text{ kg} \) and \( v_i = 6.10 \text{ m/s} \) to find:\[ KE_i = \frac{1}{2} \times 70.3 \times (6.10)^2 = 1304.835 \text{ J} \]
04

Calculate Final Kinetic Energy

The final kinetic energy \( KE_f \) is calculated similarly using the final velocity:\[ KE_f = \frac{1}{2} m v_f^2 \]Substitute \( m = 70.3 \text{ kg} \) and \( v_f = 11.3 \text{ m/s} \) to find:\[ KE_f = \frac{1}{2} \times 70.3 \times (11.3)^2 = 4488.635 \text{ J} \]
05

Calculate the Work Done

Now, calculate the work done \( W \) using the change in kinetic energy:\[ W = KE_f - KE_i = 4488.635 - 1304.835 = 3183.8 \text{ J} \]
06

Final Step: Conclusion

The work done by the net external force acting on the skier is \( 3183.8 \text{ J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Kinetic Energy
Kinetic energy is a crucial concept in physics that refers to the energy that an object possesses due to its motion. The formula to calculate kinetic energy (KE) is: \[ KE = \frac{1}{2} mv^2 \] where:
  • \(m\) is the mass of the object in kilograms,
  • \(v\) is the velocity of the object in meters per second.
In our exercise, the water-skier has both initial and final speeds. Therefore, we need to calculate both the initial kinetic energy \(KE_i\) and the final kinetic energy \(KE_f\). This calculation helps in understanding how much energy is gained or lost by the skier as her speed changes. By substituting the skier's mass and velocities into the kinetic energy formula, we first find the initial state kinetic energy. Then, we do the same for the final state to understand how the skier's energy has transformed. These are preliminary calculations before using the work-energy principle.
The Concept of Work Done
Work done is another foundational idea in physics, directly connected to energy changes. In this context, work done refers to the energy transferred by the force to cause the skier's acceleration. The work done by a force is given by the equation: \[ W = F \cdot d \cdot \cos(\theta) \] where:
  • \(F\) is the force applied,
  • \(d\) is the distance over which the force is applied,
  • \(\theta\) is the angle between the force and displacement directions.
However, when using the work-energy principle, we focus on the change in kinetic energy to determine the work done. For the skier, this can be found using: \[ W = KE_f - KE_i \] This formula indicates that the work done on the skier by the net external force is essentially the difference in her kinetic energy from start to finish. It translates the forces acting upon her into a measurable energy change, which explains her acceleration.
Role of Net External Force
Net external force is the key player in changing the state of motion of an object and is defined as the overall force resulting from all the external forces acting on an object. In physics, it's what causes acceleration, which is famously stated in Newton's second law: \[ F_{net} = ma \] where:
  • \(F_{net}\) is the net external force,
  • \(m\) is the mass of the object,
  • \(a\) is the acceleration.
In the water-skier scenario, the net external force results from the boat's pull through the tow rope. This force is responsible for the skier's acceleration from an initial speed to a higher speed. By calculating the work done using the change in kinetic energy, we're effectively determining how much energy the net external force contributes to make the skier go faster. Understanding the net external force not only helps us compute work but also deepens our grasp of the dynamics involved in motion and energy transfer in real-world situations.

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Most popular questions from this chapter

When an \(81.0-\mathrm{kg}\) adult uses a spiral staircase to climb to the second floor of his house, his gravitational potential energy increases by \(2.00 \times 10^{3}\) J. By how much does the potential energy of an \(18.0-\mathrm{kg}\) child increase when the child climbs a normal staircase to the second floor?

A person pulls a toboggan for a distance of \(35.0 \mathrm{m}\) along the snow with a rope directed \(25.0^{\circ}\) above the snow. The tension in the rope is \(94.0 \mathrm{N} .\) (a) How much work is done on the toboggan by the tension force? (b) How much work is done if the same tension is directed parallel to the snow?

A basketball player makes a jump shot. The \(0.600-\mathrm{kg}\) ball is released at a height of \(2.00 \mathrm{m}\) above the floor with a speed of \(7.20 \mathrm{m} / \mathrm{s}\). The ball goes through the net \(3.10 \mathrm{m}\) above the floor at a speed of \(4.20 \mathrm{m} / \mathrm{s}\). What is the work done on the ball by air resistance, a nonconservative force?

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of \(4.5 \times 10^{4} \mathrm{kg},\) and the force causes its speed to change from 7100 to \(5500 \mathrm{m} / \mathrm{s}\) (a) What is the work done by the force? (b) If the asteroid slows down over a distance of \(1.8 \times 10^{6} \mathrm{m},\) determine the magnitude of the force.

A 47.0-g golf ball is driven from the tee with an initial speed of \(52.0 \mathrm{m} / \mathrm{s}\) and rises to a height of \(24.6 \mathrm{m}\). (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is \(8.0 \mathrm{m}\) below its highest point?

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