/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Go A water-skier is being pulled... [FREE SOLUTION] | 91Ó°ÊÓ

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Go A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 70.3 -kg water- skier has an initial speed of \(6.10 \mathrm{m} / \mathrm{s}\). Later, the speed increases to \(11.3 \mathrm{m} / \mathrm{s} .\) Determine the work done by the net external force acting on the skier.

Short Answer

Expert verified
The work done is 3183.8 J.

Step by step solution

01

Understand the Problem

We need to find the work done on the skier given her change in speed. To do this, we use the concept of kinetic energy and the work-energy principle.
02

Apply the Work-Energy Principle

The work-energy principle states that the work done by the net external force on an object is equal to the change in kinetic energy of the object. Mathematically, this can be written as:\[ W = \Delta KE = KE_f - KE_i \]where \( KE_i \) is the initial kinetic energy and \( KE_f \) is the final kinetic energy.
03

Calculate Initial Kinetic Energy

The initial kinetic energy \( KE_i \) can be calculated using the formula:\[ KE_i = \frac{1}{2} m v_i^2 \]Substitute \( m = 70.3 \text{ kg} \) and \( v_i = 6.10 \text{ m/s} \) to find:\[ KE_i = \frac{1}{2} \times 70.3 \times (6.10)^2 = 1304.835 \text{ J} \]
04

Calculate Final Kinetic Energy

The final kinetic energy \( KE_f \) is calculated similarly using the final velocity:\[ KE_f = \frac{1}{2} m v_f^2 \]Substitute \( m = 70.3 \text{ kg} \) and \( v_f = 11.3 \text{ m/s} \) to find:\[ KE_f = \frac{1}{2} \times 70.3 \times (11.3)^2 = 4488.635 \text{ J} \]
05

Calculate the Work Done

Now, calculate the work done \( W \) using the change in kinetic energy:\[ W = KE_f - KE_i = 4488.635 - 1304.835 = 3183.8 \text{ J} \]
06

Final Step: Conclusion

The work done by the net external force acting on the skier is \( 3183.8 \text{ J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Kinetic Energy
Kinetic energy is a crucial concept in physics that refers to the energy that an object possesses due to its motion. The formula to calculate kinetic energy (KE) is: \[ KE = \frac{1}{2} mv^2 \] where:
  • \(m\) is the mass of the object in kilograms,
  • \(v\) is the velocity of the object in meters per second.
In our exercise, the water-skier has both initial and final speeds. Therefore, we need to calculate both the initial kinetic energy \(KE_i\) and the final kinetic energy \(KE_f\). This calculation helps in understanding how much energy is gained or lost by the skier as her speed changes. By substituting the skier's mass and velocities into the kinetic energy formula, we first find the initial state kinetic energy. Then, we do the same for the final state to understand how the skier's energy has transformed. These are preliminary calculations before using the work-energy principle.
The Concept of Work Done
Work done is another foundational idea in physics, directly connected to energy changes. In this context, work done refers to the energy transferred by the force to cause the skier's acceleration. The work done by a force is given by the equation: \[ W = F \cdot d \cdot \cos(\theta) \] where:
  • \(F\) is the force applied,
  • \(d\) is the distance over which the force is applied,
  • \(\theta\) is the angle between the force and displacement directions.
However, when using the work-energy principle, we focus on the change in kinetic energy to determine the work done. For the skier, this can be found using: \[ W = KE_f - KE_i \] This formula indicates that the work done on the skier by the net external force is essentially the difference in her kinetic energy from start to finish. It translates the forces acting upon her into a measurable energy change, which explains her acceleration.
Role of Net External Force
Net external force is the key player in changing the state of motion of an object and is defined as the overall force resulting from all the external forces acting on an object. In physics, it's what causes acceleration, which is famously stated in Newton's second law: \[ F_{net} = ma \] where:
  • \(F_{net}\) is the net external force,
  • \(m\) is the mass of the object,
  • \(a\) is the acceleration.
In the water-skier scenario, the net external force results from the boat's pull through the tow rope. This force is responsible for the skier's acceleration from an initial speed to a higher speed. By calculating the work done using the change in kinetic energy, we're effectively determining how much energy the net external force contributes to make the skier go faster. Understanding the net external force not only helps us compute work but also deepens our grasp of the dynamics involved in motion and energy transfer in real-world situations.

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Most popular questions from this chapter

A slingshot fires a pebble from the top of a building at a speed of \(14.0 \mathrm{m} / \mathrm{s} .\) The building is \(31.0 \mathrm{m}\) tall. Ignoring air resistance, find the speed with which the pebble strikes the ground when the pebble is fired (a) horizontally, (b) vertically straight up, and (c) vertically straight down.

A 75.0-kg skier rides a 2830-m-long lift to the top of a mountain. The lift makes an angle of \(14.6^{\circ}\) with the horizontal. What is the change in the skier's gravitational potential energy?

A 0.60-kg basketball is dropped out of a window that is 6.1 m above the ground. The ball is caught by a person whose hands are \(1.5 \mathrm{m}\) above the ground. (a) How much work is done on the ball by its weight? What is the gravitational potential energy of the basketball, relative to the ground, when it is (b) released and (c) caught? (d) How is the change \(\left(\mathrm{PE}_{\mathrm{f}}-\mathrm{PE}_{0}\right)\) in the ball's gravitational potential energy related to the work done by its weight?

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force) acts on her. The student has a mass of \(83.0 \mathrm{kg}\), and the height of the water slide is \(11.8 \mathrm{m}\). If the kinetic frictional force does \(-6.50 \times 10^{3} \mathrm{J}\) of work, how fast is the student going at the bottom of the slide?

A basketball player makes a jump shot. The \(0.600-\mathrm{kg}\) ball is released at a height of \(2.00 \mathrm{m}\) above the floor with a speed of \(7.20 \mathrm{m} / \mathrm{s}\). The ball goes through the net \(3.10 \mathrm{m}\) above the floor at a speed of \(4.20 \mathrm{m} / \mathrm{s}\). What is the work done on the ball by air resistance, a nonconservative force?

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