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A rescue helicopter is lifting a man (weight = 822 N) from a capsized boat by means of a cable and harness. (a) What is the tension in the cable when the man is given an initial upward acceleration of \(1.10 \mathrm{m} / \mathrm{s}^{2} ?\) (b) What is the tension during the remainder of the rescue when he is pulled upward at a constant velocity?

Short Answer

Expert verified
Tension is 909.36 N initially and 822 N at constant velocity.

Step by step solution

01

Understand the Problem

The problem involves calculating the tension in a cable when a man is being lifted by a helicopter. There are two scenarios: the man is given an initial upward acceleration and then he is moved with a constant velocity. Each requires a separate calculation of tension.
02

Identify the Given Values

The man's weight is given as 822 N. His initial upward acceleration is 1.10 m/s². We need to convert his weight to mass using the relation \( F = mg \). Since \( F = 822 \text{ N} \), using \( g = 9.81 \text{ m/s}^2 \), the mass \( m \) is calculated as \( m = \frac{822}{9.81} \).
03

Calculate the Mass of the Man

Using the formula \( m = \frac{822}{9.81} \), we find:\[ m = 83.78 \text{ kg} \]
04

Calculate Tension for Initial Upward Acceleration

When the man is accelerating upwards, the tension in the cable is the sum of the gravitational force and the force due to acceleration. This is calculated using\[ T_1 = m(g + a) \]Substitute \( m = 83.78 \text{ kg} \), \( g = 9.81 \text{ m/s}^2 \), and \( a = 1.10 \text{ m/s}^2 \).
05

Solve for Tension during Initial Acceleration

Plug the values into the equation:\[ T_1 = 83.78(9.81 + 1.10) = 909.36 \text{ N} \]
06

Calculate Tension for Constant Velocity

When the man is moving with constant velocity, his acceleration is zero. Therefore, tension \( T_2 \) equals the gravitational force:\[ T_2 = mg = 822 \text{ N} \]
07

Summarize the Results

We found that when the man is accelerating upward, the tension is \( 909.36 \text{ N} \) and when he moves at a constant velocity, the tension is \( 822 \text{ N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is a fundamental principle in physics. It explains how the motion of an object changes when a force is applied to it. Mathematically, it is expressed as \( F = ma \), where
  • \( F \) represents the total force acting on an object,
  • \( m \) is the object's mass,
  • \( a \) is the acceleration produced due to the force.
In the context of lifting a man with a helicopter, this law helps calculate the tension in the cable. When the man is being lifted with an acceleration, the forces involved include both the gravitational force pulling down and the force needed to accelerate him upwards. Hence, tension is calculated by adding these forces, shown in \[ T = m(g + a) \]where
  • \( g \) is the acceleration due to gravity, which is \( 9.81 \, \text{m/s}^2 \), and
  • \( a \) is the additional acceleration provided by the helicopter.
The understanding of this law allows us to determine how forces and motion relate in various situations.
Gravitational Force
Gravitational force is the force of attraction between any two masses. On Earth, it gives objects weight and is directed towards the Earth's center. For any object near Earth's surface, this force is calculated by the formula:\[ F_g = mg \]where
  • \( F_g \) is the gravitational force (or weight),
  • \( m \) is the mass of the object,
  • \( g \) is the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \).
In the exercise, the man's weight is determined by the gravitational force acting on him, which is \( 822 \, \text{N} \). By knowing this, we can also calculate the man's mass, oriented from the equation \( m = \frac{F_g}{g} \). This calculation is crucial for further determining the tension in the cable, especially when the man is at rest or moving at a constant velocity.
Constant Velocity
Constant velocity implies that an object is moving with uniform speed in a straight line. This is an interesting concept because when velocity is constant, it means no net external force is acting on the object. In terms of tension in the helicopter cable during the rescue, constant velocity means the upward force (or tension) only balances the gravitational force. There is no additional needed force to change the velocity or speed up the man, as there is no acceleration.Thus, in the exercise:
  • The tension in the cable is calculated simply as the weight of the man, \( 822 \, \text{N} \),
  • Reflects that the upward force perfectly matches the downward gravitational pull.
This balance is a perfect illustration of equilibrium in physics, as per Newton's First Law, stating if there is no net force on an object, it will maintain its state of motion, either at rest or in uniform movement.
Mass and Weight Conversion
Mass and weight are often confused, yet they are distinct concepts. Mass is the amount of matter in an object, measured in kilograms (kg), while weight is the force of gravity acting on that mass, measured in newtons (N). To convert weight to mass, you use the relation\[ m = \frac{F}{g} \]where
  • \( m \) is mass,
  • \( F \) is weight or gravitational force,
  • \( g \) is acceleration due to gravity.
For the man in the exercise, we convert his weight to mass using \( g = 9.81 \, \text{m/s}^2 \), yielding approximately \( 83.78 \, \text{kg} \). This conversion is essential for determining the force calculations involved, such as the additional tension when there is an upward acceleration during the rescue. By understanding this concept deeply, one can easily transition between the two measures depending on what information is required in a physics problem.

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Most popular questions from this chapter

The space probe Deep Space 1 was launched on October 24, 1998. Its mass was 474 kg. The goal of the mission was to test a new kind of engine called an ion propulsion drive. This engine generated only a weak thrust, but it could do so over long periods of time with the consumption of only small amounts of fuel. The mission was spectacularly successful. At a thrust of 56 mN how many days were required for the probe to attain a velocity of 805 m/s (1800 mi/h), assuming that the probe started from rest and that the mass remained nearly constant?

The figure shows two forces, \(\overrightarrow{\mathbf{F}}_{1}=+3000 \mathrm{N}\) and \(\overrightarrow{\mathbf{F}}_{2}=+5000 \mathrm{N},\) acting on a spacecraft; the plus signs indicate that the forces are directed along the \(+x\) axis. A third force \(\overrightarrow{\mathbf{F}}_{3}\) also acts on the spacecraft but is not shown in the drawing. Concepts: (i) Suppose the spacecraft were stationary. What would be the direction of \(\overrightarrow{\mathbf{F}}_{3} ?\) (ii) When the spacecraft is moving at a constant velocity of \(+850 \mathrm{m} / \mathrm{s},\) what is the direction of \(\overrightarrow{\mathbf{F}}_{3} ?\) Calculations: Find the direction and magnitude of \(\overrightarrow{\mathbf{F}}_{3}\).

You are in a helicopter towing a 129-kg laser detector that is mapping out the thickness of the Brunt Ice Shelf along the coast of Antarctica. The original cable used to suspend the detector was damaged and replaced by a lighter one with a maximum tension rating of 310 pounds, not much more than the weight of the detector. The replacement cable would work without question in the case that the detector and helicopter were not accelerating. However, some acceleration of the helicopter is inevitable. In order to monitor the tension force on the cable to make sure the maximum is not exceeded (and therefore to not lose the very expensive detector) you calculate the maximum angle the cable can make with the vertical without the cable exceeding the tension limit. (a) Assuming straight and level flight of the helicopter, what is that maximum angle? (b) What is the corresponding acceleration? (c) Your colleague wants to add a 10-kg infrared camera to the detector. What is the maximum allowable angle now?

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