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Three forces act on a moving object. One force has a magnitude of 80.0 N and is directed due north. Another has a magnitude of 60.0 N and is directed due west. What must be the magnitude and direction of the third force, such that the object continues to move with a constant velocity?

Short Answer

Expert verified
The third force has a magnitude of 100.0 N and is directed 53.1 degrees south of east.

Step by step solution

01

Understanding Equilibrium

The object continues to move with a constant velocity because of Newton's First Law, which tells us that the net force acting on the object must be zero. This means the three forces acting on the object must balance each other out.
02

Analyzing Two Forces

We have two known forces: one force, \( \overrightarrow{F_1} \), is 80.0 N to the north, and the other force, \( \overrightarrow{F_2} \), is 60.0 N to the west. These can be expressed in vector terms as \( \overrightarrow{F_1} = 80.0\,N \hat{j} \) (north) and \( \overrightarrow{F_2} = -60.0\,N \hat{i} \) (west).
03

Setting Up the Third Force

To maintain equilibrium, the third force, \( \overrightarrow{F_3} \), must counteract the effects of \( \overrightarrow{F_1} \) and \( \overrightarrow{F_2} \). Therefore, \( \overrightarrow{F_3} \) needs to have a component of 60.0 N east and 80.0 N south to neutralize the other forces. This implies \( \overrightarrow{F_3} = 60.0\,N \hat{i} - 80.0\,N \hat{j} \).
04

Calculating the Magnitude of the Third Force

The magnitude of \( \overrightarrow{F_3} \) is given by \( |\overrightarrow{F_3}| = \sqrt{(60.0)^2 + (80.0)^2} \). Simplifying this, we get \( |\overrightarrow{F_3}| = \sqrt{3600 + 6400} \), resulting in \( |\overrightarrow{F_3}| = 100.0\,N \).
05

Finding the Direction of the Third Force

To determine the direction of \( \overrightarrow{F_3} \), we can use tangent as \( \tan(\theta) = \frac{80}{60} = \frac{4}{3} \). Solving for \( \theta \), use \( \theta = \tan^{-1}\left(\frac{4}{3}\right) \), which gives \( \theta \approx 53.1^\circ \). Thus, \( \overrightarrow{F_3} \) is directed 53.1 degrees south of east.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium
Equilibrium occurs when the net force acting on an object is zero, meaning all forces balance each other out. According to Newton's First Law of Motion, an object at rest remains at rest, and an object in motion remains in motion at a constant velocity unless acted upon by an unbalanced force. In the given problem, the object continues to move at a constant velocity, which indicates that the forces acting on it are in equilibrium.

Think of equilibrium like a tug-of-war game, where both sides pull with equal strength. If neither side moves, the system is balanced or in equilibrium. For the moving object, even though it's in motion, the forces applied to it are perfectly balanced along the north, west, south, and east directions, resulting in a zero net force. Understanding equilibrium is essential when dealing with motion, as it helps us identify scenarios where forces are balanced, thus allowing the object to maintain constant velocity.
Vector Addition
Vector addition is a mathematical way to combine forces that have both magnitude (strength) and direction (way they are pointing). In this exercise, we have two vectors: one pointing north with 80.0 N and another pointing west with 60.0 N. These vectors tell us exactly how much force is acting in specific directions.

When adding vectors, think about walking in a straight line: first go north, then west. You don't walk diagonally unless the directions are combined. Vector addition uses these directions to form a triangle, with the third side representing the resultant vector, which is the combination of both forces. Using vector addition allows us to find the single vector that can replace multiple vectors and will produce the same effect on an object.
  • Use the tip-to-tail method to combine vectors.
  • The resultant vector (or net force) in equilibrium should sum to zero.
  • Both the size and direction of each vector matter.
Force Magnitude and Direction
To maintain an object's constant movement, understanding force magnitude and direction is crucial. The magnitude of a force is its strength, while its direction indicates the way it pushes or pulls the object. For the third force in our problem, its magnitude was calculated using Pythagoras’ theorem, as it's the diagonal of the right triangle formed by the north and west forces.

The calculations show that the third force must have a magnitude of 100.0 N. Its direction is determined by resolving the angle using the tangent function, giving an angle 53.1 degrees south of east.
  • The magnitude is found using the formula \( \text{Magnitude} = \sqrt{(\text{north force})^2 + (\text{west force})^2} \).
  • The direction involves finding the angle, \( \theta \), using \( \tan(\theta) = \frac{\text{opposite component}}{\text{adjacent component}} \).
  • A proper understanding of both magnitude and direction helps predict how and where an object will move.

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Most popular questions from this chapter

Synchronous communications satellites are placed in a circular orbit that is \(3.59 \times 10^{7} \mathrm{m}\) above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

A student presses a book between his hands, as the drawing indicates. The forces that he exerts on the front and back covers of the book are perpendicular to the book and are horizontal. The book weighs 31 N. The coefficient of static friction between his hands and the book is 0.40. To keep the book from falling, what is the magnitude of the minimum pressing force that each hand must exert?

Consult Multiple-Concept Example 10 for insight into solving this type of problem. A box is sliding up an incline that makes an angle of \(15.0^{\circ}\) with respect to the horizontal. The coefficient of kinetic friction between the box and the surface of the incline is \(0.180 .\) The initial speed of the box at the bottom of the incline is \(1.50 \mathrm{m} / \mathrm{s}\). How far does the box travel along the incline before coming to rest?

A person is trying to judge whether a picture (mass \(=1.10 \mathrm{kg}\) ) is properly positioned by temporarily pressing it against a wall. The pressing force is perpendicular to the wall. The coefficient of static friction between the picture and the wall is \(0.660 .\) What is the minimum amount of pressing force that must be used?

A \(325-\mathrm{kg}\) boat is sailing \(15.0^{\circ}\) north of east at a speed of \(2.00 \mathrm{m} / \mathrm{s}\). Thirty seconds later, it is sailing \(35.0^{\circ}\) north of east at a speed of \(4.00 \mathrm{m} / \mathrm{s}\). During this time, three forces act on the boat: a \(31.0-\mathrm{N}\) force directed \(15.0^{\circ}\) north of east (due to an auxiliary engine), a \(23.0-\mathrm{N}\) force directed \(15.0^{\circ}\) south of west (resistance due to the water), and \(\overrightarrow{\mathbf{F}}_{\mathbf{w}}\) (due to the wind). Find the magnitude and direction of the force \(\overrightarrow{\mathbf{F}}_{\mathbf{w}} .\) Express the direction as an angle with respect to due east.

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