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The electron in a certain hydrogen atom has an angular momentum of \(8.948 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} .\) What is the largest possible magnitude for the \(z\) component of the angular momentum of this electron? For accuracy, use \(h=6.626 \times 10^{-34} \mathrm{J} \cdot \mathrm{s}\)

Short Answer

Expert verified
The largest possible z-component of the angular momentum is approximately 8.432 x 10^-34 J·s.

Step by step solution

01

Understand the Meaning of Angular Momentum

Angular momentum in quantum mechanics is quantized. The electron's angular momentum is given by \( L = \sqrt{l(l+1)} \hbar \), where \( \hbar = \frac{h}{2\pi} \) is the reduced Planck's constant and \( l \) is the azimuthal quantum number.
02

Calculate Reduced Planck's Constant

Given \( h = 6.626 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \), calculate \( \hbar = \frac{6.626 \times 10^{-34}}{2 \pi} \approx 1.054 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \).
03

Solve for Azimuthal Quantum Number (l)

We know the total angular momentum is \( L = \sqrt{l(l+1)} \hbar \). Plug in the values: \( 8.948 \times 10^{-34} = \sqrt{l(l+1)} \times 1.054 \times 10^{-34} \). Solve this equation for \( l \).
04

Calculate Azimuthal Quantum Number (l)

From the equation \( 8.493 \approx \sqrt{l(l+1)} \), square both sides to get \( 8.493^2 \approx l(l+1) \). Compute \( 72.14 \approx l(l+1) \). Try integer values of \( l \). You'll find that \( l = 8 \) satisfies this equation closely.
05

Determine the Maximum Z-Component of Angular Momentum

The z-component of the angular momentum is quantized as \( L_z = m_l \hbar \), where \( m_l \) ranges from \(-l\) to \(l\). The largest \( L_z \) is when \( m_l = l \). Thus, the largest \( L_z = l \hbar = 8 \times 1.054 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \approx 8.432 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Atom
The hydrogen atom is a fascinating and fundamental concept in physics and chemistry. It consists of a single proton as its nucleus, with an electron orbiting this nucleus. This seemingly simple structure serves as the building block for understanding more complex atoms and molecular chemistry. The electron in a hydrogen atom occupies quantum states that are defined by distinct quantum numbers. These quantum numbers dictate the electron's energy, angular momentum, and position within the atom.
  • The principal quantum number (\( n \)) indicates the energy level of the electron.
  • The azimuthal or angular quantum number (\( l \)) describes the shape of the orbital.
  • Other quantum numbers further refine these properties.
This quantized system gives rise to the emission and absorption spectra characteristic of hydrogen. Each spectral line corresponds to a transition between different quantum states, which was famously explained by Niels Bohr. Ultimately, the hydrogen atom's study paved the way for modern quantum mechanics by revealing how discrete energy levels can exist within an atom.
Azimuthal Quantum Number
The azimuthal quantum number, often denoted as \( l \), is crucial in understanding the angular momentum of electrons in an atom. It is also known as the angular momentum quantum number and defines the shape of the electron's orbital.
  • The values of \( l \) range from 0 to \( n-1 \), where \( n \) is the principal quantum number.
  • Each value corresponds to a particular type of orbital: \( s \), \( p \), \( d \), \( f \), and so on.
  • For example, if \( n = 3 \), \( l \) can be 0, 1, or 2, corresponding to \( s \), \( p \), and \( d \) orbitals, respectively.
In quantum mechanics, the azimuthal quantum number directly affects the permitted angular momentum values. The total angular momentum \( L \) of an electron is expressed using these quantum numbers: \( L = \sqrt{l(l+1)} \hbar \), where \( \hbar \) is the reduced Planck's constant. Consequently, \( l \) not only informs us about the electron's orbital shape but also its contribution to the atom's angular momentum.
Reduced Planck's Constant
The reduced Planck's constant, represented as \( \hbar \), is a fundamental constant in quantum mechanics. It serves as a scale factor in the quantization of angular momentum, bridging the gap between classical and quantum descriptions.
  • Mathematically, \( \hbar = \frac{h}{2\pi} \), where \( h \) is the Planck's constant.
  • This constant is approximately \( 1.054 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \).
  • It is crucial in defining the quantized nature of angular momentum; for example, in electron orbitals around an atom.
In quantum mechanics, \( \hbar \) is instrumental in calculations involving angular momentum and energy of atomic and subatomic particles. It indicates that physical quantities at the quantum level, such as angular momentum, are not continuous but rather exist in discrete quanta. This quantization is a cornerstone of quantum theory, distinguishing it from classical physics.

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Most popular questions from this chapter

The electron in a hydrogen atom is in the first excited state, when the electron acquires an additional \(2.86 \mathrm{eV}\) of energy. What is the quantum number \(n\) of the state into which the electron moves?

In the ground state, the outermost shell \((n=1)\) of helium (He) is filled with electrons, as is the outermost shell \((n=2)\) of neon (Ne). The full outermost shells of these two elements distinguish them as the first two socalled "noble gases." Suppose that the spin quantum number \(m_{s}\) had three possible values, rather than two. If that were the case, which elements would be (a) the first and (b) the second noble gases? Assume that the possible values for the other three quantum numbers are unchanged, and that the Pauli exclusion principle still applies.

A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is \(514 \mathrm{nm},\) and the power is 1.5 W. During surgery, the laser beam is turned on for 0.050 s. During this time, how many photons are emitted by the laser?

A hydrogen atom emits a photon that has momentum with a magnitude of \(5.452 \times 10^{-27} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} .\) This photon is emitted because the electron in the atom falls from a higher energy level into the \(n=1\) level. What is the quantum number of the level from which the electron falls? Use a value of \(6.626 \times 10^{-34} \mathrm{J} \cdot\) s for Planck's constant.

Two of the three electrons in a lithium atom have quantum numbers of \(n=1, \ell=0, m_{c}=0, m_{s}=+\frac{1}{2}\) and \(n=1, \ell=0, m_{c}=0, m_{3}=-\frac{1}{2} .\) What quantum numbers can the third electron have if the atom is in (a) its ground state and (b) its first excited state?

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