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On a spacecraft, two engines are turned on for 684 s at a moment when the velocity of the craft has \(x\) and \(y\) components of \(v_{0 x}=4370 \mathrm{m} / \mathrm{s}\) and \(v_{0 y}=6280 \mathrm{m} / \mathrm{s} .\) While the engines are firing, the craft undergoes a displacement that has components of \(x=4.11 \times 10^{6} \mathrm{m}\) and \(y=6.07 \times 10^{6} \mathrm{m} .\) Find the \(x\) and \(y\) components of the craft's acceleration.

Short Answer

Expert verified
The x-acceleration is approximately 4.76 m/s², and the y-acceleration is approximately 7.62 m/s².

Step by step solution

01

Understand the Problem

We need to determine the acceleration components, given the initial velocity components and displacement over a specific time. The equations of motion for constant acceleration can be used here.
02

Recall the Equation of Motion

The equation that relates displacement, initial velocity, time, and acceleration is:\[ s = v_0 t + \frac{1}{2} a t^2 \] \(s\) is displacement, \(v_0\) is initial velocity, \(a\) is acceleration, and \(t\) is time.
03

Apply Equation to x-component

Given \(x = 4.11 \times 10^{6} \text{ m}\), \(v_{0x} = 4370 \text{ m/s}\), and \(t = 684 \text{ s}\), the equation for the x-direction is:\[ 4.11 \times 10^{6} = 4370 \times 684 + \frac{1}{2} a_x (684)^2 \]Solve for \(a_x\).
04

Solve for x-acceleration

Rearrange and calculate:\[ 4.11 \times 10^{6} - 4370 \times 684 = \frac{1}{2} a_x (684)^2 \]\[ 4.11 \times 10^{6} - 2,993880 = \frac{1}{2} a_x (468816) \]\[ 1,116,120 = \frac{1}{2} a_x (468816) \]\[ a_x = \frac{2 \cdot 1,116,120}{468816} \]\[ a_x \approx 4.76 \text{ m/s}^2 \]
05

Apply Equation to y-component

Given \(y = 6.07 \times 10^{6} \text{ m}\), \(v_{0y} = 6280 \text{ m/s}\), and \(t = 684 \text{ s}\), use:\[ 6.07 \times 10^{6} = 6280 \times 684 + \frac{1}{2} a_y (684)^2 \]Solve for \(a_y\).
06

Solve for y-acceleration

Rearrange and calculate:\[ 6.07 \times 10^{6} - 6280 \times 684 = \frac{1}{2} a_y (684)^2 \]\[ 6.07 \times 10^{6} - 4283520 = \frac{1}{2} a_y (468816) \]\[ 1,786,480 = \frac{1}{2} a_y (468816) \]\[ a_y = \frac{2 \cdot 1,786,480}{468816} \]\[ a_y \approx 7.62 \text{ m/s}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

constant acceleration
In physics, constant acceleration refers to a scenario where the rate of change of velocity is the same across a given period of time. This implies a uniform increase or decrease in speed every second. Constant acceleration simplifies the analysis of motion since it allows us to use specific kinematic equations to predict future motion. For example, if a spacecraft is accelerating at a constant rate, its velocity and trajectory are predictable using these equations.
When analyzing two-dimensional motion, constant acceleration becomes crucial as it allows us to separate the motion into independent orthogonal components, usually the x and y axes. Each component behaves as if in one-dimensional motion, allowing equations of motion for one dimension to be applied to each axis individually. This separateness makes calculations much easier, as seen in the example where separate equations determined the respective x and y components of acceleration.
equations of motion
Equations of motion form the backbone of mechanics for objects moving under constant acceleration. They provide mathematical relationships that connect displacement, initial velocity, final velocity, time, and acceleration.
For a given displacement ( s ), initial velocity ( v_0 ), time ( t ), and acceleration ( a ), the most commonly used equation of motion is:
  • \[ s = v_0 t + \frac{1}{2} a t^2 \]
This equation is pivotal when solving problems involving constant acceleration. By rearranging it, you can solve for any variable if the others are known.
In the context of a spacecraft, this equation was used to refine the understanding of its motion over time. By resolving the motion into x and y components and applying this formula to each, we could effectively deduce how the spacecraft's velocity was altered in each direction due to acceleration. This approach simplifies the problem, treating it as a series of smaller, manageable one-dimensional tasks.
spacecraft velocity
Spacecraft velocity is crucial in analyzing and controlling the trajectory of space missions. This velocity has both magnitude and direction, making it a vector quantity that can be broken into components, usually along x and y axes for simplicity. On account of this, we can employ kinematic equations to calculate how a spacecraft's velocity changes in response to internal or external forces.
Velocity Components:
  • The initial velocity of the spacecraft can be resolved into two directional components: \(v_{0 x}\) and \(v_{0 y}\).
  • Changes in these components depend on the spacecraft's acceleration, which is affected by factors like engine thrust.
Understanding these components allows engineers to finetune spacecraft trajectories required in highly precise missions like satellite deployment or interplanetary travel.
In our example, the velocity components helped break down the problem, showing how each axis separately contributed to the spacecraft's overall movement. By assessing these movements, aerospace engineers can predict and adjust the flight path as needed, enhancing mission safety and success.

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Most popular questions from this chapter

A swimmer, capable of swimming at a speed of \(1.4 \mathrm{m} / \mathrm{s}\) in still water (i.e., the swimmer can swim with a speed of \(1.4 \mathrm{m} / \mathrm{s}\) relative to the water), starts to swim directly across a \(2.8-\mathrm{km}\) -wide river. However, the current is \(0.91 \mathrm{m} / \mathrm{s},\) and it carries the swimmer downstream. (a) How long does it take the swimmer to cross the river? (b) How far downstream will the swimmer be upon reaching the other side of the river?

Two trees have perfectly straight trunks and are both growing perpendicular to the flat horizontal ground beneath them. The sides of the trunks that face each other are separated by \(1.3 \mathrm{m} .\) A frisky squirrel makes three jumps in rapid succession. First, he leaps from the foot of one tree to a spot that is \(1.0 \mathrm{m}\) above the ground on the other tree. Then, he jumps back to the first tree, landing on it at a spot that is \(1.7 \mathrm{m}\) above the ground. Finally, he leaps back to the other tree, now landing at a spot that is \(2.5 \mathrm{m}\) above the ground. What is the magnitude of the squirrel's displacement?

A hot-air balloon is rising straight up with a speed of \(3.0 \mathrm{m} / \mathrm{s}\). A ballast bag is released from rest relative to the balloon at \(9.5 \mathrm{m}\) above the ground. How much time elapses before the ballast bag hits the ground?

Multiple-Concept Example 4 provides useful background for this problem. A diver runs horizontally with a speed of \(1.20 \mathrm{m} / \mathrm{s}\) off a platform that is \(10.0 \mathrm{m}\) above the water. What is his speed just before striking the water?

A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is \(0.870 \mathrm{m} / \mathrm{s}\) at an angle of \(35.0^{\circ}\) above the table, and it lands on the magazine \(0.0770 \mathrm{s}\) after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

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