Chapter 29: Problem 30
In a Young's double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is \(\theta_{\mathrm{A}}=1.6 \times 10^{-4}\) degrees when the magnitude of the electron momentum is \(p_{\mathrm{A}}=1.2 \times 10^{-22} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} .\) With the same double slit, what momentum magnitude \(p_{\mathrm{B}}\) is necessary so that an angle of \(\theta_{\mathrm{B}}=4.0 \times 10^{-4}\) degrees locates the first-order bright fringes?
Short Answer
Step by step solution
Understand the relationships
Convert angles to radians
Use the experimental setup information
Express \(p_{B}\) in terms of known quantities
Substitute and calculate \(p_{B}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Wave-Particle Duality
- When electrons pass through a double-slit, they create an interference pattern typical of waves, even though they are individual particles.
- This duality can be puzzling but illustrates the quantum nature of matter.
Momentum and Wavelength Relationship
- The formula is \[ \lambda = \frac{h}{p} \]where \(\lambda\) is the wavelength, \(h\) is Planck's constant, and \(p\) is the momentum.
- This equation shows that as momentum increases, the wavelength decreases.
Interference Fringes
- ((Constructive interference)) occurs when the crests of two waves overlap, resulting in a bright fringe.
- ((Destructive interference)) happens when a crest meets a trough, leading to a dark fringe.
Planck's Constant
- Planck's constant is approximately \[ 6.626 \times 10^{-34} ext{ J} imes ext{s} \]
- In the context of the double-slit experiment, \(h\) is used in the de Broglie equation to relate the momentum of electrons to their wavelength.