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How many dark fringes will be produced on either side of the central maximum if light \((\lambda=651 \mathrm{nm})\) is incident on a single slit that is \(5.47 \times 10^{-6} \mathrm{m}\) wide?

Short Answer

Expert verified
There are 8 dark fringes on either side of the central maximum.

Step by step solution

01

Identify the Given Values

We have a wavelength of light, \(\lambda = 651\, \text{nm}\), which we should convert to meters: \(651\, \text{nm} = 651 \times 10^{-9}\, \text{m}\). The width of the slit is \(a = 5.47 \times 10^{-6}\, \text{m}\). We need to find out how many dark fringes appear on either side of the central maximum.
02

Understand the Formula for Dark Fringes

The formula to find the angle \( \theta \) for dark fringes in a single-slit diffraction pattern is \( a \sin \theta = m \lambda \), where \(m\) is the order of the dark fringe. \(m\) is an integer (\(\pm 1, \pm 2, \ldots\)). We need \(\sin \theta \leq 1\) because \(\sin \theta\) cannot be greater than 1.
03

Determine the Maximum Order of Dark Fringes

Substitute \(a = 5.47 \times 10^{-6} \text{ m}\) and \(\lambda = 651 \times 10^{-9} \text{ m}\) into the inequality for \(m\): \(m \lambda \leq a\). Thus, \(m \leq \frac{a}{\lambda} = \frac{5.47 \times 10^{-6}}{651 \times 10^{-9}} \approx 8.4\).
04

Calculate the Number of Dark Fringes

Since \(m\) must be an integer, the maximum \(m\) is \(8\). Therefore, there are \(8\) dark fringes on each side of the central maximum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dark Fringes
In the context of single-slit diffraction, dark fringes are the points in the diffraction pattern where the light intensity is minimal or zero. These occur because of the destructive interference of light waves. When light passes through a small slit, it behaves like waves bending around the edges, interacting with each other. This interaction creates areas of constructive (bright) and destructive (dark) interference.
The dark fringes are described by the equation:
  • \( a \sin \theta = m \lambda \)
where \(a\) is the width of the slit, \(\theta\) is the angle of diffraction, \(m\) is the fringe order (an integer), and \(\lambda\) is the wavelength of the light.
The integer \(m\) represents the number of dark fringes, which appear symmetrically on both sides of the central maximum.
Wavelength
The wavelength, denoted by \(\lambda\), is a key parameter in wave physics and especially in studying phenomena like diffraction. It is the distance between two consecutive points that are in phase on a wave front, such as peak to peak or trough to trough.
In the problem of single-slit diffraction:
  • The wavelength of the light used affects the position and spacing of the diffraction fringes.
  • The longer the wavelength, the wider the spacing between dark fringes.
  • For light, it is typically measured in nanometers (nm), where 1 nm = \(10^{-9}\) meters.
Understanding wavelength is crucial in calculating and predicting the diffraction pattern formed by light.
Central Maximum
The central maximum is the bright fringe located at the center of a diffraction pattern. It is the point where light waves interfere constructively after passing through a slit, resulting in the highest intensity of light.
Characteristics of the central maximum include:
  • It is the brightest and widest part of the diffraction pattern.
  • Located at \(\theta = 0\), directly in line with the slit.
  • It is flanked by alternating dark and bright fringes.
Because the central maximum contains most of the transmitted light, it plays a significant role in analyzing the overall diffraction pattern, making experiments and calculations centered around it essential for understanding diffraction behavior.
Diffraction Pattern
The diffraction pattern is the array of bright and dark regions formed on a screen when light passes through a slit. It results from the bending and interference of the waves.
Key aspects of a diffraction pattern from a single slit include:
  • A central bright fringe (central maximum) with decreasingly intense fringes on either side.
  • Alternating dark and bright fringes (dark and bright bands) resulting from destructive and constructive interference, respectively.
  • The larger the slit width, the closer the fringes.
  • The pattern's exact nature depends on the wavelength of the light and the slit dimensions.
Understanding and analyzing diffraction patterns are essential in fields like optics to assess the properties of light and its interaction with matter.

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Most popular questions from this chapter

Light shines through a single slit whose width is \(5.6 \times 10^{-4} \mathrm{m} .\) A diffraction pattern is formed on a flat screen located \(4.0 \mathrm{m}\) away. The distance between the middle of the central bright fringe and the first dark fringe is \(3.5 \mathrm{mm} .\) What is the wavelength of the light?

In a setup like that in Figure \(27.7,\) a wavelength of \(625 \mathrm{nm}\) is used in a Young's double-slit experiment. The separation between the slits is \(d=\) \(1.4 \times 10^{-5} \mathrm{m} .\) The total width of the screen is \(0.20 \mathrm{m} .\) In one version of the setup, the separation between the double slit and the screen is \(L_{\mathrm{A}}=0.35 \mathrm{m}\) whereas in another version it is \(L_{\mathrm{B}}=0.50 \mathrm{m} .\) On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting.

An inkjet printer uses tiny dots of red, green, and blue ink to produce an image. Assume that the dot separation on the printed page is the same for all colors. At normal viewing distances, the eye does not resolve the individual dots, regardless of color, so that the image has a normal look. The wavelengths for red, green, and blue are \(\lambda_{\text {red }}=660 \mathrm{nm}, \lambda_{\text {green }}=550 \mathrm{nm},\) and \(\lambda_{\text {blue }}=470 \mathrm{nm} .\) The diameter of the pupil through which light enters the eye is \(2.0 \mathrm{mm}\). For a viewing distance of \(0.40 \mathrm{m},\) what is the maximum allowable dot separation?

In a Young's double-slit experiment, the wavelength of the light used is \(520 \mathrm{nm}\) (in vacuum), and the separation between the slits is \(1.4 \times\) \(10^{-6} \mathrm{m} .\) Determine the angle that locates (a) the dark fringe for which \(m=0\) (b) the bright fringe for which \(m=1,\) (c) the dark fringe for which \(m=1,\) and (d) the bright fringe for which \(m=2\).

Two diffraction gratings, A and B, are located at the same distance from the observation screens. Light with the same wavelength \(\lambda\) is used for each. The separation between adjacent principal maxima for grating \(\mathrm{A}\) is \(2.7 \mathrm{cm},\) and for grating \(\mathrm{B}\) it is \(3.2 \mathrm{cm} .\) Grating A has 2000 lines per meter. How many lines per meter does grating B have? (Hint: The diffraction angles are small enough that the approximation \(\sin \theta \approx \tan \theta\) can be used.)

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