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A dark fringe in the diffraction pattern of a single slit is located at an angle of \(\theta_{\mathrm{A}}=34^{\circ} .\) With the same light, the same dark fringe formed with another single slit is at an angle of \(\theta_{\mathrm{B}}=56^{\circ} .\) Find the ratio \(W_{\mathrm{A}} / W_{\mathrm{B}}\) of the widths of the two slits.

Short Answer

Expert verified
The ratio of the widths is approximately 1.48.

Step by step solution

01

Understanding Diffraction and Dark Fringe

In single-slit diffraction, the condition for a dark fringe (minimum intensity) is given by the formula \( a \sin \theta = m \lambda \), where \( a \) is the width of the slit, \( \theta \) is the angle of the dark fringe, \( \lambda \) is the wavelength of the light, and \( m \) is the order of the minimum. In this problem, both slits produce a first-order dark fringe (\( m = 1 \)).
02

Apply the Formula to Slit A

For slit A, we can express the condition for a dark fringe as: \( W_A \sin \theta_A = m\lambda \). Given \( \theta_A = 34^{\circ} \), we write: \( W_A \sin 34^{\circ} = \lambda \).
03

Apply the Formula to Slit B

For slit B, the condition becomes: \( W_B \sin \theta_B = m\lambda \). Given \( \theta_B = 56^{\circ} \), we write: \( W_B \sin 56^{\circ} = \lambda \).
04

Set up the Ratio of Widths

We need to find the ratio \( \frac{W_A}{W_B} \). From the expressions for \( W_A \) and \( W_B \), we set \( W_A \sin 34^{\circ} = W_B \sin 56^{\circ} \), allowing us to solve for the ratio: \( \frac{W_A}{W_B} = \frac{\sin 56^{\circ}}{\sin 34^{\circ}} \).
05

Calculate the Sine Values

First, we find the sine of the given angles: \( \sin 34^{\circ} \approx 0.559 \) and \( \sin 56^{\circ} \approx 0.829 \).
06

Compute the Ratio

Now substitute the sine values into the ratio expression: \( \frac{W_A}{W_B} = \frac{0.829}{0.559} \approx 1.48 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dark Fringe
In the realm of optics, a dark fringe in a diffraction pattern signifies points of minimum intensity formed as light diffracts through a slit. This occurs when waves interfere destructively due to specific path differences. Understanding this concept is anchored in the diffraction equation:
  • The formula for a dark fringe in single-slit diffraction is given by: \[ a \sin \theta = m \lambda \]where:
    • \( a \) is the width of the slit
    • \( \theta \) is the angle at which the dark fringe occurs
    • \( \lambda \) is the wavelength of light
    • \( m \) is the order of the minimum (e.g., the first, second, etc.)
In this equation,
  • The order \( m = 1 \) corresponds to the first dark fringe.
This destructive interference results in the characteristic dark bands intermixed with bright fringes in the pattern formed on a screen.
Diffraction Pattern
A diffraction pattern is a series of bright and dark regions created when waves, such as light, pass through a single slit and spread out. This pattern provides a visual illustration of diffraction. It arises from the interference of diffracted waves, illustrating the wave nature of light. When light passes through a narrow slit, each point along the slit can be thought of as a source of waves that propagate in various directions. These secondary waves interfere with each other, leading to:
  • Bright areas, known as maxima, where constructive interference occurs.
  • Dark areas, or minima, where destructive interference happens.
The angles at which these fringes appear are determined by the slit width and light wavelength. The alternating pattern of dark and bright fringes is central to diffraction studies and is significant in applications such as optical instruments and resolving the structure of small objects.
Ratio of Slit Widths
The ratio of slit widths (\[ \frac{W_A}{W_B} \])is a key calculation in analyzing diffraction patterns from different slits. It allows us to understand how variations in slit width affect the diffraction angle of dark fringes. Given two angles at which dark fringes occur for different slits, this ratio can be determined using their corresponding sines:
  • For Slit A at angle \( \theta_A = 34^{\circ} \):
    • \( W_A \sin \theta_A = \lambda \)
  • For Slit B at angle \( \theta_B = 56^{\circ} \):
    • \( W_B \sin \theta_B = \lambda \)
By equating these expressions and simplifying, the ratio is simplified to:\[ \frac{W_A}{W_B} = \frac{\sin 56^{\circ}}{\sin 34^{\circ}} \approx 1.48 \]This calculation reveals that Slit B is wider than Slit A. Differing slit widths lead to variations in the diffraction pattern, allowing students to explore the influence of physical dimensions on wave behavior.

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Most popular questions from this chapter

Astronomers have discovered a planetary system orbiting the star Upsilon Andromedae, which is at a distance of \(4.2 \times 10^{17} \mathrm{m}\) from the earth. One planet is believed to be located at a distance of \(1.2 \times 10^{11} \mathrm{m}\) from the star. Using visible light with a vacuum wavelength of \(550 \mathrm{nm},\) what is the minimum necessary aperture diameter that a telescope must have so that it can resolve the planet and the star?

You are standing in air and are looking at a flat piece of glass \((n=\) 1.52 ) on which there is a layer of transparent plastic \((n=1.61) .\) Light whose wavelength is 589 nm in vacuum is incident nearly perpendicularly on the coated glass and reflects into your eyes. The layer of plastic looks dark. Find the two smallest possible nonzero values for the thickness of the layer.

In a setup like that in Figure \(27.7,\) a wavelength of \(625 \mathrm{nm}\) is used in a Young's double-slit experiment. The separation between the slits is \(d=\) \(1.4 \times 10^{-5} \mathrm{m} .\) The total width of the screen is \(0.20 \mathrm{m} .\) In one version of the setup, the separation between the double slit and the screen is \(L_{\mathrm{A}}=0.35 \mathrm{m}\) whereas in another version it is \(L_{\mathrm{B}}=0.50 \mathrm{m} .\) On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting.

In a Young's double-slit experiment, the wavelength of the light used is \(520 \mathrm{nm}\) (in vacuum), and the separation between the slits is \(1.4 \times\) \(10^{-6} \mathrm{m} .\) Determine the angle that locates (a) the dark fringe for which \(m=0\) (b) the bright fringe for which \(m=1,\) (c) the dark fringe for which \(m=1,\) and (d) the bright fringe for which \(m=2\).

For a wavelength of \(420 \mathrm{nm},\) a diffraction grating produces a bright fringe at an angle of \(26^{\circ} .\) For an unknown wavelength, the same grating produces a bright fringe at an angle of \(41^{\circ} .\) In both cases the bright fringes are of the same order \(m .\) What is the unknown wavelength?

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