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A dark fringe in the diffraction pattern of a single slit is located at an angle of \(\theta_{\mathrm{A}}=34^{\circ} .\) With the same light, the same dark fringe formed with another single slit is at an angle of \(\theta_{\mathrm{B}}=56^{\circ} .\) Find the ratio \(W_{\mathrm{A}} / W_{\mathrm{B}}\) of the widths of the two slits.

Short Answer

Expert verified
The ratio of the widths is approximately 1.48.

Step by step solution

01

Understanding Diffraction and Dark Fringe

In single-slit diffraction, the condition for a dark fringe (minimum intensity) is given by the formula \( a \sin \theta = m \lambda \), where \( a \) is the width of the slit, \( \theta \) is the angle of the dark fringe, \( \lambda \) is the wavelength of the light, and \( m \) is the order of the minimum. In this problem, both slits produce a first-order dark fringe (\( m = 1 \)).
02

Apply the Formula to Slit A

For slit A, we can express the condition for a dark fringe as: \( W_A \sin \theta_A = m\lambda \). Given \( \theta_A = 34^{\circ} \), we write: \( W_A \sin 34^{\circ} = \lambda \).
03

Apply the Formula to Slit B

For slit B, the condition becomes: \( W_B \sin \theta_B = m\lambda \). Given \( \theta_B = 56^{\circ} \), we write: \( W_B \sin 56^{\circ} = \lambda \).
04

Set up the Ratio of Widths

We need to find the ratio \( \frac{W_A}{W_B} \). From the expressions for \( W_A \) and \( W_B \), we set \( W_A \sin 34^{\circ} = W_B \sin 56^{\circ} \), allowing us to solve for the ratio: \( \frac{W_A}{W_B} = \frac{\sin 56^{\circ}}{\sin 34^{\circ}} \).
05

Calculate the Sine Values

First, we find the sine of the given angles: \( \sin 34^{\circ} \approx 0.559 \) and \( \sin 56^{\circ} \approx 0.829 \).
06

Compute the Ratio

Now substitute the sine values into the ratio expression: \( \frac{W_A}{W_B} = \frac{0.829}{0.559} \approx 1.48 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dark Fringe
In the realm of optics, a dark fringe in a diffraction pattern signifies points of minimum intensity formed as light diffracts through a slit. This occurs when waves interfere destructively due to specific path differences. Understanding this concept is anchored in the diffraction equation:
  • The formula for a dark fringe in single-slit diffraction is given by: \[ a \sin \theta = m \lambda \]where:
    • \( a \) is the width of the slit
    • \( \theta \) is the angle at which the dark fringe occurs
    • \( \lambda \) is the wavelength of light
    • \( m \) is the order of the minimum (e.g., the first, second, etc.)
In this equation,
  • The order \( m = 1 \) corresponds to the first dark fringe.
This destructive interference results in the characteristic dark bands intermixed with bright fringes in the pattern formed on a screen.
Diffraction Pattern
A diffraction pattern is a series of bright and dark regions created when waves, such as light, pass through a single slit and spread out. This pattern provides a visual illustration of diffraction. It arises from the interference of diffracted waves, illustrating the wave nature of light. When light passes through a narrow slit, each point along the slit can be thought of as a source of waves that propagate in various directions. These secondary waves interfere with each other, leading to:
  • Bright areas, known as maxima, where constructive interference occurs.
  • Dark areas, or minima, where destructive interference happens.
The angles at which these fringes appear are determined by the slit width and light wavelength. The alternating pattern of dark and bright fringes is central to diffraction studies and is significant in applications such as optical instruments and resolving the structure of small objects.
Ratio of Slit Widths
The ratio of slit widths (\[ \frac{W_A}{W_B} \])is a key calculation in analyzing diffraction patterns from different slits. It allows us to understand how variations in slit width affect the diffraction angle of dark fringes. Given two angles at which dark fringes occur for different slits, this ratio can be determined using their corresponding sines:
  • For Slit A at angle \( \theta_A = 34^{\circ} \):
    • \( W_A \sin \theta_A = \lambda \)
  • For Slit B at angle \( \theta_B = 56^{\circ} \):
    • \( W_B \sin \theta_B = \lambda \)
By equating these expressions and simplifying, the ratio is simplified to:\[ \frac{W_A}{W_B} = \frac{\sin 56^{\circ}}{\sin 34^{\circ}} \approx 1.48 \]This calculation reveals that Slit B is wider than Slit A. Differing slit widths lead to variations in the diffraction pattern, allowing students to explore the influence of physical dimensions on wave behavior.

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Most popular questions from this chapter

Light of wavelength \(410 \mathrm{nm}\) (in vacuum) is incident on a diffraction grating that has a slit separation of \(1.2 \times 10^{-5} \mathrm{m} .\) The distance between the grating and the viewing screen is \(0.15 \mathrm{m} .\) A diffraction pattern is produced on the screen that consists of a central bright fringe and higher-order bright fringes (see the drawing). (a) Determine the distance \(y\) from the central bright fringe to the second-order bright fringe. (Hint: The diffraction angles are small enough that the approximation \(\tan \theta \approx \sin \theta\) can be used.) (b) If the entire apparatus is submerged in water \(\left(n_{\text {water }}=1.33\right),\) what is the distance \(y ?\)

Light that has a wavelength of 668 nm passes through a slit \(6.73 \times 10^{-6} \mathrm{m}\) wide and falls on a screen that is \(1.85 \mathrm{m}\) away. What is the distance on the screen from the center of the central bright fringe to the third dark fringe on either side?

Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is \(\lambda_{\mathrm{A}}=645 \mathrm{nm} .\) The other wavelength is \(\lambda_{\mathrm{B}}\) and is unknown. On a viewing screen, the light with wavelength \(\lambda_{\mathrm{A}}=645 \mathrm{nm}\) produces its third-order bright fringe at the same place where the light with wavelength \(\lambda_{\mathrm{B}}\) produces its fourth dark fringe. The fringes are counted relative to the central or zeroth-order bright fringe. What is the unknown wavelength?

Violet light (wavelength \(=410 \mathrm{nm}\) ) and red light (wavelength \(=\) \(660 \mathrm{nm}\) ) lie at opposite ends of the visible spectrum. (a) For each wavelength, find the angle \(\theta\) that locates the first-order maximum produced by a grating with 3300 lines/cm. This grating converts a mixture of all colors between violet and red into a rainbow-like dispersion between the two angles. Repeat the calculation above for (b) the second-order maximum and (c) the thirdorder maximum. (d) From your results, decide whether there is an overlap between any of the "rainbows" and, if so, specify which orders overlap.

For a wavelength of \(420 \mathrm{nm},\) a diffraction grating produces a bright fringe at an angle of \(26^{\circ} .\) For an unknown wavelength, the same grating produces a bright fringe at an angle of \(41^{\circ} .\) In both cases the bright fringes are of the same order \(m .\) What is the unknown wavelength?

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