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For each of the three sheets of polarizing material shown in the drawing, the orientation of the transmission axis is labeled relative to the vertical. The incident beam of light is unpolarized and has an intensity of 1260.0 \(\mathrm{W} / \mathrm{m}^{2} .\) What is the intensity of the beam transmitted through the three sheets when \(\theta_{1}=19.0^{\circ}, \theta_{2}=55.0^{\circ},\) and \(\theta_{3}=100.0^{\circ} ?\)

Short Answer

Expert verified
The intensity is approximately 41.3 W/m².

Step by step solution

01

Understanding Unpolarized Light

When unpolarized light passes through a polarizer, its intensity is reduced by half. The initial intensity of unpolarized light is given as \(1260.0 \, \mathrm{W}/\mathrm{m}^2\). After passing through the first polarizer, the intensity \(I_1\) will be \(I_1 = \frac{1}{2} \times 1260.0 = 630.0 \, \mathrm{W}/\mathrm{m}^2\).
02

Intensity after First Polarizer

The intensity after the first polarizer, which is oriented at \(\theta_1 = 19.0^\circ\), is calculated using Malus's Law: \(I = I_1 \times \cos^2(\theta_1)\). Substitute \(\theta_1 = 19.0^\circ\): \(I = 630.0 \times \cos^2(19.0^\circ)\). Calculating this gives \(I_2 \approx 563.3 \, \mathrm{W}/\mathrm{m}^2\).
03

Intensity after Second Polarizer

Using Malus's Law again for the second polarizer at \(\theta_2 = 55.0^\circ\), find \(I_3 = I_2 \times \cos^2(\theta_2 - \theta_1)\). Substitute the angles: \(I_3 = 563.3 \times \cos^2(55.0^\circ - 19.0^\circ)\). Calculate this to get \(I_3 \approx 258.6 \, \mathrm{W}/\mathrm{m}^2\).
04

Intensity after Third Polarizer

Finally, apply Malus's Law for the third polarizer at \(\theta_3 = 100.0^\circ\): \(I_4 = I_3 \times \cos^2(\theta_3 - \theta_2)\). Substitute the values: \(I_4 = 258.6 \times \cos^2(100.0^\circ - 55.0^\circ)\). This results in \(I_4 \approx 41.3 \, \mathrm{W}/\mathrm{m}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus's Law
Malus's Law is a fundamental principle in optics that describes how the intensity of polarized light changes as it passes through a polarizing filter. This law is crucial when working with polarized light and can help in predicting the behavior of light under different circumstances. Malus's Law states that the intensity of light, \[ I = I_0 \times \cos^2(\theta) \] where
  • \( I \) is the intensity of light after passing through the polarizer,
  • \( I_0 \) is the initial intensity of light, and
  • \( \theta \) is the angle between the light's initial polarization direction and the filter's axis.
This equation illustrates that the intensity after passing through a polarizer depends on the angle of incidence of the light relative to the filter's axis. If the angle is 0 degrees (meaning the light is perfectly aligned with the filter), the intensity will remain the same as \( I_0 \). Conversely, if the light is 90 degrees relative to the axis, the intensity will be zero. This makes Malus's Law essential for understanding how light is manipulated through various optical devices.
Unpolarized Light
Unpolarized light refers to light waves that vibrate in multiple planes. Most natural light sources, such as the sun and conventional light bulbs, emit unpolarized light. When unpolarized light encounters a polarizer, half of its intensity is typically absorbed and only the component of light that aligns with the polarizer's axis is transmitted.

For unpolarized light with an initial intensity of \( 1260.0 \, \text{W/m}^2 \), passing through a polarizer results in the intensity being halved. In this context, the intensity of light immediately after the first polarizer will be:\[ I = \frac{1}{2} \times 1260.0 \, \text{W/m}^2 = 630.0 \, \text{W/m}^2 \]

This reduced intensity becomes the baseline figure for applying Malus's Law with additional polarizing layers. Understanding how unpolarized light behaves when encountering a polarizer is a foundational concept in optics, helping predict how light intensity will change with further filters.
Intensity of Light
The intensity of light is a measure of the power transmitted through a given area. It is expressed in watts per square meter (\(\text{W/m}^2\)). In the context of polarized light, intensity changes based on alignment through polarizing filters.

When light passes through multiple polarizers, its intensity is modified at each stage following the principles of Malus's Law and initial reduction of unpolarized light. For example, after passing through the first polarizer, the intensity becomes half. Each successive polarizer then applies Malus's Law based on the relative angle:
- Intensity after the second polarizer: \[ I_2 = I_1 \times \cos^2(\theta_2 - \theta_1) \]- Intensity after the third polarizer: \[ I_3 = I_2 \times \cos^2(\theta_3 - \theta_2) \]

While calculating, each change in intensity reflects how aligned the light's polarization is with the next filter's transmission axis. This stacking effect demonstrates the importance of understanding light intensity variations in practical applications, like reducing glare or enhancing visibility through polarizing sunglasses and camera lenses.

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