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A series \(\mathrm{RCL}\) circuit contains a \(47.0-\Omega\) resistor, a \(2.00-\mu \mathrm{F}\) capacitor, and a \(4.00-\mathrm{mH}\) inductor. When the frequency is \(2550 \mathrm{Hz},\) what is the power factor of the circuit?

Short Answer

Expert verified
The power factor is calculated using the impedance and resistance, yielding a specific value for this circuit configuration.

Step by step solution

01

Calculate the Inductive Reactance

Use the formula for inductive reactance, \( X_L = 2 \pi f L \), where \( f \) is the frequency and \( L \) is the inductance. In this case, \( X_L = 2 \pi \times 2550 \times 4.00 \times 10^{-3} \). Calculate this to find \( X_L \).
02

Calculate the Capacitive Reactance

Use the formula for capacitive reactance, \( X_C = \frac{1}{2 \pi f C} \), where \( C \) is the capacitance. Plug in the values, \( X_C = \frac{1}{2 \pi \times 2550 \times 2.00 \times 10^{-6}} \), to determine \( X_C \).
03

Calculate the Impedance of the Circuit

The impedance \( Z \) is calculated using the formula: \( Z = \sqrt{R^2 + (X_L - X_C)^2} \), where \( R \) is the resistance. Substitute \( R = 47.0 \), and the values from Steps 1 and 2 for \( X_L \) and \( X_C \).
04

Determine the Power Factor

The power factor \( \cos(\phi) \) is given by \( \frac{R}{Z} \). Use the results from Step 3 to calculate \( \cos(\phi) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductive Reactance
Inductive reactance is a measure of how much a coil of wire, known as an inductor, resists the change of electric current passing through it. When an alternating current (AC) flows through an inductor, it creates a magnetic field that opposes changes in the current. The formula for inductive reactance, denoted as \( X_L \), is given by \( X_L = 2 \pi f L \). Here, \( f \) is the frequency of the AC, and \( L \) is the inductance in henrys (H).
For example, in the provided problem, with a frequency of \( 2550 \text{ Hz} \) and inductance of \( 4.00 \times 10^{-3} \text{ H} \) (or 4.00 mH), you can calculate the inductive reactance as follows:
  • Plug in the values: \( X_L = 2 \pi \times 2550 \times 4.00 \times 10^{-3} \)

  • Calculate \( X_L \) to find the resistor's opposing force to the change in current due to the inductance.
This calculation helps in understanding how an inductor affects the flow of AC and aids in the overall analysis of an RCL circuit.
Capacitive Reactance
Capacitive reactance is a measure of how much a capacitor, a device that stores electrical energy, resists the flow of AC. When an AC voltage is applied to a capacitor, it charges and discharges in a manner that reduces the current flow. The formula for capacitive reactance \( X_C \) is \( X_C = \frac{1}{2 \pi f C} \), where \( C \) represents the capacitance in farads (F).
In the context of the original exercise, where the frequency is \( 2550 \text{ Hz} \) and the capacitance is \( 2.00 \times 10^{-6} \text{ F} \) (or 2.00 μF), the capacitive reactance can be calculated by:
  • Substitute into the formula: \( X_C = \frac{1}{2 \pi \times 2550 \times 2.00 \times 10^{-6}} \)

  • Solve for \( X_C \) to find out how the capacitor affects current flow in the circuit.
Understanding capacitive reactance is crucial as it indicates how capacitors, often used for smoothing voltage, can influence the performance of RCL circuits.
Power Factor
The power factor is a measure of how effectively electrical power is being used in a circuit. It is the ratio of the real power that does actual work in the circuit to the apparent power that flows through the circuit. The power factor is given by \( \cos(\phi) \), where \( \phi \) is the phase difference between the voltage and current.
In RCL circuits, power factor ranges between 0 and 1, where a value close to 1 indicates that more of the power is being effectively used for doing work. You can calculate the power factor in a circuit using the formula \( \cos(\phi) = \frac{R}{Z} \), where \( R \) is the resistance, and \( Z \) is the impedance.
This means:
  • Calculate the impedance \( Z \) using the formula: \( Z = \sqrt{R^2 + (X_L - X_C)^2} \)

  • Determine the power factor using \( \cos(\phi) \)
The power factor is important for efficiency and cost savings in electrical systems. A high power factor means less energy is wasted.
Impedance Calculation
Impedance is a key concept in AC circuit analysis. It is the total opposition a circuit offers to the passage of alternating current, essentially combining resistance and reactance (both inductive and capacitive). Impedance, denoted as \( Z \), is calculated with the formula \( Z = \sqrt{R^2 + (X_L - X_C)^2} \).
In this formula:
  • \( R \) is the resistance in ohms (\( \Omega \))
  • \( X_L \) is the inductive reactance
  • \( X_C \) is the capacitive reactance
By substituting the values of resistance and the reactances, you can determine the overall impedance. In RCL circuits, impedance affects both how voltages and currents are distributed and the overall energy consumption. Understanding impedance is crucial as it helps predict the circuit behavior under various electrical conditions.

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Most popular questions from this chapter

An inductor has an inductance of \(0.080 \mathrm{H}\). The voltage across this inductor is \(55 \mathrm{V}\) and has a frequency of \(650 \mathrm{Hz}\). What is the current in the inductor?

A capacitor is connected across an ac generator whose frequency is \(750 \mathrm{Hz}\) and whose peak output voltage is \(140 \mathrm{V} .\) The rms current in the circuit is \(3.0 \mathrm{A}\). (a) What is the capacitance of the capacitor? (b) What is the magnitude of the maximum charge on one plate of the capacitor?

A series \(\mathrm{RCL}\) circuit includes a resistance of \(275 \Omega,\) an inductive reactance of \(648 \Omega,\) and a capacitive reactance of \(415 \Omega .\) The current in the circuit is 0.233 A. What is the voltage of the generator?

An ac series circuit has an impedance of \(192 \Omega,\) and the phase angle between the current and the voltage of the generator is \(\phi=-75^{\circ} .\) The circuit contains a resistor and either a capacitor or an inductor. Find the resistance \(R\) and the capacitive reactance \(X_{\mathrm{C}}\) or the inductive reactance \(X_{\mathrm{L}}\) whichever is appropriate.

A \(63.0-\mu \mathrm{F}\) capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is \(4.00 \mathrm{V}\) and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches \(15.0 \mathrm{A}\). As the generator frequency is increased, at what frequency will the fuse burn out?

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