/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A \(40.0-\mu \mathrm{F}\) capaci... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(40.0-\mu \mathrm{F}\) capacitor is connected across a \(60.0-\mathrm{Hz}\) generator. An inductor is then connected in parallel with the capacitor. What is the value of the inductance if the rms currents in the inductor and capacitor are equal?

Short Answer

Expert verified
The inductance is approximately 0.176 H.

Step by step solution

01

Identify the Capacitance and Frequency

The capacitance of the capacitor is given as \( C = 40.0 \mu F \) and the frequency of the generator is given as \( f = 60.0 \text{ Hz} \).
02

Calculate Capacitor Reactance

The reactance of the capacitor \( X_C \) can be calculated using the formula \( X_C = \frac{1}{2\pi f C} \).Substitute \( C = 40.0 \times 10^{-6} \text{ F} \) and \( f = 60 \text{ Hz} \): \[X_C = \frac{1}{2\pi \times 60 \times 40.0 \times 10^{-6}} \approx 66.31 \Omega\]
03

Use Current Relationship

Since the rms currents in the inductor and the capacitor are equal, the reactance of the inductor \( L \) is equal to the reactance of the capacitor. This means \( X_L = X_C \).Since \( X_L = 2 \pi f L \), we can write:\[ 2 \pi f L = X_C \approx 66.31 \Omega \]
04

Solve for Inductance

Rearrange the equation from Step 3 to solve for \( L \):\[ L = \frac{X_C}{2 \pi f} \]Substitute \( X_C = 66.31 \Omega \) and \( f = 60 \text{ Hz} \):\[ L = \frac{66.31}{2 \pi \times 60} \approx 0.176 \text{ H} \]
05

Final Answer

The value of the inductance \( L \) is approximately \( 0.176 \text{ H} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capacitance
Capacitance is a fundamental concept in electrical engineering, relating to the ability of a system to store an electric charge. When you hear about capacitors in a circuit, they are devices that hold electrical energy through a phenomenon called capacitance. The capacitance value, measured in farads (F), tells us how much charge is stored per volt of potential difference across the capacitor. In our exercise, we have a capacitor with a capacitance of 40.0 microfarads (μF), which is a common unit for capacitors.
The formula to calculate capacitive reactance, which represents the opposition a capacitor presents to the change of voltage in an AC circuit, is given by:\[ X_C = \frac{1}{2\pi f C} \]Where:
  • \( X_C \) is the capacitive reactance in ohms (Ω).
  • \( f \) is the frequency of the AC source in hertz (Hz).
  • \( C \) is the capacitance in farads (F).
Understanding this formula helps in determining how capacitors behave in circuits with alternating current.
Inductance
Inductance is another key concept in electronics, closely related to the behavior of wires and coils when exposed to changing currents. It describes the property through which an inductor resists changes in current through it. Inductance is measured in henrys (H) and plays a critical role in AC circuits.
An inductor's opposition to current changes is quantified by its inductive reactance, calculated as:\[ X_L = 2 \pi f L \]Where:
  • \( X_L \) is the inductive reactance in ohms (Ω).
  • \( f \) is the frequency in hertz (Hz).
  • \( L \) is the inductance in henrys (H).
In our exercise, the inductor is paired with a capacitor, and because their rms currents are equal, their reactances are matched. Solving for inductance when the reactance is known allows us to determine how much the inductor will impede changes in the current at a given frequency.
RMS Current
RMS stands for root mean square and is a method used to compute the effective value of an alternating current (AC). Unlike direct current (DC), which has a constant value, AC varies with time. To compare its effect with DC, we use the concept of RMS, which gives a value that represents the equivalent power in an AC circuit.
In applications, the RMS current is crucial because it reflects the amount of work done or power dissipated by the circuit. The relationship between RMS current and reactance is important for predicting the behavior of components like capacitors and inductors under AC conditions. In our specific scenario, equal RMS currents across the inductor and capacitor indicate that their reactances are the same. This is key in our calculations for determining the inductance, as it allows us to equate the reactance values to solve for the unknowns. By using RMS, we ensure that our comparisons and measurements adhere to real-world, effective values.

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Most popular questions from this chapter

A series RCL circuit contains a \(5.10-\mu \mathrm{F}\) capacitor and a generator whose voltage is \(11.0 \mathrm{V}\). At a resonant frequency of \(1.30 \mathrm{kHz}\) the power delivered to the circuit is \(25.0 \mathrm{W}\). Find the values of (a) the inductance and (b) the resistance. (c) Calculate the power factor when the generator frequency is \(2.31 \mathrm{kHz}\)

A capacitor is connected across the terminals of an ac generator that has a frequency of \(440 \mathrm{Hz}\) and supplies a voltage of \(24 \mathrm{V} .\) When a second capacitor is connected in parallel with the first one, the current from the generator increases by 0.18 A. Find the capacitance of the second capacitor.

In the absence of a nearby metal object, the two inductances \(\left(L_{\mathrm{A}}\right.\) and \(\left.L_{\mathrm{B}}\right)\) in a heterodyne metal detector are the same, and the resonant frequencies of the two oscillator circuits have the same value of \(630.0 \mathrm{kHz}\) When the search coil (inductor \(\mathrm{B}\) ) is brought near a buried metal object, a beat frequency of \(7.30 \mathrm{kHz}\) is heard. By what percentage does the buried object increase the inductance of the search coil?

The reactance of a capacitor is \(68 \Omega\) when the ac frequency is \(460 \mathrm{Hz}\). What is the reactance when the frequency is \(870 \mathrm{Hz}\) ?

A circuit consists of a resistor in series with an inductor and an ac generator that supplies a voltage of 115 V. The inductive reactance is \(52.0 \Omega\), and the current in the circuit is 1.75 A. Find the average power delivered to the circuit.

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