/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A standard door into a house rot... [FREE SOLUTION] | 91Ó°ÊÓ

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A standard door into a house rotates about a vertical axis through one side, as defined by the door's hinges. A uniform magnetic field is parallel to the ground and perpendicular to this axis. Through what angle must the door rotate so that the magnetic flux that passes through it decreases from its maximum value to one-third of its maximum value?

Short Answer

Expert verified
The door must rotate by approximately 70.53 degrees.

Step by step solution

01

Define Magnetic Flux Formula

Magnetic flux \( \Phi \) through a surface is given by the formula \( \Phi = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field, \( A \) is the area of the door, and \( \theta \) is the angle between the magnetic field and the normal to the surface.
02

Determine Initial Condition

Initially, when the door is perpendicular to the magnetic field, \( \theta = 0 \) degrees. This makes \( \cos(\theta) = \cos(0) = 1 \). Therefore, the magnetic flux is at its maximum value, \( \Phi_{\text{max}} = B \cdot A \).
03

Calculate One-third of Maximum Flux

To achieve one-third of the maximum flux, the equation becomes \( \Phi = \frac{1}{3} \Phi_{\text{max}} = \frac{1}{3} B \cdot A \).
04

Set up Equation for Reduced Flux

Substitute the flux condition into the formula: \( \frac{1}{3} B \cdot A = B \cdot A \cdot \cos(\theta) \). Simplifying, we have \( \frac{1}{3} = \cos(\theta) \).
05

Solve for \( \theta \)

To find \( \theta \), take the inverse cosine, so \( \theta = \cos^{-1}\left(\frac{1}{3}\right) \). Calculate this using a calculator to find \( \theta \approx 70.53 \) degrees.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
A magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts. In simpler terms, it represents how the magnetic force is distributed in space.
The magnetic field is denoted by the symbol \( B \) and is measured in teslas (T). It affects various materials differently depending on their magnetic properties.When we talk about magnetic fields in physics, we usually refer to how they interact with different surfaces or objects. In this particular problem, the magnetic field is parallel to the ground and perpendicular to the door's axis of rotation. This orientation is key to determining how the magnetic flux changes as the door rotates.
  • Magnetic fields have both direction and magnitude.
  • They can be visualized as lines of force that extend from north to south poles of a magnet.
  • The strength of a magnetic field decreases with distance from the source.
Understanding the basics of magnetic fields helps in grasping how they influence the magnetic flux through a surface like a door in this scenario.
Angle of Rotation
The angle of rotation is a crucial factor in determining how much the magnetic flux through the door changes. Rotation refers to how the door moves around its vertical axis. Initially, when the door is perfectly perpendicular to the magnetic field, the angle \( \theta \) is \( 0 \) degrees. This setup results in the maximum possible magnetic flux. As the door starts rotating, this angle increases, which in turn affects how much of the magnetic field lines pass through the door's surface.When we want the flux to drop from its maximum to one-third of its maximum, we need to calculate the new orientation, i.e., the angle of rotation that makes this happen.
  • The formula \( \Phi = B \cdot A \cdot \cos(\theta) \) incorporates the angle \( \theta \) between the magnetic field and the normal to the surface.
  • As \( \theta \) grows larger, \( \cos(\theta) \) becomes smaller, reducing the flux.
  • For this problem, the calculation \( \theta = \cos^{-1}(\frac{1}{3}) \) results in approximately \( 70.53 \) degrees.
This means the door must rotate around \( 70.53 \) degrees to reduce the flux to one-third of the maximum value.
Physics Problem Solving
Physics problem solving requires a structured approach, involving comprehension of fundamental concepts and methodical calculations.
To solve a physics problem correctly, it is important to:
  • Clearly understand what is being asked. In this case, we're finding the rotation angle of a door to decrease magnetic flux to one-third of its maximum value.
  • Identify and understand the physical principles involved. For this problem, it’s the interaction between a magnetic field and a rotating surface.
  • Set up equations based on these principles. We used the equation \( \Phi = B \cdot A \cdot \cos(\theta) \) to represent the flux through the rotating door.
  • Simplify and solve these equations step-by-step. By manipulating the equation to match the problem's conditions, we derived \( \theta = \cos^{-1}(\frac{1}{3}) \).
Approaching problems in this organized manner facilitates not only a solution but also a deeper understanding of the physical phenomena at play.

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Most popular questions from this chapter

A generating station is producing \(1.2 \times 10^{6} \mathrm{W}\) of power that is to be sent to a small town located \(7.0 \mathrm{km}\) away. Each of the two wires that comprise the transmission line has a resistance per kilometer of \(5.0 \times\) \(10^{-2} \Omega / \mathrm{km} .\) (a) Find the power used to heat the wires if the power is transmitted at \(1200 \mathrm{V} .\) (b) \(\mathrm{A} 100: 1\) step-up transformer is used to raise the voltage before the power is transmitted. How much power is now used to heat the wires?

A Generator Bike. You and your team are designing a generator using a stationary bike to rotate a coil in a uniform magnetic field. The gearing is set up so that the coil rotates 60 times for one complete rotation of the bike pedals. Therefore, one revolution of the pedals per second results in a \(60-\mathrm{Hz}\) alternating current in the coil. The circular coil has 350 turns and a diameter of \(15.0 \mathrm{cm},\) and its axis of rotation is along its diameter. (a) If a uniform magnetic field is oriented perpendicular to the coil's axis of rotation and has a magnitude of \(B=0.225 \mathrm{T}\), what is the peak emf produced by the generator bike? (b) What is the rms emf? (c) To what magnitude should you reduce the field if you want the rms emf to be 110 VAC? (d) Instead of reducing the field, you could use a step-down transformer to reduce the rms emf to 110 VAC. What should be the ratio of primary to secondary turns of the transformer coils?

The resistances of the primary and secondary coils of a transformer are 56 and \(14 \Omega,\) respectively. Both coils are made from lengths of the same copper wire. The circular turns of each coil have the same diameter. Find the turns ratio \(N_{J} / N_{\mathrm{p}}\).

A generator has a square coil consisting of 248 turns. The coil rotates at \(79.1 \mathrm{rad} / \mathrm{s}\) in a \(0.170-\mathrm{T}\) magnetic field. The peak output of the generator is \(75.0 \mathrm{V}\). What is the length of one side of the coil?

Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bicycle generator presses against the bike tire and turns the coil of the generator at an angular speed that is 38 times as great as the angular speed of the tire itself. Each tire has a radius of \(0.300 \mathrm{m}\). The coil consists of 125 turns, has an area of \(3.86 \times 10^{-3} \mathrm{m}^{2},\) and rotates in a \(0.0900-\mathrm{T}\) magnetic field. The bicycle starts from rest and has an acceleration of \(+0.550 \mathrm{m} / \mathrm{s}^{2} .\) What is the peak emf produced by the generator at the end of 5.10 s?

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