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Suppose that a uniform magnetic field is everywhere perpendicular to this page. The field points directly upward toward you. A circular path is drawn on the page. Use Ampère's law to show that there can be no net current passing through the circular surface.

Short Answer

Expert verified
There can be no net current encircled because the magnetic field is perpendicular, leading to a zero line integral.

Step by step solution

01

Understanding Ampère's Law

Ampère's Law states that the line integral of the magnetic field \(B\) around a closed path is equal to the permeability of free space \(\mu_0\) times the net current \(I_{enc}\) passing through the surface enclosed by the path. Mathematically, this is expressed as \(\oint B \cdot dl = \mu_0 I_{enc}\). In this scenario, we need to consider how the magnetic field interacts with the circular path drawn.
02

Analyzing the Uniform Magnetic Field

In this problem, the magnetic field is uniform and points upward perpendicular to the page. Considering a circular path drawn on the page, this means the magnetic field is perpendicular to any path on the page, including the circular one.
03

Calculating the Line Integral

Because the magnetic field lines are perpendicular to the plane, they run parallel to the normal of the circle drawn on the page. Therefore, the dot product \(B \cdot dl\) becomes zero everywhere along the path, since \(B\) and \(dl\) are perpendicular. This leads to a line integral of zero: \(\oint B \cdot dl = 0\).
04

Applying Ampère's Law to Find Net Current

According to Ampère's Law \(\oint B \cdot dl = \mu_0 I_{enc}\), if the integral is zero (as calculated previously), then it must be true that \(\mu_0 I_{enc} = 0\). Since \(\mu_0\) is a constant and not zero, it implies that the net current \(I_{enc}\) through the loop must be zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. The magnetic field at any given point is specified by a vector, which means it has both a direction and a magnitude. In common terms, the magnetic field around a magnet is the area where magnetic forces are observable.

In the problem we are addressing, the magnetic field is specified to be uniform and perpendicular to the page. This means every magnetic field vector in the region of interest points in the same direction - towards the observer. In physical scenarios, magnetic fields can be created by either permanent magnets or currents flowing through a conductor.

When dealing with Ampère's Law, understanding the direction and uniformity of the magnetic field is essential, as it helps determine the relationship between the field and the path or surface being analyzed. The interaction of the magnetic field with various paths determines how we apply mathematical operations like line integrals, influencing the overall analysis of magnetic and electrical interactions.
Line Integral
A line integral is a calculus concept used to find a function's integral over a path in space. In the context of magnetic fields, the line integral is specifically used to evaluate the magnetic field along a given closed path or loop. This concept is crucial when applying Ampère’s Law, which relates magnetic fields to the electric currents that produce them.

For a magnetic field described in the exercise, imagine moving along the circular path. At every point, the "path element" is represented by a small vector, denoted by \(dl\). The dot product of the magnetic field \(B\) and the path element \(dl\) gives us the contribution to the line integral from that small section. In mathematical notation, the line integral of the magnetic field is \[ \oint B \cdot dl = \text{sum of } B \cdot dl \text{ over the path} \].

In this specific problem, because the magnetic field is perpendicular to the path, the dot product \(B \cdot dl\) results in zero at each point of the path. This causes the total line integral to be zero, which, by Ampère's Law, implies there is no net current threading the loop. Understanding this confirms that if no component of the magnetic field parallels the path, the magnetic influence measured by the line integral vanishes.
Current
Current, in the context of electromagnetism, refers to the flow of electric charge through a conductor. Measured in amperes (A), it is fundamental to generating magnetic fields and is directly related to Ampère's Law. The net current in a given loop dictates the magnetic field pattern that surrounds it.

In Ampère's Law, the key term related to current is \(I_{enc}\), the enclosed current by the loop or path in question. According to the exercise, the net current is calculated using the line integral of the magnetic field over a closed path. If this integral equals zero, as in our uniform magnetic field scenario, the net current must also be zero.

This result tells us that no current is passing through the area enclosed by the circular path. This conclusion is integral to the concept of Ampère's law, reinforcing the principle that a zero integral of magnetic field implies zero enclosed current. Therefore, while the magnetic field itself needs no current to maintain its uniformity, Ampère's Law helps us understand the underlying presence or absence of current in complex electromagnetic scenarios.

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Most popular questions from this chapter

One component of a magnetic field has a magnitude of \(0.048 \mathrm{T}\) and points along the \(+x\) axis, while the other component has a magnitude of \(0.065 \mathrm{T}\) and points along the \(-y\) axis. A particle carrying a charge of \(+2.0 \times 10^{-5} \mathrm{C}\) is moving along the \(+z\) axis at a speed of \(4.2 \times \mathrm{x}\) \(10^{3} \mathrm{m} / \mathrm{s}\) (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the \(+x\) axis.

The \(x, y,\) and \(z\) components of a magnetic field are \(B_{x}=0.10 \mathrm{T},\) \(B_{y}=0.15 \mathrm{T},\) and \(B_{z}=0.17 \mathrm{T} .\) A \(25-\mathrm{cm}\) wire is oriented along the \(z\) axis and carries a current of \(4.3 \mathrm{A} .\) What is the magnitude of the magnetic force that acts on this wire?

A wire has a length of \(7.00 \times 10^{-2} \mathrm{m}\) and is used to make a circular coil of one turn. There is a current of \(4.30 \mathrm{A}\) in the wire. In the presence of a \(2.50-\mathrm{T}\) magnetic field, what is the maximum torque that this coil can experience?

Electron beams are sometimes used to melt and evaporate metals in order to deposit thin metallic films on surfaces (similar to gold plating). One method is to put the material to be evaporated (called the "target") into a small tungsten cup (a crucible that has a very high melting point) and direct a beam of electrons at the target. Your team has been given the task of designing an electron-beam evaporator. The crucible is a cylinder, \(2.0 \mathrm{cm}\) in diameter and \(1.5 \mathrm{cm}\) in height, and contains a small target of pure nickel (Ni). The electrons are accelerated through a potential difference of \(V=1.20 \mathrm{kV}\), and form a beam that originates below the crucible, exactly \(3.70 \mathrm{cm}\) off its center, in the \(+x\) direction (see the drawing). (a) What is the speed of the electrons in the beam? (b) You must steer the electron beam with a magnetic field so that it curls over the lip of the cup and strikes the nickel target. Assuming that a uniform field exists above the cup (the field is zero below), what must be the radius of the beam's circular path? (c) In what direction should the field point if the beam initially approaches the cup from the \(-y\) axis? (d) What must be the magnitude of the uniform magnetic field?

A long solenoid has a length of \(0.65 \mathrm{m}\) and contains 1400 turns of wire. There is a current of \(4.7 \mathrm{A}\) in the wire. What is the magnitude of the magnetic field within the solenoid?

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