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A square coil and a rectangular coil are each made from the same length of wire. Each contains a single turn. The long sides of the rectangle are twice as long as the short sides. Find the ratio \(\tau_{\text {square }} / \tau_{\text {rectangle }}\) of the maximum torques that these coils experience in the same magnetic field when they contain the same current.

Short Answer

Expert verified
The ratio of the maximum torques is \( \frac{9}{8} \).

Step by step solution

01

Understanding the Problem

We need to find the ratio of the torques experienced by two coils, one square and one rectangular, made from the same length of wire. The rectangle has long sides twice the length of the short sides. Both carry the same current and are placed in the same magnetic field.
02

Express Wire Length Equations

Let the side of the square coil be \( s \). Therefore, the total length of the wire is \( 4s \). For the rectangular coil, let the short side be \( x \) and the long side be \( 2x \), so the length is \( 2x + 2(2x) = 6x \). Since both coils use the same length of wire, we equate: \( 4s = 6x \).
03

Solve for Dimensions

From \( 4s = 6x \), we find the relationships \( s = \frac{3x}{2} \) and \( x = \frac{2s}{3} \). This allows us to express the dimensions of both coils in terms of a single variable.
04

Calculate Coil Areas

For the square coil, the area is \( s^2 \). For the rectangular coil, the area is \( x \times 2x = 2x^2 \). Substitute \( x = \frac{2s}{3} \) into the rectangular area, giving \( 2\left(\frac{2s}{3}\right)^2 = \frac{8s^2}{9} \).
05

Calculate Torque Ratios

The torque experienced by a coil in a magnetic field is given by \( \tau = NIA \sin \theta \), where \( N \) is the number of turns, \( I \) is the current, \( A \) is the area, and \( \theta \) is the angle with the field direction. For maximum torque, \( \sin \theta = 1 \). The ratio of maximum torques is given by \( \frac{\tau_{\text{square}}}{\tau_{\text{rectangle}}} = \frac{IA_{\text{square}}}{IA_{\text{rectangle}}} = \frac{s^2}{\frac{8s^2}{9}} = \frac{9}{8} \).
06

Solution Conclusion

The ratio of the maximum torques experienced by the square coil to the rectangular coil in the same conditions is \( \frac{9}{8} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

square coil
A square coil is essentially a loop of wire formed into the shape of a square. It is characterized by having all four sides of equal length. This is an appealing geometry in electromagnetism due to its symmetry, which simplifies calculations and analysis.
When considering such a coil in a magnetic field, each side of the coil contributes equally to the magnetic torque, making it a model often used in educational exercises. In exercises involving square coils, the calculation of the magnetic torque typically involves knowing the area of the square. This can be given as the side length squared, \[A = s^2\]where \(s\) is the length of one side. The wire in a square coil is distributed equally across its perimeter, leading to predictable magnetic interactions when current flows through it. Remember that the formula for torque in a magnetic field is based on the coil area and orientation, expressed as \(\tau = NIAB\), where \(N\) is the number of turns, \(I\) is the current, \(A\) is the area, and \(B\) is the magnetic field's intensity.
rectangular coil
A rectangular coil is another common shape used in electromagnetism exercises and is made from a loop of wire shaped like a rectangle. In comparison to square coils, rectangular coils have varied side lengths, typically with one pair being longer than the other. For example, when one side is twice as long as its adjacent side, the analysis of its properties can be slightly more complex. The coil described in the problem has a perimeter equation of \(6x\) when the short side is \(x\) and the long side is \(2x\). The area of such a rectangular coil is calculated by:\[A = x \times 2x = 2x^2 \]Since we have relations between the lengths such as \(x = \frac{2s}{3}\), we can further refine the area description in terms of \(s\). This results in:\[A = \frac{8s^2}{9}\]Rectangular coils, due to their non-uniform sides, distribute wire and current differently across their perimeter, which alters the way they generate magnetic torque in a magnetic field.
maximum torque
Maximum torque in the context of coils in a magnetic field relates to the maximum rotational force a coil experiences under the influence of the magnetic field. A prevalent formula expressing this relationship is \(\tau = NIAB \sin \theta\). Here, \(N\) is the number of turns in the coil, \(I\) is the current, \(A\) is the area of the coil, \(B\) is the uniform magnetic field, and \(\sin \theta\) is the sine of the angle between the normal to the coil and the magnetic field direction. When \(\theta = 90^\circ\), \(\sin \theta = 1\), reaching the condition for maximum torque.The maximum torque experienced by a square coil is relatively straightforward to calculate. For instance, if both a square and a rectangular coil use the same current and magnetic field, the area primarily influences the maximum torque each can achieve. Through substitution, the ratio of the maximum torques when the coils are made from the same length of wire is:\[\frac{s^2}{\frac{8s^2}{9}} = \frac{9}{8}\]This shows that the maximum torque of the square coil is greater than that of the rectangular coil by a factor of \(\frac{9}{8}\), elucidating how different coil shapes can affect magnetic torque outcomes.

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Most popular questions from this chapter

A particle of mass \(6.0 \times 10^{-8} \mathrm{kg}\) and charge \(+7.2 \mu \mathrm{C}\) is traveling due east. It enters perpendicularly a magnetic field whose magnitude is \(3.0 \mathrm{T}\). After entering the field, the particle completes one-half of a circle and exits the field traveling due west. How much time does the particle spend traveling in the magnetic field?

Two charged particles move in the same direction with respect to the same magnetic field. Particle 1 travels three times faster than particle 2 . However, each particle experiences a magnetic force of the same magnitude. Find the ratio \(\left|q_{1}\right| /\left|q_{2}\right|\) of the magnitudes of the charges.

A positively charged particle of mass \(7.2 \times 10^{-8} \mathrm{kg}\) is traveling due east with a speed of \(85 \mathrm{m} / \mathrm{s}\) and enters a \(0.31-\mathrm{T}\) uniform magnetic field. The particle moves through one- quarter of a circle in a time of \(2.2 \times 10^{-3} \mathrm{s},\) at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge.

A piece of copper wire has a resistance per unit length of \(5.90 \times 10^{-3} \Omega / \mathrm{m} .\) The wire is wound into a thin, flat coil of many turns that has a radius of \(0.140 \mathrm{m}\). The ends of the wire are connected to a \(12.0-\mathrm{V}\) battery. Find the magnetic field strength at the center of the coil.

Electron beams are sometimes used to melt and evaporate metals in order to deposit thin metallic films on surfaces (similar to gold plating). One method is to put the material to be evaporated (called the "target") into a small tungsten cup (a crucible that has a very high melting point) and direct a beam of electrons at the target. Your team has been given the task of designing an electron-beam evaporator. The crucible is a cylinder, \(2.0 \mathrm{cm}\) in diameter and \(1.5 \mathrm{cm}\) in height, and contains a small target of pure nickel (Ni). The electrons are accelerated through a potential difference of \(V=1.20 \mathrm{kV}\), and form a beam that originates below the crucible, exactly \(3.70 \mathrm{cm}\) off its center, in the \(+x\) direction (see the drawing). (a) What is the speed of the electrons in the beam? (b) You must steer the electron beam with a magnetic field so that it curls over the lip of the cup and strikes the nickel target. Assuming that a uniform field exists above the cup (the field is zero below), what must be the radius of the beam's circular path? (c) In what direction should the field point if the beam initially approaches the cup from the \(-y\) axis? (d) What must be the magnitude of the uniform magnetic field?

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