/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 A charge of \(-8.3 \mu \mathrm{C... [FREE SOLUTION] | 91Ó°ÊÓ

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A charge of \(-8.3 \mu \mathrm{C}\) is traveling at a speed of \(7.4 \times 10^{6} \mathrm{m} / \mathrm{s}\) in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is \(52^{\circ} .\) A force of magnitude \(5.4 \times 10^{-3} \mathrm{N}\) acts on the charge. What is the magnitude of the magnetic field?

Short Answer

Expert verified
The magnetic field magnitude is approximately \(1.13 \times 10^{-4} \text{ T}\).

Step by step solution

01

Understand the Known and Unknown Values

We know the following values: the charge \( q = -8.3 \times 10^{-6} \text{ C}\), the velocity \( v = 7.4 \times 10^6 \text{ m/s} \), the force \( F = 5.4 \times 10^{-3} \text{ N} \), and the angle \( \theta = 52^{\circ} \). We are asked to find the magnitude of the magnetic field \( B \).
02

Use the Formula for Magnetic Force

The formula for the magnetic force acting on a moving charge is \( F = |q|vB\sin(\theta) \), where \( F \) is the force, \( q \) is the charge, \( v \) is the velocity, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the direction of the velocity and magnetic field.
03

Rearrange the Formula to Solve for B

To find \( B \), we rearrange the formula: \( B = \frac{F}{|q|v \sin(\theta)} \). This expresses the magnetic field in terms of force, charge, velocity, and the sine of the angle.
04

Plug in the Known Values

Substitute the known values into the equation: \( B = \frac{5.4 \times 10^{-3} \text{ N}}{8.3 \times 10^{-6} \text{ C} \times 7.4 \times 10^6 \text{ m/s} \times \sin(52^{\circ})} \).
05

Solve the Equation

Calculate \( \sin(52^{\circ}) \approx 0.7880 \). Substitute this into the equation to find \( B \): \( B = \frac{5.4 \times 10^{-3}}{8.3 \times 10^{-6} \times 7.4 \times 10^6 \times 0.7880} \approx 1.13 \times 10^{-4} \text{ T} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Force
The concept of magnetic force is pivotal in understanding how charged particles move in magnetic fields. Magnetic force is a type of force that acts on charges in motion. It is directly proportional to the strength of the magnetic field and the component of the velocity that is perpendicular to the magnetic field. When a charge, such as an electron or proton, moves within a magnetic field, it experiences a force that is perpendicular to both its velocity and the magnetic field direction. This is described by the right-hand rule, providing a tangible way to determine the force direction. In practical applications, this phenomenon allows for the operation of devices such as electric motors and generators, where magnetic forces are harnessed for mechanical work.
Understanding the nature of this force is crucial, as it affects particles' paths, making magnetic force a fundamental component in technologies that rely on charged particles.
Moving Charge
A moving charge in a magnetic field is the basic context for calculating the magnetic force. When a charge moves, it creates an electric current, and when it travels through a magnetic field, it is subjected to a force. This movement and interaction are key to understanding magnetic phenomena in physical systems. The velocity of the charge affects the magnitude of the force, as does the orientation of its motion relative to the magnetic field.
For instance, if a charge moves parallel to the field, the magnetic force is zero because the sine of 0 degrees is zero, indicating that only the perpendicular component of the velocity to the field contributes to the magnetic force. This principle is what leads to the earth’s magnetic field impacting charged particles from space, affecting their trajectories.
Physics Problem Solving
In physics, problem solving often involves breaking down a complex situation into known quantities and applying relevant formulas. This systematic approach is crucial for calculating values like the magnetic field strength when given a moving charge. Initially, one must identify the known and unknown variables, a pivotal part of any solution strategy. Here, the charge, force, and velocity were provided, while the magnetic field was the unknown parameter.
Leveraging specific formulas, like the magnetic force equation, helps translate these knowns into solutions. Rearranging the formula to isolate the unknown (in this case, the magnetic field) is a common technique. Employing a sequence of logical steps and calculations ensures that solutions are both accurate and replicable.
Magnetic Force Formula
The magnetic force formula, given as \( F = |q|vB\sin(\theta) \), is integral in determining the force on a moving charge within a magnetic field. Each variable in this formula provides essential information about the relationship between the dynamics of a moving charge and the magnetic field.
  • \( F \) represents the magnetic force acting on the charge, which varies based on velocity and field strength.
  • \( |q| \) is the magnitude of the charge, demonstrating that the force is proportional to the charge's size.
  • \( v \) signifies the velocity of the charge, showcasing that faster moving charges experience greater force.
  • \( B \) indicates the magnetic field's strength, and \( \theta \) denotes the angle between the field and the velocity.

To find and manipulate these contributing factors, once the equation is rearranged to \( B = \frac{F}{|q|v \sin(\theta)} \), students can derive the magnetic field strength from the other quantities. This formula underscores the concept that magnetic fields exert a calculated force, helping us harness and predict the interaction between charged particles and magnetic environments in real-world applications.

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Most popular questions from this chapter

In a certain region, the earth's magnetic field has a magnitude of \(5.4 \times 10^{-5} \mathrm{T}\) and is directed north at an angle of \(58^{\circ}\) below the horizontal. An electrically charged bullet is fired north and \(11^{\circ}\) above the horizontal, with a speed of \(670 \mathrm{m} / \mathrm{s} .\) The magnetic force on the bullet is \(2.8 \times 10^{-10} \mathrm{N},\) directed due east. Determine the bullet's electric charge, including its algebraic sign \((+\operatorname{or}-)\).

A very long, straight wire carries a current of 0.12 A. This wire is tangent to a single-turn, circular wire loop that also carries a current. The directions of the currents are such that the net magnetic field at the center of the loop is zero. Both wires are insulated and have diameters that can be neglected. How much current is there in the loop?

In a lightning bolt, a large amount of charge flows during a time of \(1.8 \times 10^{-3} \mathrm{s} .\) Assume that the bolt can be treated as a long, straight line of current. At a perpendicular distance of \(27 \mathrm{m}\) from the bolt, a magnetic field of \(8.0 \times 10^{-5} \mathrm{T}\) is measured. How much charge has flowed during the lightning bolt? Ignore the earth's magnetic field.

A magnetic field has a magnitude of \(1.2 \times 10^{-3} \mathrm{T}\), and an electric field has a magnitude of \(4.6 \times 10^{3} \mathrm{N} / \mathrm{C} .\) Both fields point in the same direction. A positive \(1.8 \mu \mathrm{C}\) charge moves at a speed of \(3.1 \times 10^{6} \mathrm{m} / \mathrm{s}\) in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.

The ion source in a mass spectrometer produces both singly and doubly ionized species, \(X^{+}\) and \(X^{2+} .\) The difference in mass between these species is too small to be detected. Both species are accelerated through the same electric potential difference, and both experience the same magnetic field, which causes them to move on circular paths. The radius of the path for the species \(\mathrm{X}^{+}\) is \(r_{1},\) while the radius for species \(\mathrm{X}^{2+}\) is \(r_{2} .\) Find the ratio \(r_{1} / r_{2}\) of the radii.

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