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A wire carries a current of 0.66 A. This wire makes an angle of \(58^{\circ}\) with respect to a magnetic field of magnitude \(4.7 \times 10^{-5}\) T. The wire experiences a magnetic force of magnitude \(7.1 \times 10^{-5} \mathrm{N} .\) What is the length of the wire?

Short Answer

Expert verified
The wire is approximately 2.704 meters long.

Step by step solution

01

Understanding the Problem

We need to determine the length of a wire that experiences a magnetic force while carrying a certain current at an angle to a magnetic field. We have the current (\(I = 0.66\) A), the angle (\(\theta = 58^\circ\)), the magnetic field (\(B = 4.7 \times 10^{-5}\) T), and the force experienced by the wire (\(F = 7.1 \times 10^{-5}\) N).
02

Applying the Magnetic Force Formula

We use the formula for the magnetic force on a current-carrying wire: \[ F = I \cdot L \cdot B \cdot \sin(\theta) \]where \(F\) is the magnetic force, \(I\) is the current, \(L\) is the length of the wire, \(B\) is the magnetic field, and \(\theta\) is the angle between the wire and the magnetic field.
03

Rearranging the Formula for Length

To find the length \(L\), rearrange the equation:\[ L = \frac{F}{I \cdot B \cdot \sin(\theta)} \]
04

Calculating \( \sin(\theta) \)

First, find \( \sin(58^\circ) \). Using a calculator, \[ \sin(58^\circ) \approx 0.848 \]
05

Substitute Known Values

Substitute the values into the rearranged equation:\[ L = \frac{7.1 \times 10^{-5}}{0.66 \times 4.7 \times 10^{-5} \times 0.848} \]
06

Performing the Calculation

Compute the denominator:\[ 0.66 \times 4.7 \times 10^{-5} \times 0.848 = 2.625192 \times 10^{-5} \]Then, compute the length:\[ L = \frac{7.1 \times 10^{-5}}{2.625192 \times 10^{-5}} \approx 2.704 \text{ meters} \]
07

Final Answer

The length of the wire is approximately \(2.704\) meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current-Carrying Wire
When discussing physics, a current-carrying wire is a fundamental concept involving the flow of electric charge through a conductor. This flow of charge is measured in amperes (A), and it plays a critical role in many applications including electromagnetism.
Ever wondered why wires heat up? It's because moving charges, or current, encounter resistance in the wire, causing energy dissipation as heat.
In this context, the electric current is defined as the rate at which charge flows, expressed as:
  • Current, denoted by \(I\), can be mathematically expressed as \(I = \frac{Q}{t}\)
  • where \(Q\) is the charge in coulombs, and \(t\) is the time in seconds.
Understanding how current interacts with magnetic fields helps us predict and harness the power of electromagnetism. The more you know about current flow in wires, the better you understand essential technologies like motors and generators.
Magnetic Field
A magnetic field is an invisible force field that exerts a force on moving electric charges and magnetic materials. It is represented by the letter \(B\) and measured in teslas (T). Magnetic fields are a cornerstone of electromagnetism, influencing phenomena from the Earth's magnetosphere to everyday electronics.
A key aspect of magnetic fields is their ability to influence current-carrying wires. According to the
  • Lorentz force law, a magnetic field applies a force on a wire carrying current perpendicular to the direction of the field and flow of current. This magnetic force \(F\) is given by:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \] where \(I\) represents the current, \(L\) is the length of the wire, \(B\) is the magnetic field strength, and \(\theta\) is the angle between the wire and the field.
Through this interaction, magnetic fields enable the functioning of many devices, from magnetic resonance imaging (MRI) to electron beams in particle accelerators.
Trigonometry in Physics
Trigonometry is a mathematical discipline that deals with the relationships between the sides and angles of triangles. In physics, it is frequently used to resolve components of vectors, including forces and velocities. Understanding how to apply trigonometry helps simplify complex problems into more manageable calculations.
When a wire makes an angle \(\theta\) with a magnetic field, trigonometry helps us calculate how much of the magnetic force acts on the wire. Here, the magnetic force is defined by the sine function, \(\sin(\theta)\), which determines the perpendicular component of the force relative to the field.
Let's break it down:
  • The sine function, \(\sin(\theta)\), is calculated using a calculator or trigonometric tables. It provides the ratio of the length of the opposite side to the hypotenuse in a right triangle.
  • For instance, \(\sin(58^\circ)\) is approximately 0.848.
Being comfortable with trigonometric tools not only applies to physics but also develops problem-solving skills useful in engineering, architecture, and various technological fields.

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Most popular questions from this chapter

(a) A proton, traveling with a velocity of \(4.5 \times 10^{6} \mathrm{m} / \mathrm{s}\) due east, experiences a magnetic force that has a maximum magnitude of \(8.0 \times 10^{-14} \mathrm{N}\) and a direction of due south. What are the magnitude and direction of the magnetic field causing the force? (b) Repeat part (a) assuming the proton is replaced by an electron.

When beryllium- 7 ions \(\left(m=11.65 \times 10^{-27} \mathrm{kg}\right)\) pass through a mass spectrometer, a uniform magnetic field of \(0.283 \mathrm{T}\) curves their path directly to the center of the detector (see Figure 21.14 ). For the same accelerating potential difference, what magnetic field should be used to send beryllium-10 ions \(\left(m=16.63 \times 10^{-27} \mathrm{kg}\right)\) to the same location in the detector? Both types of ions are singly ionized \((q=+e)\).

A \(45-\mathrm{m}\) length of wire is stretched horizontally between two vertical posts. The wire carries a current of \(75 \mathrm{A}\) and experiences a magnetic force of 0.15 N. Find the magnitude of the earth's magnetic field at the location of the wire, assuming the field makes an angle of \(60.0^{\circ}\) with respect to the wire.

A wire has a length of \(7.00 \times 10^{-2} \mathrm{m}\) and is used to make a circular coil of one turn. There is a current of \(4.30 \mathrm{A}\) in the wire. In the presence of a \(2.50-\mathrm{T}\) magnetic field, what is the maximum torque that this coil can experience?

A charged particle enters a uniform magnetic field and follows the circular path shown in the drawing. (a) Is the particle positively or negatively charged? Why? (b) The particle's speed is \(140 \mathrm{m} / \mathrm{s},\) the magnitude of the magnetic field is \(0.48 \mathrm{T}\), and the radius of the path is \(960 \mathrm{m}\). Determine the mass of the particle, given that its charge has a magnitude of \(8.2 \times 10^{-4} \mathrm{C}\).

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