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At New York City, the earth's magnetic field has a vertical component of \(5.2 \times 10^{-5} \mathrm{T}\) that points downward (perpendicular to the ground) and a horizontal component of \(1.8 \times 10^{-5} \mathrm{T}\) that points toward geographic north (parallel to the ground). What are the magnitude and direction of the magnetic force on a \(6.0-\mathrm{m}\) long, straight wire that carries a current of \(28 \mathrm{A}\) perpendicularly into the ground?

Short Answer

Expert verified
The magnetic force is \(3.024 \times 10^{-3} \, \text{N}\) directed east.

Step by step solution

01

Understanding the Problem

We are asked to find the magnetic force on a wire due to Earth's magnetic field. The wire carries a current of 28 A perpendicularly into the ground, meaning only the horizontal component of the magnetic field affects it. The given horizontal component is towards north, and the wire's direction is downward.
02

Identify the Relevant Formula

The formula to calculate the magnetic force on a straight conductor is: \[ F = I \times L \times B \times \sin(\theta) \] where \( F \) is the magnetic force, \( I \) is the current, \( L \) is the length of the wire, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the current direction and the magnetic field.
03

Determine the Effective Magnetic Field Component

Since the current flows vertically, only the horizontal component of Earth's magnetic field affects it. Here, \( B = 1.8 \times 10^{-5} \, \text{T} \).
04

Find the Angle θ

The angle \( \theta \) between the wire and the magnetic field is 90 degrees because the wire points downward and the magnetic field points northward (horizontally). Therefore, \( \sin(90^\circ) = 1 \).
05

Calculate the Magnetic Force

Substitute the values into the formula: \[ F = 28 \, \text{A} \times 6.0 \, \text{m} \times 1.8 \times 10^{-5} \, \text{T} \times 1 = 3.024 \times 10^{-3} \, \text{N} \]
06

Determine the Direction of the Force

Use the right-hand rule: point your thumb in the direction of the current (downward), fingers in the direction of the magnetic field (northward); your palm points towards the force direction, which is east.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's Magnetic Field Components
The Earth's magnetic field is an invisible force that surrounds our planet, affecting compasses and electrical currents alike. In many situations, it provides a vital influence on current-carrying wires and other magnetic objects. When discussing Earth's magnetic field, it's important to consider its two main components: the horizontal and vertical components of the field.

In New York City, for example, the vertical component of the Earth's magnetic field is given as \(5.2 \times 10^{-5} \text{ T}\) and it points downward, perpendicular to the ground. This means that if you were to measure the field with a device sticking out of the soil upward, it would record this vertical measurement.

The horizontal component, on the other hand, measures \(1.8 \times 10^{-5} \text{ T}\) and points towards geographic north. This is parallel to the ground and significantly affects objects that lie flat or move along the surface.

Understanding these components becomes essential when solving physics problems, such as calculating the force acting on a wire due to Earth's magnetic field.
Right-Hand Rule in Magnetism
The right-hand rule in magnetism is a simple and effective way for you to determine the direction of the magnetic force relating to current-carrying wires and magnetic fields. It acts as your guide to solving questions around the direction of forces in magnetic fields.

To apply the right-hand rule, follow these steps:
  • Extend your right hand so that your thumb points in the direction of the current flow. For example, in some problems, the current might flow downward. Extend your thumb downwards to match this direction.
  • Next, orient your fingers so they point in the direction of the magnetic field. If the magnetic field is horizontal towards the north, then let your fingers follow this northward direction.
  • Finally, your palm will face the direction in which the magnetic force acts, which can be on the side of the wire. In some scenarios, like typical physics problems, this direction might be eastward.
Practice with the right-hand rule can make it an automatic tool in understanding the physics of electricity and magnetism.
Magnetic Force Direction Determination
Determining the direction of magnetic force on a current-carrying wire is a crucial skill in physics, particularly in electromagnetics. When an electrical current moves through a wire, it interacts with surrounding magnetic fields, producing a force.

The formula used to compute this force is \( F = I \times L \times B \times \sin(\theta) \), where \( F \) is the magnetic force, \( I \) is the current in amperes, \( L \) is the length of the wire, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the current and the magnetic field.

For instance, imagine a wire running vertically downward and a horizontal magnetic field. Here, \( \theta \) equals 90 degrees because the angles between vertical and horizontal directions form a perpendicular angle. Accordingly, \( \sin(90^\circ) = 1 \), which simplifies the calculation.

Using the right-hand rule, you can determine the force's direction. For instance, placing your thumb down for the current and your fingers towards the magnetic field, your palm will face eastward, indicating the force's direction. This visualization is not only satisfying but also essential for solving related physics problems.

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Most popular questions from this chapter

You have a wire of length \(L=1.00 \mathrm{m}\) from which to make the square coil of a dc motor. The current in the coil is \(I=1.7 \mathrm{A},\) and the magnetic field of the motor has a magnitude of \(B=0.34\) T. Find the maximum torque exerted on the coil when the wire is used to make a single-turn square coil and a two-turn square coil.

Hydrogen has three isotopes \({ }^{1} \mathrm{H}\left(m_{1}=m_{\mathrm{p}}\right)\) \({ }^{2} \mathrm{H}\left(m_{2} \cong 2 m_{\mathrm{p}}\right),\) and \({ }^{3} \mathrm{H}\left(m_{\mathrm{s}} \cong 3 m_{\mathrm{p}}\right),\) where \(m_{\mathrm{p}}\) is the mass of a proton \((1.67 \times\) \(10^{-27} \mathrm{kg}\) ). You and your team are tasked with constructing an isotope separator that will separate a gas of mixed hydrogen isotopes. The gas first passes through a device that atomizes it (i.e., makes sure the atoms are separate, and do not form \(\mathrm{H}_{2}\) molecules), and then ionizes the atoms (strips off their only electron) so that they have a net charge of \(+e .\) Next, the atoms (now positive ions) are accelerated between the plates of a parallel-plate capacitor with a voltage of \(2.5 \mathrm{kV}\) across it, and emerge through a hole in one of the plates as a beam. (a) What are the speeds of the three isotopes when they emerge from the capacitor plates? (b) The accelerated ions enter a region of uniform magnetic field oriented perpendicular to the velocity vector of the ion beam. What should be the magnitude of the magnetic field if you want the largest diameter of the three ion paths to be \(20.0 \mathrm{cm} ?\) (c) If you are collecting the atoms after completing a half-circle, one collector should be located \(20.0 \mathrm{cm}\) from the point where the beam enters the magnetic field. Where should the other two be located?

When beryllium- 7 ions \(\left(m=11.65 \times 10^{-27} \mathrm{kg}\right)\) pass through a mass spectrometer, a uniform magnetic field of \(0.283 \mathrm{T}\) curves their path directly to the center of the detector (see Figure 21.14 ). For the same accelerating potential difference, what magnetic field should be used to send beryllium-10 ions \(\left(m=16.63 \times 10^{-27} \mathrm{kg}\right)\) to the same location in the detector? Both types of ions are singly ionized \((q=+e)\).

A charged particle with a charge-to-mass ratio of \(|q| / m=5.7 \times\). \(10^{8} \mathrm{C} / \mathrm{kg}\) travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.72 T. How much time does it take for the particle to complete one revolution?

In the operating room, anesthesiologists use mass spectrometers to monitor the respiratory gases of patients undergoing surgery. One gas that is often monitored is the anesthetic isoflurane (molecular mass \(=\) \(3.06 \times 10^{-25} \mathrm{kg}\) ). In a spectrometer, a singly ionized molecule of isoflurane (charge \(=+e\) ) moves at a speed of \(7.2 \times 10^{3} \mathrm{m} / \mathrm{s}\) on a circular path that has a radius of \(0.10 \mathrm{m} .\) What is the magnitude of the magnetic field that the spectrometer uses?

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