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Two identical resistors are connected in parallel across a \(25-\mathrm{V}\) battery, which supplies them with a total power of \(9.6 \mathrm{W}\). While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains unchanged. Find (a) the initial resistance of each resistor and (b) the total power delivered to the resistors after one resistor has been heated.

Short Answer

Expert verified
(a) Each initial resistor is approximately 130.21 Ω. (b) Power after heating is approximately 7.2 W.

Step by step solution

01

Understand the Formula for Power

The power supplied to the resistors is given by the formula \(P = \frac{V^2}{R_{eq}}\), where \(P\) is the power supplied by the battery, \(V\) is the voltage across the resistors, and \(R_{eq}\) is the equivalent resistance of the resistors in parallel.
02

Calculate Equivalent Resistance in Initial State

Initially, for two identical resistors \(R\) in parallel, the equivalent resistance is given by \(R_{eq} = \frac{R}{2}\). Use the power formula and solve \(9.6 = \frac{(25)^2}{\frac{R}{2}}\) to find \(R\).
03

Solve for Initial Resistance of Each Resistor

Re-arrange the equation to solve for \(R\): \(\frac{R}{2} = \frac{625}{9.6}\). Therefore, \(R = 2 \times \frac{625}{9.6} = \frac{6250}{48}\), which simplifies to \(R \approx 130.21 \text{ \(\Omega\)}\).
04

Describe the Scenario After Heating One Resistor

After one resistor heats up, its resistance doubles from \(R\) to \(2R\), while the other resistor remains \(R\). The new equivalent resistance for the two resistors is given by \(R'_{eq} = \frac{R \times 2R}{R + 2R} = \frac{2R^2}{3R} = \frac{2}{3}R\).
05

Calculate New Total Power

The new power consumed by the resistors can be calculated using \(P' = \frac{(25)^2}{R'_{eq}}\). Substitute the values into the formula: \(P' = \frac{625}{\frac{2}{3}R} = \frac{3 \times 625}{2R}\). Substitute \(R \approx 130.21\) to get \(P'\approx 7.2\, \text{W}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Introduction to Resistors
Resistors are crucial components in electric circuits. They control the flow of electric current by providing resistance, which is measured in ohms (\( \Omega \)). By inserting resistors into a circuit, we are able to regulate the current and, consequently, the power distribution across the circuit.
  • Resistors are often represented by the symbol \( R \) in equations and diagrams.
  • A resistor's resistance determines how much it will oppose the electric current, causing the current to 'slow down'.
When resistors are connected in parallel, they share the voltage equally across them. The key point in a parallel configuration is that each resistor is like a separate path for the current to flow through. This means the total or equivalent resistance is less than the smallest resistor in the network. For identical resistors connected in parallel, the equivalent resistance \( R_{eq} \) is computed as \( \frac{R}{n} \), where \( n \) is the number of resistors.
Understanding Power Calculation in Circuits
In electrical circuits, power indicates how much energy is converted per unit of time. It is measured in watts (\( W \)), and its calculation is often pivotal in understanding circuit dynamics. The fundamental formula for power in a circuit is \( P = \frac{V^2}{R} \), where:
  • \( P \) is the power in watts.
  • \( V \) stands for voltage across the circuit in volts.
  • \( R \) represents the resistance in ohms.
Using these parameters, we can analyze a circuit to determine how much power is consumed or supplied. Initially, when two identical resistors are in a circuit with a given voltage, the power can be determined using their equivalent resistance. The formula demonstrates that as the equivalent resistance changes (such as when a resistor's resistance doubles due to heating), the total power delivered by the battery will also change. Calculating this power involves finding the new equivalent resistance, using it in the power formula, and then applying the voltage to solve for power.
Calculating Equivalent Resistance
In an electric circuit, equivalent resistance simplifies complex networks into a single resistor model with the same effect on the circuit as the original network of resistors. Understanding how to calculate this is essential when dealing with circuits that have multiple resistors arranged in series or parallel. When resistors are connected in parallel, the equivalent resistance \( R_{eq} \) is calculated using the formula:\[R_{eq} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}}\]For identical resistors, say two resistors of resistance \( R \), connected in parallel, the equivalent resistance is simply \( \frac{R}{2} \). However, if a resistor's value changes, as in the heating scenario, the new equivalent resistance must be recalculated. For example, when one resistor doubles in resistance from \( R \) to \( 2R \), while the other stays constant, the equation becomes:\[R'_{eq} = \frac{1}{\frac{1}{R} + \frac{1}{2R}} = \frac{2R^2}{3R} = \frac{2}{3}R\] This recalculation is vital for making accurate power and current assessments in dynamically changing circuits.

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Most popular questions from this chapter

You and your team are designing a small tube heater that consists of a small ceramic tube wrapped with a special heater wire composed of Nichrome. When you run an electrical current through the wire, the wire (and therefore the tube) heats up through resistive heating. Nichrome is an alloy composed of \(80 \%\) nickel and \(20 \%\) chromium, and has a resistivity of \(\rho=1.25 \times 10^{-6} \Omega \cdot \mathrm{m} .\) (a) What is the resistance per centimeter of 28-gauge Nichrome wire? ("28 gauge" means the wire has a diameter \(D=0.320 \mathrm{mm}\) (b) You wrap the tube with \(45.0 \mathrm{cm}\) of the Nichrome wire, and you want the power output of your heater to be \(120 \mathrm{W}\). What current is needed? (c) What voltage will provide the current calculated in (b)?

A digital thermometer employs a thermistor as the temperaturesensing element. A thermistor is a kind of semiconductor and has a large negative temperature coefficient of resistivity \(\alpha .\) Suppose that \(\alpha=-0.060\left(\mathrm{C}^{\circ}\right)^{-1}\) for the thermistor in a digital thermometer used to measure the temperature of a patient. The resistance of the thermistor decreases to \(85 \%\) of its value at the normal body temperature of \(37.0^{\circ} \mathrm{C} .\) What is the patient's temperature?

Suppose that the resistance between the walls of a biological cell is \(5.0 \times 10^{9} \Omega .\) (a) What is the current when the potential difference between the walls is \(75 \mathrm{mV} ?\) (b) If the current is composed of \(\mathrm{Na}^{+}\) ions \((q=+e),\) how many such ions flow in \(0.50 \mathrm{s} ?\)

The heating element in an iron has a resistance of \(24 \Omega .\) The iron is plugged into a \(120-\mathrm{V}\) outlet. What is the power delivered to the iron?

A 550 -W space heater is designed for operation in Germany, where household electrical outlets supply \(230 \mathrm{V}\) (rms) service. What is the power output of the heater when plugged into a \(120-\mathrm{V}\) (rms) electrical outlet in a house in the United States? Ignore the effects of temperature on the heater's resistance.

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