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The total current delivered to a number of devices connected in parallel is the sum of the individual currents in each device. Circuit breakers are resettable automatic switches that protect against a dangerously large total current by "opening" to stop the current at a specified safe value. A \(1650-\mathrm{W}\) toaster, a \(1090-\mathrm{W}\) iron, and a \(1250-\mathrm{W}\) microwave oven are turned on in a kitchen. As the drawing shows, they are all connected through a \(20-\mathrm{A}\) circuit breaker (which has negligible resistance) to an ac voltage of \(120 \mathrm{V}\) (a) Find the equivalent resistance of the three devices. (b) Obtain the total current delivered by the source and determine whether the breaker will "open" to prevent an accident.

Short Answer

Expert verified
The equivalent resistance is \(5.23\, \Omega\), and the breaker will open.

Step by step solution

01

Calculate the Individual Currents

First, we will find the current flowing through each device. The power equation is given by \( P = IV \), where \( P \) is the power, \( I \) is the current, and \( V \) is the voltage. Rearrange for \( I \): \( I = \frac{P}{V} \). Use the voltage \( V = 120 \text{ V} \) for each device.- For the toaster (\( P = 1650 \text{ W} \)), \( I = \frac{1650}{120} = 13.75 \text{ A} \).- For the iron (\( P = 1090 \text{ W} \)), \( I = \frac{1090}{120} \approx 9.08 \text{ A} \).- For the microwave oven (\( P = 1250 \text{ W} \)), \( I = \frac{1250}{120} \approx 10.42 \text{ A} \).
02

Calculate the Total Current

Since the devices are connected in parallel, the total current \( I_{\text{total}} \) is the sum of the individual currents:\[ I_{\text{total}} = I_1 + I_2 + I_3 = 13.75 + 9.08 + 10.42 \approx 33.25 \text{ A} \].
03

Examine Circuit Breaker Condition

The circuit breaker will "open" if the total current exceeds its rating of \( 20 \text{ A} \). We found that \( I_{\text{total}} \approx 33.25 \text{ A} \), which is greater than \( 20 \text{ A} \). Therefore, the breaker will open.
04

Calculate Equivalent Resistance

For devices in parallel, the equivalent resistance \( R_{\text{eq}} \) is given by the formula:\[ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \].Find each device's resistance using \( R = \frac{V}{I} \):- Toaster: \( R_1 = \frac{120}{13.75} \approx 8.73 \Omega \).- Iron: \( R_2 = \frac{120}{9.08} \approx 13.22 \Omega \).- Microwave: \( R_3 = \frac{120}{10.42} \approx 11.52 \Omega \).Calculate \( R_{\text{eq}} \):\[ \frac{1}{R_{\text{eq}}} = \frac{1}{8.73} + \frac{1}{13.22} + \frac{1}{11.52} \approx 0.1911 \].Therefore, \( R_{\text{eq}} \approx 5.23 \Omega \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current Calculation
In a parallel circuit, each device operates independently. This means the current flowing through each device can be calculated separately. Using the formula for electrical power, \( P = IV \), where \( P \) is the power in watts, \( I \) is the current in amperes, and \( V \) is the voltage in volts. You can solve for current with the equation \( I = \frac{P}{V} \). For example, in the given problem:
- The toaster, with a power rating of \( 1650 \text{ W} \), draws a current of \( 13.75 \text{ A} \) using \( I = \frac{1650}{120} \).
- The iron, rated at \( 1090 \text{ W} \), draws about \( 9.08 \text{ A} \).
- The microwave oven, rated at \( 1250 \text{ W} \), draws approximately \( 10.42 \text{ A} \).
Each device in parallel adds its current to the total current drawn from the source. Thus, the total current is simply the sum of all these individual currents.
Circuit Breaker
A circuit breaker is an essential safety device in electrical circuits. It protects an electrical circuit from damage caused by an overload or short circuit. It works by interrupting the flow of electrical current when it exceeds a designated safe level. The breaker "opens" or "trips" to stop the current. This prevents the wiring from overheating and possibly causing fires. In our example, the circuit breaker is rated at \( 20 \text{ A} \). If the total current surpasses this value, the breaker will open.
From our calculations, the total current drawn by the toaster, iron, and microwave is about \( 33.25 \text{ A} \). Since this total is well above the breaker's safe limit, the breaker will indeed "open" to protect the circuit. The circuit breaker effectively safeguards against scenarios where too much power is drawn from the circuit.
Equivalent Resistance
In a parallel circuit, determining equivalent resistance is slightly more complex than in series circuits. The total or "equivalent" resistance \( R_{\text{eq}} \) in a parallel configuration is derived from the formula \[\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots\]Each device’s resistance is found via \( R = \frac{V}{I} \). In the case of the toaster, iron, and microwave:
- Toaster resistance \( R_1 \approx 8.73 \Omega \)
- Iron resistance \( R_2 \approx 13.22 \Omega \)
- Microwave resistance \( R_3 \approx 11.52 \Omega \)
Substitute these resistances into the equation to find \( R_{\text{eq}} \).
When you do the math, you find \( R_{\text{eq}} \approx 5.23 \Omega \). The lower equivalent resistance in parallel circuits means they allow more current to flow than a single device would under the same conditions.

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Most popular questions from this chapter

A \(1.40-\Omega\) resistor is connected across a \(9.00-\mathrm{V}\) battery. The voltage between the terminals of the battery is observed to be only 8.30 V. Find the internal resistance of the battery.

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